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Introduction
Due to the large number of continuous-time signals that are
present, the
Fourier
series provided us the first glimpse of how me we may
represent some of these signals in a general manner: as a
superposition of a number of sinusoids. Now, we can look at a
way to represent continuous-time nonperiodic signals using the
same idea of superposition. Below we will present the
Continuous-Time Fourier Transform (CTFT), also
referred to as just the Fourier Transform (FT). Because the
CTFT now deals with nonperiodic signals, we must now find a
way to include
all frequencies in the
general equations.
Equations
Continuous-Time Fourier Transform
ℱΩ=∫-∞∞ftⅇ-ⅈΩtdt
ℱ
Ω
t
f
t
Ω
t
(1)
Inverse CTFT
ft=12π∫-∞∞ℱΩⅇⅈΩtdΩ
f
t
1
2
Ω
ℱ
Ω
Ω
t
(2)
warning:
Do not be confused by notation - it is not uncommon to see
the above formula written slightly different. One of the
most common differences among many professors is the way
that the exponential is written. Above we used the radial
frequency variable
Ω
Ω in the exponential, where
Ω=2πf
Ω
2
f
, but one will often see
professors include the more explicit expression,
ⅈ2πft
2
f
t
, in the exponential.
Click here for an
overview of the notation used in Connexion's DSP modules.
The above equations for the CTFT and its inverse come directly
from the Fourier series and our understanding of its
coefficients. For the CTFT we simply utilize integration rather than
summation to be able to express the aperiodic signals. This
should make sense since for the CTFT we are simply extending
the ideas of the Fourier series to include nonperiodic
signals, and thus the entire frequency spectrum. Look at the
Derivation of the Fourier
Transform for a more in depth look at this.
Relevant Spaces
The Continuous-Time Fourier Transform maps infinite-length,
continuous-time signals in
L2L2
to infinite-length, continuous-frequency signals in
L2L2.
Review the
Fourier
Analysis for an overview of all the spaces used in
Fourier analysis.
Example Problems
Problem 1
Find the Fourier Transform (CTFT) of the function
ft=
ⅇ-αtift≥00otherwise
f
t
α
t
t
0
0
(3)
[
Click for Solution 1 ]
Solution 1
In order to calculate the Fourier transform, all we need
to use is
Equation 1,
complex exponentials,
and basic calculus.
ℱΩ=∫-∞∞ftⅇ-ⅈΩtdt=∫0∞ⅇ-αtⅇ-ⅈΩtdt=∫0∞ⅇ-tα+ⅈΩdt=0--1α+ⅈΩ
ℱ
Ω
t
f
t
Ω
t
t
0
α
t
Ω
t
t
0
t
α
Ω
0
-1
α
Ω
(4)
ℱΩ=1α+ⅈΩ
ℱ
Ω
1
α
Ω
(5)
[
Hide Solution 1 ]
Problem 2
Find the inverse Fourier transform of the square wave
defined as
XΩ=
1if|Ω|≤M0otherwise
X
Ω
1
Ω
M
0
(6)
[
Click for Solution 2 ]
Solution 2
Here we will use
Equation 2 to
find the inverse FT given that
t≠0
t
0
.
xt=12π∫-MMⅇ
ⅈ
Ω
t
dΩ=12πⅇ
ⅈ
Ω
t
|Ω,Ω=ⅇⅈw=1πtsinMt
x
t
1
2
Ω
M
M
Ω
t
Ω
w
1
2
Ω
t
1
t
M
t
(7)
xt=MπsincMtπ
x
t
M
sinc
M
t
(8)
[
Hide Solution 2 ]
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