We now discuss pointwise and norm convergence of vectors.
Other types of convergence also exist, and one in particular,
uniform convergence,
can also be studied. For this discussion , we will assume
that the vectors belong to a normed vector space.
A sequence
gn
|
n
=1∞
n
1
gn
converges pointwise to the limit
g
g
if each element of
gn
gn
converges to the corresponding element in
g
g.
Below are few examples to try and help illustrate this idea.
gn
=
gn
1
gn
2=1+1n2−1n
gn
gn
1
gn
2
1
1
n
2
1
n
First we find the following limits for our two
gn
gn's:
limit
n
→
∞
gn
1=1
n
gn
1
1
limit
n
→
∞
gn
2=2
n
gn
2
2
Therefore we have the following,
limit
n
→
∞
gn
=g
n
gn
g
pointwise, where
g=12
g
1
2
.
∀
t
,t∈R:
gn
t=tn
t
t
gn
t
t
n
As done above, we first want to examine the limit
limit
n
→
∞
gn
t0=limit
n
→
∞
t0n=0
n
gn
t0
n
t0
n
0
where
t0∈R
t0
. Thus
limit
n
→
∞
gn=g
n
gn
g
pointwise where
gt=0
g
t
0
for all
t∈R
t
.
The sequence
gn
|
n
=1∞
n
1
gn
converges to gg in
norm if
limit
n
→
∞
∥
gn
−g∥=0
n
gn
g
0
. Here
∥˙∥
˙
is the norm of the
corresponding vector space of
g
n
g
n
's. Intuitively this means the distance between
vectors
g
n
g
n
and
g
g decreases to 00.
g
n
=1+1n2−1n
g
n
1
1
n
2
1
n
Let
g=12
g
1
2
∥
g
n
−g∥=1+1n−12+2−1n2=1n2+1n2=2n
g
n
g
1
1
n
1
2
2
1
n
1
2
1
n
2
1
n
2
2
n
(1)
Thus
limit
n
→
∞
∥
g
n
−g∥=0
n
g
n
g
0
Therefore,
g
n
→g
g
n
g
in norm.
g
n
t={tn if 0≤t≤10 otherwise
g
n
t
t
n
0
t
1
0
Let
gt=0
g
t
0
for all tt.
∥
g
n
t−gt∥=∫01t2n2d
t
=t33n2|
n
=01=13n2
g
n
t
g
t
t
1
0
t
2
n
2
n
0
1
t
3
3
n
2
1
3
n
2
(2)
Thus
limit
n
→
∞
∥
g
n
t−gt∥=0
n
g
n
t
g
t
0
Therefore,
g
n
t→gt
g
n
t
g
t
in norm.
For
Rm
m
, pointwise and norm convergence are equivalent.
g
n
i→gi
g
n
i
g
i
Assuming the above, then
∥
g
n
−g∥2=∑
i
=1m
g
n
i−gi2
g
n
g
2
i
m
1
g
n
i
g
i
2
Thus,
limit
n
→
∞
∥
g
n
−g∥2=limit
n
→
∞
∑
i
=1m2=∑
i
=1mlimit
n
→
∞
2=0
n
g
n
g
2
n
i
m
1
g
n
i
g
i
2
i
m
1
n
g
n
i
g
i
2
0
(3)
∥
g
n
−g∥→0
g
n
g
0
limit
n
→
∞
∑
i
=1m2=∑
i
=1mlimit
n
→
∞
2=0
n
i
m
1
g
n
i
g
i
2
i
m
1
n
g
n
i
g
i
2
0
(4)
Since each term is greater than or equal zero, all
'
mm' terms must be zero.
Thus,
limit
n
→
∞
2=0
n
g
n
i
g
i
2
0
forall
ii. Therefore,
g
n
→g
pointwise
g
n
g
pointwise
In infinite dimensional spaces the above theorem is no
longer true. We prove this with counter examples shown
below.
We are given the following function:
g
n
t={n if 0<t<1n0 otherwise
g
n
t
n
0
t
1
n
0
Then
limit
n
→
∞
g
n
t=0
n
g
n
t
0
This means that,
g
n
t→gt
g
n
t
g
t
pointwise
where for all tt
gt=0
g
t
0
.
Now,
∥
g
n
∥2=∫−∞∞|
g
n
t|2d
t
=∫01nn2d
t
=n→∞
g
n
2
t
g
n
t
2
t
1
n
0
n
2
n
(5)
Since the function norms blow up, they cannot converge to
any function with finite norm.
We are given the following function:
g
n
t={1 if 0<t<1n0 otherwise
if n is even
g
n
t
1
0
t
1
n
0
if n is even
g
n
t={-1 if 0<t<1n0 otherwise
if n is odd
g
n
t
-1
0
t
1
n
0
if n is odd
Then,
∥
g
n
−g∥=∫01n1d
t
=1n→0
g
n
g
t
1
n
0
1
1
n
0
where
gt=0
g
t
0
for all tt. Therefore,
g
n
→g
in norm
g
n
g
in norm
However, at
t=0
t
0
,
g
n
t
g
n
t
oscillates between -1 and 1, and so it does not
converge. Thus,
g
n
t
g
n
t
does not converge pointwise.
Prove if the following sequences are pointwise convergent,
norm convergent, or both and then state their limits.
-
g
n
t={1nt if 0<t0 if t≤0
g
n
t
1
n
t
0
t
0
t
0
-
g
n
t={e−(nt) if t≥00 if t<0
g
n
t
n
t
t
0
0
t
0