We will not always be dealing with transmission
lines excited with a pulse. Although this is a good model for
digital circuitry, it will not always apply. When we go to analog
signals (rf, high frequency analog, etc.) we will need more tools
than are available to us at this point. In the
not-too-distant-past, the material we will next consider was
starting to be considered passé. The rf spectrum was more or
less filled up, and the watchword was "digital". Now, in the new
age of wireless communication, cell phones, and rf Local Area
Networks, demand for engineers who understand ac behavior on
transmission lines and who can design systems which work well
with rf signals are very much in demand. Pay heed to what we say
here, and you might well find yourself with many lucrative job
offers in the future.
To begin, we want to consider a transmission line
which is being excited with an oscillating source Figure 1.
The usual set-up includes a source, with a sinusoidal output, a
source impedance
Z
g
Z
g
a transmission line with impedance
Z
0
Z
0
,
LL meters long, and a
load of impedance
Z
L
Z
L
at the end.
Let's look at the source first. We can describe
the output waveform from the generator as
Vt=
V
g
cosωt+θ
V
t
V
g
ω
t
θ
(1)
Which when plotted lookes like
Figure 2.
The oscillating waveform has a period
TT and its angular frequency
ωω is given as
ω=2πT=2πf
ω
2
T
2
f
(2)
The angle,
θθ, which
specifies how much the wave is leading a cosine function with
zero off-set is given by
θ=2πτT
θ
2
τ
T
(3)
What we
do not want to do, is carry a bunch
of sine and cosine functions around with us everywhere. Once we
start multiplying and dividing, the trig turns into a big mess,
and gets in the way of our understanding of what is going
on. The way we deal with this, as every good 242 student knows,
is to introduce
phasors.
Since we know from Euler's Identity
V
g
ⅇⅈωt+θ=
V
g
cosωt+θ+ⅈsinωt+θ
V
g
ω
t
θ
V
g
ω
t
θ
ω
t
θ
(4)
If we take a real part of
V
g
ⅇⅈωt+θ
V
g
ω
t
θ
we will extract the voltage waveform we desire. We
will re-write this function as
V
g
ⅇⅈωt+θ=
V
g
ⅇⅈθⅇⅈωt
V
g
ω
t
θ
V
g
θ
ω
t
(5)
and then
define
V
∼
g
V
∼
g
as the
phasor voltage where
V
∼
g
=
V
g
ⅇⅈθ
V
∼
g
V
g
θ
(6)
Note that
V
∼
g
V
∼
g
is a complex quantity, with both a magnitude
|
V
g
|
V
g
and a phase angle
θθ. In order to retrieve a real
voltage signal from a phasor, we have to multiply the phasor by
ⅇⅈωt
ω
t
and then take the real part. Note that this is the
same thing as plotting the phasor on the complex plane, and then
observing the projection of the phasor on the real axis, as the
phasor rotates around at a rate
ωt
ω
t
Figure 3.
This method of visualization will sometimes help make results
seem a little easier to understand, or at least check for
reasonableness.
"This course offers an introduction to solid state device including field effect and bipolar transistors. Properties of transmission lines and propagating E&M waves are also presented. It is […]"