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The Matrix Exponential

Module by: Steven Cox

Summary: This module describes the general idea of matrix exponential.

The matrix exponential is a powerful means for representing the solution to nn linear, constant coefficient, differential equations. The initial value problem for such a system may be written x t=Axt x t A x t x0=x0 x 0 x0 where AA is the n-by-n matrix of coefficients. By analogy to the 1-by-1 case we might expect

xt=Atu x t A t u (1)
to hold. Our expectations are granted if we properly define At A t . Do you see why simply exponentiating each element of At will no suffice?

There are at least 4 distinct (but of course equivalent) approaches to properly defining At A t . The first two are natural analogs of the single variable case while the latter two make use of heavier matrix algebra machinery.

Please visit each of these modules to see the definition and a number of examples.

For a concrete application of these methods to a real dynamical system, please visit the Mass-Spring-Damper module.

Regardless of the approach, the matrix exponential may be shown to obey the 3 lovely properties

  1. ddtAt=AAt=AtA t A t A A t A t A
  2. At1+t2=At1At2 A t1 t2 A t1 A t2
  3. At A t is nonsingular and At-1=-At A t A t

Let us confirm each of these on the suite of examples used in the submodules.

Example 1

If A=1002 A 1 0 0 2 then At=t002t A t t 0 0 2 t

  1. ddtAt=t0022t=1002t002t t A t t 0 0 2 2 t 1 0 0 2 t 0 0 2 t
  2. t1+t2002t1+2t2=t1t2002t12t2=t1002t1t2002t2 t1 t2 0 0 2 t1 2 t2 t1 t2 0 0 2 t1 2 t2 t1 0 0 2 t1 t2 0 0 2 t2
  3. At-1=-t00-2t=-At A t t 0 0 2 t A t

Example 2

If A=01-10 A 0 1 -1 0 then At=costsint-sintcost A t t t t t

  1. ddtAt=-sintcost-cost-sint t A t t t t t and AAt=-sintcost-cost-sint A A t t t t t
  2. You will recognize this statement as a basic trig identity cost1+t2sint1+t2-sint1+t2cost1+t2=cost1sint1-sint1cost1cost2sint2-sint2cost2 t1 t2 t1 t2 t1 t2 t1 t2 t1 t1 t1 t1 t2 t2 t2 t2
  3. Using the cofactor expansion we find At-1=cost-sintsintcost=cos-t-sin-tsin-tcos-t=-At A t t t t t t t t t A t

Example 3

If A=0100 A 0 1 0 0 then At=1t01 A t 1 t 0 1

  1. ddtAt=0100=AAt t A t 0 1 0 0 A A t
  2. 1t1+t201=1t1011t201 1 t1 t2 0 1 1 t1 0 1 1 t2 0 1
  3. 1t01-1=1-t01=-At 1 t 0 1 1 t 0 1 A t

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