Summary: Using the Smith Chart to match the appropriate circuit elements to a line.
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This gets us to "B", and we find that
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| Matching the load with a capacitor |
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The capacitor and the inductor just cancel each other out (series
resonance) and so the apparent load for the line is just
We were lucky that the real part of
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How could we match this load? We could add another 25Ω in series with the first resistor, but if we want to maximize the power we deliver to the first one, this would not be a very satisfactory approach. Let's move down the line a ways. If we go to point "B", we find that
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at this spot,
There's one awkward feature to this solution, and that is we have to cut the line to insert the capacitor. It would be a lot easier if we could simply add something across the line, instead of having to cut it. This is easily done, if we go over into the admittance world.
"This course offers an introduction to solid state device including field effect and bipolar transistors. Properties of transmission lines and propagating E&M waves are also presented. It is […]"