Consider the scaling function
φt={1 if 0≤t<10 if else
φ
t
1
0
t
1
0
else
Define
V
0
=closurespan
φt−n
n∈Z
V
0
closure
span
φ
t
n
n
where the overbar denotes closure which
is the union of a set and its limit points.
Any
f
0
t∈
V
0
f
0
t
V
0
can be written as
f
0
t=∑
n
=−∞∞
a
n
φt−n
f
0
t
n
a
n
φ
t
n
.
V
0
V
0
contains functions constant over
n
n+1
n
n
1
.
Now define
φ
k
,
n
t=2−k2φ2−kt−n
φ
k
,
n
t
2
k
2
φ
2
k
t
n
Note:
∥
φ
k
,
n
∥=1
φ
k
,
n
1
Now define
V
k
=closurespan
φ
k
,
n
t
n∈Z
V
k
closure
span
φ
k
,
n
t
n
. Then note that
…⊂
V
2
⊂
V
1
⊂
V
0
⊂
V
-1
⊂…
…
V
2
V
1
V
0
V
-1
…
coarse
fine
coarse fine
Can show:
-
V
∞
=0
V
∞
0
... contains no signals.
-
V
∞
=L2
V
∞
L
2
... contains all signals.
-
φ
k
,
n
t
n∈Z
φ
k
,
n
t
n
form an orthonormal basis for
V
k
V
k
.
So what does the projection of
ft∈
L
2
f
t
L
2
onto
V
k
V
k
look like?
Say:
f
k
t=∑
m
m
a
k
,
m
φ
k
,
m
t
Say:
f
k
t
m
m
a
k
,
m
φ
k
,
m
t
Know:
∀
n
:(〈
φ
k
,
n
t,ft−
f
k
t〉=0)⇒(〈
φ
k
,
n
t,ft〉=〈
φ
k
,
n
,
f
k
t〉)
Know:
n
φ
k
,
n
t
f
t
f
k
t
0
φ
k
,
n
t
f
t
φ
k
,
n
f
k
t
(1)
∀
n
:〈
φ
k
,
n
t,ft〉=∑
m
m
a
k
,
m
〈(
φ
k
,
n
t,
φ
k
,
m
t)〉
n
φ
k
,
n
t
f
t
m
m
a
k
,
m
φ
k
,
n
t
φ
k
,
m
t
∀
n
:〈
φ
k
,
n
t,ft〉=
a
k
,
n
n
φ
k
,
n
t
f
t
a
k
,
n
Thus:
a
k
,
n
=∫−∞∞
φ
k
,
n
t¯ftd
t
a
k
,
n
t
φ
k
,
n
t
f
t
(2)
a
k
,
n
=∫n2k(n+1)2kft2−k2d
t
a
k
,
n
t
n
2
k
n
1
2
k
f
t
2
k
2
Since:
and
f
n
t=∑
n
=−∞∞12k∫n2k(n+1)2kftd
t
(2−k2
φ
k
,
n
t)
f
n
t
n
1
2
k
t
n
2
k
n
1
2
k
f
t
2
k
2
φ
k
,
n
t
(3)
Where
-
12k∫n2k(n+1)2kftd
t
1
2
k
t
n
2
k
n
1
2
k
f
t
is the average value of
ft
f
t
in the interval
-
2−k2
φ
k
,
n
t
2
k
2
φ
k
,
n
t
is height 1