How do we go from
xn
x
n
to CT (Figure 1)?
Place
xn
x
n
into CT on an impulse train
st
s
t
(Figure 2).
x
s
t=∑n=-∞∞xnδt-nT
x
s
t
n
x
n
δ
t
n
T
(1)
Pass
x
s
t
x
s
t
through an idea lowpass filter
H
LP
Ω
H
LP
Ω
(Figure 3).
If we had no aliasing then
x
r
t=
x
c
t
x
r
t
x
c
t
, where
xn=
x
c
nT
x
n
x
c
n
T
.
-
X
s
Ω=XΩT
X
s
Ω
X
Ω
T
where
XΩT
X
Ω
T
is the DTFT of
xn
x
n
at digital frequency
ω=ΩT
ω
Ω
T
.
-
X
r
Ω=
H
LP
Ω
X
s
Ω
X
r
Ω
H
LP
Ω
X
s
Ω
X
r
Ω=
H
LP
ΩXΩT
X
r
Ω
H
LP
Ω
X
Ω
T
-
x
s
t=∑n=-∞∞xnδt-nT
x
s
t
n
x
n
δ
t
n
T
-
x
r
t=∑n=-∞∞xnδt-nT*
h
LP
t
x
r
t
n
x
n
δ
t
n
T
h
LP
t
h
LP
t=sincπTt
h
LP
t
sinc
T
t
x
r
t=∑n=-∞∞xnsincπTt-nT
x
r
t
n
x
n
sinc
T
t
n
T
h
LP
t=sincπTt=sinπTtπTt
h
LP
t
sinc
T
t
T
t
T
t
(2)
h
LP
t
h
LP
t
"interpolates" the values of
xn
x
n
to generate
x
r
t
x
r
t
(
Figure 6).
x
r
t=∑n=-∞∞xnsinπTt-nTπTt-nT
x
r
t
n
x
n
T
t
n
T
T
t
n
T
(3)