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Frequency Shift Keying

Module by: Don Johnson

Summary: Frequency Shift Keying uses the bit to affect the frequency of a carrier sinusoid.

Note: Your browser may not currently support MathML. See our browser support page for additional details. You can always view the correct math in the PDF version.

In frequency-shift keying (FSK), the bit affects the frequency of a carrier sinusoid.

s 0 t=A p T tsin2π f 0 t s 0 t A p T t 2 f 0 t (1)
s 1 t=A p T tsin2π f 1 t s 1 t A p T t 2 f 1 t

Figure 1
Figure 1 (sig31.png)

The frequencies f 0 f 0 , f 1 f 1 are usually harmonically related to the bit interval. In the depicted example, f 0 =3T f 0 3 T and f 1 =4T f 1 4 T . As can be seen from the transmitted signal for our example bit stream (Figure 2), the transitions at bit interval boundaries are smoother than those of BPSK.

Figure 2: This plot shows the FSK waveform for same bitstream used in the BPSK example.
Figure 2 (sig32.png)

To determine the bandwidth required by this signal set, we again consider the alternating bit stream. Think of it as two signals added together: The first comprised of the signal s 0 t s 0 t , the zero signal, s 0 t s 0 t , zero, etc., and the second having the same structure but interleaved with the first and containing s 1 t s 1 t (Figure 3).

Figure 3: The depicted decomposition of the FSK-modulated alternating bit stream into its frequency components simplifies the calculation of its bandwidth.
Figure 3 (sig33.png)

Each component can be thought of as a fixed-frequency sinusoid multiplied by a square wave of period 2T 2 T that alternates between one and zero. This baseband square wave has the same Fourier spectrum as our BPSK example, but with the addition of the constant term c 0 c 0 . This quantity's presence changes the number of Fourier series terms required for the 90% bandwidth: Now we need only include the zero and first harmonics to achieve it. The bandwidth thus equals, with f 0 < f 1 f 0 f 1 , f 1 +12T( f 0 12T)= f 1 f 0 +1T f 1 1 2 T f 0 1 2 T f 1 f 0 1 T . If the two frequencies are harmonics of the bit-interval duration, f 0 = k 0 T f 0 k 0 T and f 1 = k 1 T f 1 k 1 T with k 1 > k 0 k 1 k 0 , the bandwidth equals k 1 +- k 0 +1T k 1 k 0 1 T . If the difference between harmonic numbers is 11, then the FSK bandwidth is smaller than the BPSK bandwidth. If the difference is 22, the bandwidths are equal and larger differences produce a transmission bandwidth larger than that resulting from using a BPSK signal set.

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