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  <name>Wireless Channels</name>
  <metadata>
  <md:version>2.14</md:version>
  <md:created>2000/10/09</md:created>
  <md:revised>2007/06/03 16:43:36.490 GMT-5</md:revised>
  <md:authorlist>
      <md:author id="dhj">
      <md:firstname>Don</md:firstname>
      
      <md:surname>Johnson</md:surname>
      <md:email>dhj@rice.edu</md:email>
    </md:author>
  </md:authorlist>

  <md:maintainerlist>
    <md:maintainer id="dhj">
      <md:firstname>Don</md:firstname>
      
      <md:surname>Johnson</md:surname>
      <md:email>dhj@rice.edu</md:email>
    </md:maintainer>
    <md:maintainer id="montgom">
      <md:firstname>Joe</md:firstname>
      
      <md:surname>Montgomery</md:surname>
      <md:email>montgom@rice.edu</md:email>
    </md:maintainer>
  </md:maintainerlist>
  
  <md:keywordlist>
    <md:keyword>frequency</md:keyword>
    <md:keyword>wavelength</md:keyword>
    <md:keyword>wireless channel</md:keyword>
  </md:keywordlist>

  <md:abstract>A basic analysis of wireless channels and their transfer characteristics.</md:abstract>
</metadata>

  <content>
    <para id="p1">
      Wireless channels exploit the prediction made by Maxwell's
      equation that electromagnetic fields propagate in free space
      like light. When a voltage is applied to an antenna, it creates
      an electromagnetic field that propagates in all directions
      (although antenna geometry affects how much power flows in any
      given direction) that induces electric currents in the
      receiver's antenna.  Antenna geometry determines how energetic a
      field a voltage of a given frequency creates.  In general terms,
      the dominant factor is the relation of the antenna's size to the
      field's wavelength.  The fundamental equation relating frequency
      and wavelength for a propagating wave is

      <m:math display="block">
	<m:apply>
	  <m:eq/>
	  <m:apply>
	    <m:times/>
	    <m:ci>λ</m:ci>
	    <m:ci>f</m:ci>
	  </m:apply>
	  <m:ci>c</m:ci>
	</m:apply>
      </m:math>

      Thus, wavelength and frequency are inversely related: High
      frequency corresponds to small wavelengths.  For example, a
      1 MHz electromagnetic field has a wavelength of 300 m.
      Antennas having a size or distance from the ground comparable to
      the wavelength radiate fields most efficiently.  Consequently,
      the lower the frequency the bigger the antenna must be.  Because
      most information signals are baseband signals, having spectral
      energy at low frequencies, they must be modulated to higher
      frequencies to be transmitted over wireless channels.
    </para>

    <para id="p2">
      For most antenna-based wireless systems, how the signal
      diminishes as the receiver moves further from the transmitter
      derives by considering how radiated power changes with distance
      from the transmitting antenna.  An antenna radiates a given
      amount of power into free space, and ideally this power
      propagates without loss in all directions.  Considering a sphere
      centered at the transmitter, the total power, which is found by
      integrating the radiated power over the surface of the sphere,
      must be constant regardless of the sphere's radius.  This
      requirement results from the conservation of energy.  Thus, if
      <m:math>
	<m:apply>
	  <m:ci type="fn">p</m:ci>
	  <m:ci>d</m:ci>
	</m:apply>
      </m:math>
      represents the power integrated with respect to direction at a
      distance <m:math><m:ci>d</m:ci></m:math> from the antenna, the
      total power will be
      <m:math>
	<m:apply>
	  <m:times/>
	  <m:apply>
	    <m:ci type="fn">p</m:ci>
	    <m:ci>d</m:ci>
	  </m:apply>
	  <m:cn>4</m:cn>
	  <m:pi/>
	  <m:apply>
	    <m:power/>
	    <m:ci>d</m:ci>
	    <m:cn>2</m:cn>
	  </m:apply>
	</m:apply>
      </m:math>.  
      For this quantity to be a constant, we must have 

      <m:math display="block">
	<m:apply>
	  <m:ci><m:mo>∝</m:mo></m:ci>
	  <m:apply>
	    <m:ci type="fn">p</m:ci>
	    <m:ci>d</m:ci>
	  </m:apply>
	  <m:apply>
	    <m:divide/>
	    <m:cn>1</m:cn>
	    <m:apply>
	      <m:power/>
	      <m:ci>d</m:ci>
	      <m:cn>2</m:cn>
	    </m:apply>
	  </m:apply>
	</m:apply>
      </m:math>

      which means that the received signal amplitude  
      <m:math>
	<m:ci>
	  <m:msub>
	    <m:mi>A</m:mi>
	    <m:mi>R</m:mi>
	  </m:msub>
	</m:ci>
      </m:math>
      must be proportional to the transmitter's amplitude   
      <m:math>
	<m:ci>
	  <m:msub>
	    <m:mi>A</m:mi>
	    <m:mi>T</m:mi>
	  </m:msub>
	</m:ci>
      </m:math>
      and inversely related to distance from the transmitter.

      <equation id="eq1">
	<m:math>
	  <m:apply>
	    <m:eq/>
	    <m:ci>
	      <m:msub>
		<m:mi>A</m:mi>
		<m:mi>R</m:mi>
	      </m:msub>
	    </m:ci>
	    <m:apply>
	      <m:divide/>
	      <m:apply>
		<m:times/>
		<m:ci>k</m:ci>
		<m:ci>
		  <m:msub>
		    <m:mi>A</m:mi>
		    <m:mi>T</m:mi>
		  </m:msub>
		</m:ci>
	      </m:apply>
	      <m:ci>d</m:ci>
	    </m:apply>
	  </m:apply>
	</m:math>
      </equation>

      for some value of the constant <m:math><m:ci>k</m:ci></m:math>.
      Thus, the further from the transmitter the receiver is located,
      the weaker the received signal.  Whereas the attenuation found
      in wireline channels can be controlled by physical parameters
      and choice of transmission frequency, the inverse-distance
      attenuation found in wireless channels persists across all
      frequencies.
    </para>


    <exercise id="new_exercise">
      <problem>
	<para id="nea">Why don't signals attenuate according to the inverse-square
	  law in a conductor?  What is the difference between the wireline
	  and wireless cases?
	</para>
      </problem>
      <solution>
	<para id="neb">
	  As shown <cnxn document="m0100" target="eq11" strength="8">previously</cnxn>, voltages and currents in a
	  wireline channel, which is modeled as a transmission line
	  having resistance, capacitance and inductance, decay
	  exponentially with distance.  The inverse-square law governs
	  free-space propagation because such propagation is lossless,
	  with the inverse-square law a consequence of the
	  conservation of power.  The exponential decay of wireline
	  channels occurs because they have losses and some filtering.
	</para>
      </solution>
    </exercise>


    <para id="p3">
      The speed of propagation is governed by the dielectric constant  
      <m:math>
	<m:ci>
	  <m:msub>
	    <m:mi>μ</m:mi>
	    <m:mn>0</m:mn>
	  </m:msub>
	</m:ci>
      </m:math>
      and magnetic permeability   
      <m:math>
	<m:ci>
	  <m:msub>
	    <m:mi>ε</m:mi>
	    <m:mn>0</m:mn>
	  </m:msub>
	</m:ci>
      </m:math>
      of free space.

      <equation id="eq2">
	<m:math>
	  <m:apply>
	    <m:eq/>
	    <m:ci>c</m:ci>
	    <m:apply>
	      <m:divide/>
	      <m:cn>1</m:cn>
	      <m:apply>
		<m:root/>
		<m:apply>
		  <m:times/>
		  <m:ci>
		    <m:msub>
		      <m:mi>μ</m:mi>
		      <m:mn>0</m:mn>
		    </m:msub>
		  </m:ci>
		  <m:ci>
		    <m:msub>
		      <m:mi>ε</m:mi>
		      <m:mn>0</m:mn>
		    </m:msub>
		  </m:ci>
		</m:apply>
	      </m:apply>
	    </m:apply>
	    <m:apply>
	      <m:times/>
	      <m:cn type="e-notation">3<m:sep/>8</m:cn>
	      <m:apply>
		<m:divide/>
		<m:ci>m</m:ci>
		<m:ci>s</m:ci>
	      </m:apply>
	    </m:apply>
	  </m:apply>
	</m:math>
      </equation>

      Known familiarly as the speed of light, it sets an upper limit
      on how fast signals can propagate from one place to another.
      Because signals travel at a finite speed, a receiver senses a
      transmitted signal only after a time delay directly related to
      the propagation speed:

      <m:math display="block">
	<m:apply>
	  <m:eq/>
	  <m:apply>
	    <m:ci><m:mo>Δ</m:mo></m:ci>
	    <m:ci>t</m:ci>
	  </m:apply>
	  <m:apply>
	    <m:divide/>
	    <m:ci>d</m:ci>
	    <m:ci>c</m:ci>
	  </m:apply>
	</m:apply>
      </m:math>

      At the speed of light, a signal travels across the United States
      in 16 ms, a reasonably small time delay.  If a lossless
      (zero space constant) coaxial cable connected the East and West
      coasts, this delay would be two to three times longer because of
      the slower propagation speed.
    </para>
  </content>
</document>
