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  <name xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Kirchoff's Laws</name>

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  <md:version xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">2.6</md:version>
  <md:created xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">2000/07/11</md:created>
  <md:revised xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">2004/08/10 08:16:07.991 GMT-5</md:revised>
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      <md:author xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="dhj">
      <md:firstname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Don</md:firstname>
      
      <md:surname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Johnson</md:surname>
      <md:email xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">dhj@rice.edu</md:email>
    </md:author>
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      <md:firstname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Don</md:firstname>
      
      <md:surname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Johnson</md:surname>
      <md:email xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">dhj@rice.edu</md:email>
    </md:maintainer>
    <md:maintainer xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="rha">
      <md:firstname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Roy</md:firstname>
      
      <md:surname xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Ha</md:surname>
      <md:email xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">rha@rice.edu</md:email>
    </md:maintainer>
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  <md:keywordlist xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">
    <md:keyword xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">circuit</md:keyword>
    <md:keyword xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Kirchoff</md:keyword>
    <md:keyword xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">KVL</md:keyword>
    <md:keyword xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">KCL</md:keyword>
  </md:keywordlist>

  <md:abstract xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">A brief description of Kirchoff's Laws (current and voltage)
</md:abstract>
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  <section xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="current">
    <name xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Kirchoff's Current Law</name>

    <para xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="para1"> 
      At every node, the sum of all currents entering a node must equal zero. What 
      this law means physically is that charge cannot accumulate in a node; what 
      goes in must come out. In the example, <cnxn xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" target="simplecircuit" strength="6"/>, 
      below we have a three-node circuit and thus have three KCL equations.
      <equation xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="eq1">
        <m:math>
          <m:apply>
            <m:eq/>
              <m:apply>
                <m:minus/>
                  <m:apply>
                    <m:minus/>
                      <m:ci>i</m:ci>
                  </m:apply>
                  <m:ci>
                    <m:msub>
                      <m:mi>i</m:mi>
                      <m:mi>1</m:mi>
                    </m:msub>
                  </m:ci>
              </m:apply>
              <m:cn>0</m:cn>
          </m:apply>
        </m:math>
      </equation>
      
      <equation xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="eq2">
        <m:math>
          <m:apply>
            <m:eq/>
              <m:apply>
                <m:minus/>
                  <m:ci>
                    <m:msub>
                      <m:mi>i</m:mi>
                      <m:mi>1</m:mi>
                    </m:msub>
                  </m:ci>
                  <m:ci>
                    <m:msub>
                      <m:mi>i</m:mi>
                      <m:mi>2</m:mi>
                    </m:msub>
                  </m:ci>
              </m:apply>
              <m:cn>0</m:cn>
          </m:apply>
        </m:math>
      </equation>
      
      <equation xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="eq3">
        <m:math>
          <m:apply>
            <m:eq/>
              <m:apply>
                <m:plus/>
                  <m:ci>i</m:ci>
                  <m:ci>
                    <m:msub>
                      <m:mi>i</m:mi>
                      <m:mi>2</m:mi>
                    </m:msub>
                  </m:ci>
              </m:apply>
              <m:cn>0</m:cn>
          </m:apply>
        </m:math>
      </equation>
      Note that the current entering a node is the negative of the current leaving
      the node.
    </para>
    
    <para xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="para2">
      Given any two of these KCL equations, we can find the other by adding or subtracting
      them. Thus, one of them is redundant and, in mathematical terms, we can discard any one
      of them. The convention is to discard the equation for the (unlabeled) node at the bottom of the
      circuit.
    </para>

    <figure xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="simplecircuit" orient="horizontal">
      <name xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Figure 1</name>
      <subfigure xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/"><media xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" type="image/png" src="circuit4.png"/></subfigure>
      <subfigure xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/"><media xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" type="image/png" src="circuit4a.png"/></subfigure> 
      <caption xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">
        The circuit shown is perhaps the simplest circuit that performs a signal processing 
        function. The input is provided by the voltage source 
	<m:math>
	  <m:ci>
	    <m:msub>
	      <m:mi>v</m:mi>
	      <m:mi>in</m:mi>
	    </m:msub>
	  </m:ci>
	</m:math>
	
        and the output is the voltage 
	<m:math>
	  <m:ci>
	    <m:msub>
	      <m:mi>v</m:mi>
	      <m:mi>out</m:mi>
	    </m:msub>
	  </m:ci>
	</m:math> 
        across the resistor labelled
        <m:math>
	  <m:ci>
	    <m:msub>
	      <m:mi>R</m:mi>
	      <m:mi>2</m:mi>
	    </m:msub>
	  </m:ci>
	</m:math>.
      </caption>                                                                     
    </figure>

    <exercise xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="exer1">
      <problem xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">
        <para xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="exer1a">
          In writing KCL equations, you will find that in an 
          <m:math><m:ci>n</m:ci></m:math>-node circuit, exactly one of them is always 
          redundant. Can you sketch a proof of why this might be true? Hint: It has to 
          do with the fact that charge won't accumulate in one place on its own.
        </para>
      </problem>
      <solution xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">
        <para xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="exer1b">
          KCL says that the sum of currents entering or leaving a node must be zero. If 
          we consider two nodes together as a "supernode", KCL applies as well to currents 
          entering the combination. Since no currents enter an entire circuit, the sum of 
          currents must be zero. If we had a two-node circuit, the KCL equation of one  
          <emphasis xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">must </emphasis>be the negative of the other, We can combine all but one 
          node in a circuit into a supernode; KCL for the supernode must be the negative of 
          the remaining node's KCL equation. Consequently, specifying  
	  <m:math>
	    <m:apply>
	      <m:minus/>
		<m:ci>n</m:ci>
		<m:cn>1</m:cn>
	    </m:apply>
	  </m:math>
	  KCL equations always specifies the remaining one.
        </para>
      </solution>
    </exercise>
  </section>

  <section xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="voltage">
    <name xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/">Kirchoff's Voltage Law (KVL)</name>
    <para xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="para3">
      The voltage law says that the sum of voltages around every closed loop in the circuit 
      must equal zero. A closed loop has the obvious definition: Starting at a node, trace 
      a path through the circuit that returns you to the origin node. KVL expresses the fact 
      that electric fields are conservative: The total work performed in moving a test charge 
      around a closed path is zero. The KVL equation for our circuit is 
      <equation xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="eq4">
        <m:math>
          <m:apply>
            <m:eq/> 
              <m:apply>
                <m:minus/>
                  <m:apply>
                    <m:plus/>
                      <m:ci>
                        <m:msub>
                          <m:mi>v</m:mi>
                          <m:mi>1</m:mi>
                        </m:msub>
                      </m:ci>
                      <m:ci>
                        <m:msub>
                          <m:mi>v</m:mi>
                          <m:mi>2</m:mi>
                        </m:msub>
                      </m:ci>
                  </m:apply>
                  <m:ci>v</m:ci>
              </m:apply>
              <m:cn>0</m:cn>
          </m:apply>
        </m:math>
      </equation>
      In writing KVL equations, we follow the convention that an element's voltage enters 
      with a plus sign if traversing the closed path, we go from the positive to the 
      negative of the voltage's definition.
    </para>
  </section>

</content>
</document>
