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<!DOCTYPE document PUBLIC "-//CNX//DTD CNXML 0.5 plus MathML//EN" "http://cnx.rice.edu/cnxml/0.5/DTD/cnxml_mathml.dtd">
<document xmlns="http://cnx.rice.edu/cnxml" xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="new38">
  <name>Small Signal Model for Bipolar Transistor</name>
  <metadata>
  <md:version>2.12</md:version>
  <md:created>2000/08/04</md:created>
  <md:revised>2007/08/23 18:39:25.199 GMT-5</md:revised>
  <md:authorlist>
      <md:author id="wlw">
      <md:firstname>Bill</md:firstname>
      
      <md:surname>Wilson</md:surname>
      <md:email>wlw@madriver.net</md:email>
    </md:author>
  </md:authorlist>

  <md:maintainerlist>
    <md:maintainer id="wlw">
      <md:firstname>Bill</md:firstname>
      
      <md:surname>Wilson</md:surname>
      <md:email>wlw@madriver.net</md:email>
    </md:maintainer>
    <md:maintainer id="lizzardg">
      <md:firstname>Elizabeth</md:firstname>
      
      <md:surname>Gregory</md:surname>
      <md:email>elizabeth.gregory@gmail.com</md:email>
    </md:maintainer>
    <md:maintainer id="jsilv">
      <md:firstname>Jeffrey</md:firstname>
      <md:othername>M</md:othername>
      <md:surname>Silverman</md:surname>
      <md:email>JSilverman@astro.berkeley.edu</md:email>
    </md:maintainer>
    <md:maintainer id="gerardw">
      <md:firstname>Gerard</md:firstname>
      
      <md:surname>Wysocki</md:surname>
      <md:email>gerardw@rice.edu</md:email>
    </md:maintainer>
  </md:maintainerlist>
  
  <md:keywordlist>
    <md:keyword>bipolar transistor</md:keyword>
    <md:keyword>signal model</md:keyword>
  </md:keywordlist>

  <md:abstract>Small Signal Model for Bipolar Transistor</md:abstract>
</metadata>

  <content>

    <para id="para1">
      Thus if we go back to <cnxn document="m1017" target="fig10">the
      circuit model</cnxn> for the common emitter transistor, and
      re-draw it as a <term>small signal model</term> it would look
      something like <cnxn target="fig16"/>. Here we have replaced the
      diode with a linear element (a resistor, called

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>π</m:mi>
          </m:msub>
        </m:ci>
      </m:math>)

    and we have changed the notation for the currents from

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>B</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    and

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    to

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>i</m:mi>
            <m:mi>b</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    and

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>i</m:mi>
            <m:mi>c</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    respectively, to remind us that we are now talking about small signal
    ac quantities, not large signal ones. The bias currents

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>B</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    and

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    are still flowing through the device (and we will leave it to ELEC 342
    to discuss how these are generated and set up) but they do not appear
    in the small signal model. This model is only used to figure out how
    the transistor behaves for the ac signal going through it, not have
    it responds to large DC values.

  </para>

  <figure id="fig16">
    <media type="image/png" src="3.16.png"/>
    <caption>Small signal linear model for the common emitter transistor
    </caption>
  </figure>

  <para id="para2">
    Now

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>π</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    the equivalent small signal resistance of the base-emitter diode
    is given simply by the inverse of the conductance of the
    equivalent diode. Remember, we found

      <equation id="eqn26">
        <m:math>
          <m:apply>
	    <m:eq/>
	    <m:ci>
	      <m:msub>
		<m:mi>r</m:mi>
		<m:mi>π</m:mi>
	      </m:msub>
	    </m:ci>

            <m:apply>
	      <m:divide/>
              <m:cn>1</m:cn>
              <m:apply><m:times/>
                <m:apply><m:divide/>
                  <m:ci>q</m:ci>
                  <m:apply><m:times/>
                    <m:ci>k</m:ci>
                    <m:ci>T</m:ci>
                  </m:apply>
                </m:apply>
                <m:ci>
                  <m:msub>
                    <m:mi>I</m:mi>
                    <m:mi>B</m:mi>
                  </m:msub>
                </m:ci>
              </m:apply>
            </m:apply>


            <m:apply><m:divide/>
              <m:cn>1</m:cn>
              <m:apply><m:times/>
                <m:apply><m:divide/>
                  <m:ci>q</m:ci>
                  <m:apply><m:times/>
                    <m:ci>k</m:ci>
                    <m:ci>T</m:ci>
                  </m:apply>
                </m:apply>
                <m:apply><m:divide/>
                  <m:ci>
                    <m:msub>
                      <m:mi>I</m:mi>
                      <m:mi>C</m:mi>
                    </m:msub>
                  </m:ci>
                  <m:ci>β</m:ci>
                </m:apply>
              </m:apply>
            </m:apply>

            <m:apply><m:divide/>
              <m:ci>β</m:ci>
              <m:apply><m:times/>
                <m:cn>40</m:cn>
                <m:ci>
                  <m:msub>
                    <m:mi>I</m:mi>
                    <m:mi>C</m:mi>
                  </m:msub>
                </m:ci>
              </m:apply>
            </m:apply>

          </m:apply>
        </m:math>
      </equation>


    where we have used the fact that

     <m:math>
       <m:apply><m:eq/>
         <m:ci>
           <m:msub>
             <m:mi>I</m:mi>
             <m:mi>C</m:mi>
           </m:msub>
         </m:ci>
         <m:apply><m:times/>
           <m:ci>β</m:ci>
           <m:ci>
             <m:msub>
               <m:mi>I</m:mi>
               <m:mi>B</m:mi>
             </m:msub>
           </m:ci>
         </m:apply>
       </m:apply>
     </m:math>

    and

    <m:math>
      <m:apply><m:eq/>
        <m:apply><m:divide/>
          <m:ci>q</m:ci>
          <m:apply><m:times/>
            <m:ci>k</m:ci>
            <m:ci>T</m:ci>
          </m:apply>
        </m:apply>
        <m:apply>
	    <m:times/>
	    <m:cn>40</m:cn>
	    <m:apply>
	      <m:power/>
	      <m:ci>V</m:ci>
	      <m:cn>-1</m:cn>
	    </m:apply>
	  </m:apply>
	</m:apply>
      </m:math>.

    As we said earlier, typical values for <m:math><m:ci>β</m:ci>
    </m:math>in a standard bipolar transistor will be around
    100. Thus, for a typical collector bias current of

      <m:math>
        <m:apply><m:eq/>
          <m:ci>
            <m:msub>
              <m:mi>I</m:mi>
              <m:mi>C</m:mi>
            </m:msub>
          </m:ci>
	  <m:apply>
	    <m:times/>
	    <m:cn>1</m:cn>
	    <m:ci>mA</m:ci>
	  </m:apply>
        </m:apply>
      </m:math>,

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>π</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    will be about 2.5 kΩ.

  </para>

  <para id="para3">
    There is one more item we should consider in putting together our
    model for the bipolar transistor. We did not get things completely
    right when we drew the <cnxn document="m1016" target="fig09">common emitter characteristic curves</cnxn> for the
    transistor. There is a somewhat subtle effect going on when

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>
    is increased. Remember, we said that the current coming out of the
    collector is not effected by how big the drop was in the reverse
    biased base-collector junction. The collector current just depends
    on how many electrons are injected into the base by the emitter,
    and how many of them make it across the base to the base-collector
    junction. As the base-collector reverse bias is increased (by
    increasing

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    the depletion width of the base-collector junction increases as
    well. This has the effect of making the base region somewhat
    shorter. This means that a few more electrons are able to make it
    across the base region without recombining and as a result
    <m:math><m:ci>α</m:ci> </m:math> and hence
    <m:math><m:ci>β</m:ci> </m:math> increase somewhat. This then
    means that

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    goes up slightly with increasing

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>.

    The effect is called <term>base width modulation</term>.
    Let us now include that effect in the common emitter
    characteristic curves. As you can see in <cnxn target="fig18"/>,
    there is now a slope to the

     <m:math>
      <m:apply>
        <m:ci type="fn"><m:msub>
          <m:mi>I</m:mi>
          <m:mi>C</m:mi>
        </m:msub></m:ci>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:apply>
    </m:math>

    curve, with

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    increasing somewhat as

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    increases. The effect has been somewhat exaggerated in <cnxn target="fig17"/>, and I will now make the slope even bigger so
    that we may define a new quantity, called the <term>Early
    Voltage</term>.

  </para>


  <figure id="fig17"><media type="image/png" src="3.17b.png"/>
	<caption>Common emitter response with base-width modulation
      effect</caption>
</figure>

  <figure id="fig18"><media type="image/png" src="3.18b.png"/>
	<caption>Finding the Early Voltage</caption>
</figure>

  <para id="para4">
    Back in the very beginning of the transistor era, an engineer
    at Bell Labs, Jim Early, predicted that there would be a slope to the

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    curves, and that they would all project back to the same
    intersection point on the horizontal axis. Having made that
    prediction, Jim went down into the lab, made the measurement, and
    confirmed his prediction, thus showing that the theory of
    transistor behavior was being properly understood. The point of
    intersection of the

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    axis is known as the <term>Early Voltage</term>.  Since
    the symbol

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>E</m:mi>
          </m:msub>
        </m:ci>
      </m:math>,

    for the emitter voltage was already taken, they had to label the
    Early Voltage

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>A</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    instead. (Even though the intersection point in on the negative
    half of the

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>CE</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    axis,

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>A</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    is universally quoted as a positive number.)

  </para>

    <para id="para5">
      How can we model the sloping I-V curve? We can do almost the
      same thing as we did with the solar cell. The horizontal part of
      the curve is still a current source, and the sloped part is
      simply a resistor in parallel with it. Here is a graphical
      explanation in <cnxn target="fig19"/>.
    </para>


    <figure id="fig19">
      <media type="image/png" src="3.19.png"/>
      <caption>Combining a current course and a resistor in parallel</caption>
    </figure>

  <para id="para6">
    Usually, the slope is much less than we have shown here, and so
    for any given value of

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>,

    we can just take the slope of the line as

     <m:math>
       <m:apply><m:divide/>
         <m:ci>
           <m:msub>
             <m:mi>I</m:mi>
             <m:mi>C</m:mi>
           </m:msub>
         </m:ci>
         <m:ci>
           <m:msub>
             <m:mi>V</m:mi>
             <m:mi>A</m:mi>
           </m:msub>
         </m:ci>
       </m:apply>
     </m:math>,

    and hence the resistance, which is usually called

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>o</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    is just

      <m:math>
        <m:apply><m:divide/>
          <m:ci>
            <m:msub>
              <m:mi>V</m:mi>
              <m:mi>A</m:mi>
            </m:msub>
          </m:ci>
          <m:ci>
            <m:msub>
              <m:mi>I</m:mi>
              <m:mi>c</m:mi>
            </m:msub>
          </m:ci>
        </m:apply>
      </m:math>.

    Thus, we add

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>o</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    to the small signal model for the bipolar transistor. This is
    shown in <cnxn target="fig20"/>. In a good quality modern
    transistor, the Early Voltage,

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>V</m:mi>
            <m:mi>A</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    will be on the order of 150-250 Volts. So if we let

      <m:math>
        <m:apply><m:eq/>
          <m:ci>
            <m:msub>
              <m:mi>V</m:mi>
              <m:mi>A</m:mi>
            </m:msub>
          </m:ci>
          <m:cn>200</m:cn>
        </m:apply>
      </m:math>,

      and we imagine that we have our transistor biased at 1 mA, then

      <equation id="eqn27">
        <m:math>
          <m:apply><m:eq/>
            <m:ci>
              <m:msub>
                <m:mi>r</m:mi>
                <m:mi>o</m:mi>
              </m:msub>
            </m:ci>
            <m:apply><m:divide/>
	      <m:apply>
		<m:times/>
		<m:cn>200</m:cn>
		<m:ci>V</m:ci>
	      </m:apply>
	      <m:apply>
		<m:times/>
		<m:cn>1</m:cn>
		<m:ci>mA</m:ci>
	      </m:apply>
            </m:apply>
	    <m:apply>
	      <m:times/>
	      <m:cn>200</m:cn>
	      <m:ci>kΩ</m:ci>
	    </m:apply>
          </m:apply>
        </m:math>
      </equation>


    which is usually much larger than most of the other resistors you
    will encounter in a typical circuit.  In most instances,

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>r</m:mi>
            <m:mi>o</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    can be ignored with no problem. If you get into high impedance
    circuits however, as you might find in a instrumentation
    amplifier, then

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>v</m:mi>
            <m:mi>be</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    has to be taken into account.

  </para>


   <figure id="fig20">
    <media type="image/png" src="3.20.png"/>
    <caption>Including ro in the small signal linear model</caption>
  </figure>

  <para id="para7">
    Sometimes it is advantageous to use a mutual transconductance
    model instead of a current gain model for the transistor. If we
    call the input small signal voltage

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>v</m:mi>
            <m:mi>be</m:mi>
          </m:msub>
        </m:ci>
      </m:math>,

    then obviously

  </para>

  <para id="para8">

     <equation id="eqn28">
       <m:math>
           <m:apply><m:eq/>
             <m:ci>
               <m:msub>
                 <m:mi>i</m:mi>
                 <m:mi>b</m:mi>
               </m:msub>
             </m:ci>
             <m:apply><m:divide/>
               <m:ci>
                 <m:msub>
                   <m:mi>v</m:mi>
                   <m:mi>be</m:mi>
                 </m:msub>
               </m:ci>
               <m:ci>
                 <m:msub>
                   <m:mi>r</m:mi>
                   <m:mi>π</m:mi>
                 </m:msub>
               </m:ci>
             </m:apply>

             <m:apply><m:divide/>
               <m:ci>
                 <m:msub>
                   <m:mi>v</m:mi>
                   <m:mi>be</m:mi>
                 </m:msub>
               </m:ci>
               <m:apply><m:divide/>
                 <m:ci>β</m:ci>
                 <m:apply><m:times/>
                   <m:cn>40</m:cn>
                   <m:ci>
                     <m:msub>
                       <m:mi>I</m:mi>
                       <m:mi>C</m:mi>
                     </m:msub>
                   </m:ci>
                 </m:apply>
               </m:apply>
             </m:apply>

          </m:apply>
         </m:math>
       </equation>

  </para>

  <para id="para9">
    But
  </para>

  <para id="para10">

    <equation id="eqn29">
      <m:math>
           <m:apply><m:equivalent/>
             <m:apply><m:eq/>
               <m:ci>
                 <m:msub>
                   <m:mi>i</m:mi>
                   <m:mi>c</m:mi>
                 </m:msub>
               </m:ci>
               <m:apply><m:times/>
                 <m:ci>β</m:ci>
                 <m:ci>
                   <m:msub>
                     <m:mi>i</m:mi>
                     <m:mi>b</m:mi>
                   </m:msub>
                 </m:ci>
               </m:apply>

               <m:apply><m:divide/>
                 <m:apply><m:times/>
                   <m:ci>β</m:ci>
                   <m:ci>
                     <m:msub>
                       <m:mi>v</m:mi>
                       <m:mi>be</m:mi>
                     </m:msub>
                   </m:ci>
                 </m:apply>
                 <m:apply><m:divide/>
                   <m:ci>β</m:ci>
                   <m:apply><m:times/>
                     <m:cn>40</m:cn>
                     <m:ci>
                       <m:msub>
                         <m:mi>I</m:mi>
                         <m:mi>C</m:mi>
                       </m:msub>
                     </m:ci>
                   </m:apply>
                 </m:apply>
               </m:apply>

               <m:apply><m:times/>
                 <m:cn>40</m:cn>
                 <m:ci>
                   <m:msub>
                     <m:mi>I</m:mi>
                     <m:mi>C</m:mi>
                   </m:msub>
                 </m:ci>
                 <m:ci>
                   <m:msub>
                     <m:mi>v</m:mi>
                     <m:mi>be</m:mi>
                   </m:msub>
                 </m:ci>
               </m:apply>

             </m:apply>

             <m:apply><m:times/>
               <m:ci>
                 <m:msub>
                   <m:mi>g</m:mi>
                   <m:mi>m</m:mi>
                 </m:msub>
               </m:ci>
               <m:ci>
                 <m:msub>
                   <m:mi>v</m:mi>
                   <m:mi>be</m:mi>
                 </m:msub>
               </m:ci>
             </m:apply>

           </m:apply>
         </m:math>
       </equation>

  </para>

  <para id="para11">
    Where

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>g</m:mi>
            <m:mi>m</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    is called the mutual transconductance of the transistor.
    Notice that <m:math><m:ci>β</m:ci></m:math>
    has completely cancelled out in the expression for

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>g</m:mi>
            <m:mi>m</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    and that

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>g</m:mi>
            <m:mi>m</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    depends only upon the bias current,

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>,

    flowing through the collector and not on any of the physical
    properties of the transistor itself!

  </para>


   <figure id="fig21">
    <media type="image/png" src="3.21.png"/>
    <caption>Transconductance small signal linear model</caption>
  </figure>

  <para id="para12">
    Finally, there is one last physical consideration we should make
    concerning the operation of the bipolar transistor. The
    base-collector junction is reverse biased. We know that if we
    apply too much reverse bias to a pn junction, it can breakdown
    through avalanche multiplication. Breakdown in a transistor is
    somewhat "softer" than for a simple diode, because once a small
    amount of avalanche multiplication starts, extra holes are
    generated within the base-collector junction. These holes fall up,
    into the base, where they act as additional base current, which,
    in turn, causes

      <m:math>
        <m:ci>
          <m:msub>
            <m:mi>I</m:mi>
            <m:mi>C</m:mi>
          </m:msub>
        </m:ci>
      </m:math>

    to increase. This is shown in <cnxn target="fig22"/>.

  </para>

   <figure id="fig22">
    <media type="image/png" src="3.22.png"/>
    <caption>Ionization at the base-collector junction causes additional
      base current</caption>
  </figure>

  <para id="para13">A set of characteristic curves for a transistor going into
    breakdown is also shown in <cnxn target="fig23"/>.
  </para>

  <figure id="fig23"><media type="image/png" src="3.23b.png"/>
	<caption>Bipolar Transistor going into breakdown</caption>
</figure>

  <para id="para14">
    Well, we have learned quite a bit about bipolar transistors in a
    very short space.  Go back over this chapter and see if you can
    pick out the two or three most important ideas of equations which
    would make up a set of "facts" that you could stick away in you
    head someplace. Do this so you will always have them to refer to
    when the subject of bipolars comes up (In say, a job interview or
    something!).
  </para>

  </content>
  
</document>
