Y
c
Ω=
H
LP
ΩYΩT
Y
c
Ω
H
LP
Ω
Y
Ω
T
(1)
where we know that
Yω=XωGω
Y
ω
X
ω
G
ω
and
Gω
G
ω
is the frequency response of the DT LTI system.
Also, remember that
ω≡ΩT
ω
Ω
T
So,
Y
c
Ω=
H
LP
ΩGΩTXΩT
Y
c
Ω
H
LP
Ω
G
Ω
T
X
Ω
T
(2)
where
Y
c
Ω
Y
c
Ω
and
H
LP
Ω
H
LP
Ω
are CTFTs and
GΩT
G
Ω
T
and
XΩT
X
Ω
T
are DTFTs.
Xω=2πT∑k=-∞∞
X
c
ω-2πkT
X
ω
2
T
k
X
c
ω
2
k
T
OR
XΩT=2πT∑k=-∞∞
X
c
Ω-k
Ω
s
X
Ω
T
2
T
k
X
c
Ω
k
Ω
s
Therefore our final output signal,
Y
c
Ω
Y
c
Ω
, will be:
Y
c
Ω=
H
LP
ΩGΩT2πT∑k=-∞∞
X
c
Ω-k
Ω
s
Y
c
Ω
H
LP
Ω
G
Ω
T
2
T
k
X
c
Ω
k
Ω
s
(3)
Now, if
X
c
Ω
X
c
Ω
is bandlimited to
-
Ω
s
2
Ω
s
2
Ω
s
2
Ω
s
2
and we use the usual lowpass reconstruction filter in the
D/A,
Figure 2:
Then,
Y
c
Ω=GΩT
X
c
Ωif|Ω|<
Ω
s
20otherwise
Y
c
Ω
G
Ω
T
X
c
Ω
Ω
Ω
s
2
0
(4)
For bandlimited signals sampled at or above the Nyquist
rate, we can relate the input and output of the DSP system
by:
Y
c
Ω=
G
eff
Ω
X
c
Ω
Y
c
Ω
G
eff
Ω
X
c
Ω
(5)
where
G
eff
Ω=GΩTif|Ω|<
Ω
s
20otherwise
G
eff
Ω
G
Ω
T
Ω
Ω
s
2
0
G
eff
Ω
G
eff
Ω
is LTI if and only if the following two
conditions are satisfied:
-
Gω
G
ω
is LTI (in DT).
-
X
c
T
X
c
T
is bandlimited and sampling rate equal to or
greater than Nyquist. For example, if we had a simple
pulse described by
X
c
t=ut-
T
0
-ut-
T
1
X
c
t
u
t
T
0
u
t
T
1
where
T
1
>
T
0
T
1
T
0
. If the sampling period
T>
T
1
-
T
0
T
T
1
T
0
,
then some samples might "miss" the pulse while others
might not be "missed." This is what we term
time-varying behavior.
If
2πT>2B
2
T
2
B
and
ω
1
<BT
ω
1
B
T
, determine and sketch
Y
c
Ω
Y
c
Ω
using Figure 4.
Unfortunately, in real-world situations electrodes also pick
up ambient 60 Hz signals from lights, computers,
etc.. In fact, usually this "60 Hz noise"
is much greater in amplitude than the EKG signal shown in
Figure 5. Figure 6 shows the EKG signal; it is barely noticeable
as it has become overwhelmed by noise.
First we must note that
|YΩ|
Y
Ω
is bandlimited to ±60 Hz.
Therefore, the minimum rate should be 120 Hz. In order to
get the best results we should set
f
s
=240Hz
f
s
240
Hz
.
Ω
s
=2π240rads
Ω
s
2
240
rad
s
Therefore, we want to design a digital filter that will
remove the 60Hz component and preserve the rest.