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Time-Domain System Example One

Module by: Don Johnson

Summary: Explains the parameters and response of the difference equation.

Example 1

Let's consider the simple system having p=1 p 1 and q=0 q 0 .

yn=ayn-1+bxn yn a y n1 b xn (1)
To compute the output at some index, this difference equation says we need to know what the previous output yn-1 y n 1 and what the input signal is at that moment of time. In more detail, let's compute this system's output to a unit-sample input: xn=δn x n δ n . Because the input is zero for negative indices, we start by trying to compute the output at n=0 n 0 .
y0=ay-1+b y0 a y -1 b (2)
What is the value of y-1 y -1 ? Because we have used an input that is zero for all negative indices, it is reasonable to assume that the output is also zero. Certainly, the difference equation would not describe a linear system if the input that is zero for all time did not produce a zero output. With this assumption, y-1=0 y -1 0 , leaving y0=b y 0 b . For n>0 n 0 , the input unit-sample is zero, which leaves us with the difference equation n,n>0:yn=ayn-1 n n 0 yn a y n1 . We can envision how the filter responds to this input by making a table.
yn=ayn-1+bδn yn a y n1 b δn (3)

Figure 1
nn xn x n yn y n
-1-1 00 00
00 bb bb
11 00 ba b a
22 00 ba2 b a 2
00
nn 00 ban b a n

Coefficient values determine how the output behaves. The parameter bb can be any value, and serves as a gain. The effect of the parameter aa is more complicated (Figure 1). If it equals zero, the output simply equals the input times the gain b b. For all non-zero values of aa, the output lasts forever; such systems are said to be IIR ( Infinite Impulse Response). The reason for this terminology is that the unit sample also known as the impulse (especially in analog situations), and the system's response to the "impulse" lasts forever. If aa is positive and less than one, the output is a decaying exponential. When a=1 a1, the output is a unit step. If aa is negative and greater than -11, the outputoscillates while decaying exponentially. When a=1 a1, the output changes sign forever, alternating between bb and -bb. More dramatic effects when |a|>1 a 1 ; whether positive or negative, the output signal becomes larger and larger, growing exponentially.

Figure 2: The input to the simple example system, a unit sample, is shown at the top, with the outputs for several system parameter values shown below.
Figure 2 (sig21.png)

Positive values of aa are used in population models to describe how population size increases over time. Here, nn might correspond to generation. The difference equation says that the number in the next generation is some multiple of the previous one. If this multiple is less than one, the population becomes extinct; if greater than one, the population flourishes. The same difference equation also describes the effect of compound interest on deposits. Here, nn indexes the times at which compounding occurs (daily, monthly, etc.), aa equals the compound interest rate plus one, and b=1 b1 (the bank provides no gain). In signal processing applications, we typically require that the output remain bounded for any input. For our example, that means that we restrict |a|=1 a 1 and chose values for it and the gain according to the application.

Exercise 1

Note that the difference equation,

yn= a 1 yn-1+...+ a p yn-p+ b 0 xn+ b 1 xn-1+...+ b q xn-q y n a 1 y n 1 ... a p y n p b 0 x n b 1 x n 1 ... b q x n q (4)
does not involve terms like yn+1 y n 1 or xn+1 x n 1 on the equation's right side. Can such terms also be included? Why or why not?

Solution 1

Such terms would require the system to know what future input or output values would be before the current value was computed. Thus, such terms can cause difficulties.

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