Define
mk=∫tkφtdt
m
k
t
t
k
φ
t
μk=∑nnkhn
μ
k
n
n
k
h
n
Then
m1=∫tφtdt
m
1
t
t
φ
t
μ1=∑nnhn
μ
1
n
n
h
n
It turns out we can relate
m1
m
1
to the moments of
hn
h
n
by using the dilation equation.
m1=∫tφtdt=∫t2∑nhnφ2t−ndt=2∑nhn∫tφ2t−ndt=2∑nhn12∫α2+n2φαdα=24∑nhn∫αφαdα+24∑nhn∫nφαdα=24∑nhnm1+24∑nnhnm0=24m1∑nhn+24m0∑nnhn=24m1μ0+24m0μ1
m
1
t
t
φ
t
t
t
2
n
h
n
φ
2
t
n
2
n
h
n
t
t
φ
2
t
n
2
n
h
n
1
2
α
α
2
n
2
φ
α
2
4
n
h
n
α
α
φ
α
2
4
n
h
n
α
n
φ
α
2
4
n
h
n
m
1
2
4
n
n
h
n
m
0
2
4
m
1
n
h
n
2
4
m
0
n
n
h
n
2
4
m
1
μ
0
2
4
m
0
μ
1
(1)
So we have
m1=24m1μ0+24m0μ1
m
1
2
4
m
1
μ
0
2
4
m
0
μ
1
Solving for
m1
m
1
gives
m1=2m0μ14−2μ0
m
1
2
m
0
μ
1
4
2
μ
0
A valid scaling filter
hn
h
n
must have
μ0=2
μ
0
2
. Using this, we get
m1=m0μ12
m
1
m
0
μ
1
2
With the normalization
m0=∫φtdt=1
m
0
t
φ
t
1
, we get
m1=μ12
m
1
μ
1
2
(2)