You may recall from Calculus that for any numbers
aa and
tt one may achieve
ⅇat
a
t
via
ⅇat=∑k=0∞atkk!
a
t
k
0
a
t
k
k
(1)
The natural matrix definition is therefore
ⅇAt=∑k=0∞Atkk!
A
t
k
0
A
t
k
k
(2)
where
A0=I
A
0
I
is the
nn-by-
nn
identity matrix.
The easiest case is the diagonal case, e.g.,
A=1002
A
1
0
0
2
for then
Atk=tk002tk
A
t
k
t
k
0
0
2
t
k
and so (recalling Equation 1 above)
ⅇAt=ⅇt00ⅇ2t
A
t
t
0
0
2
t
Note that this is NOT the exponential of each
element of AA.
As a second example let us suppose
A=01-10
A
0
1
-1
0
We recognize that its powers cycle, i.e.,
A2=-100-1
A
2
-1
0
0
-1
A3=0-110
A
3
0
-1
1
0
A4=1001
A
4
1
0
0
1
A5=01-10=A
A
5
0
1
-1
0
A
and so
ⅇAt=1-t22!+t44!-…t-t33!+t55!-…-t+t33!-t55!+…1-t22!+t44!-…=costsint-sintcost
A
t
1
t
2
2
t
4
4
…
t
t
3
3
t
5
5
…
t
t
3
3
t
5
5
…
1
t
2
2
t
4
4
…
t
t
t
t
If
A=0100
A
0
1
0
0
then
A2=A3=Ak=0100
A
2
A
3
A
k
0
1
0
0
and so
ⅇAt=I+tA=1t01
A
t
I
t
A
1
t
0
1