This section covers the effects of linear transformations on measures of
central tendency and variability. Let's start with an example we
saw before in the section that defined linear transformation: temperatures
of cities. Table 1 shows the temperatures of 5 cities.
Temperatures in 5 cities on 11/16/2002
| City |
Degrees Fahrenheit |
Degrees Centigrade |
| Houston |
54 |
12.22 |
| Chicago |
37 |
2.78 |
| Minneapolis |
31 |
-0.56 |
| Miami |
78 |
25.56 |
| Phoenix |
70 |
21.11 |
| Mean |
54.000 |
12.22 |
| Median |
54.000 |
12.22 |
| Variance |
330.00 |
18.166 |
| SD |
101.852 |
10.092 |
Recall that to tranform the degrees Fahrenheit to degrees Centigrade, we use the formula
C=0.55556F-17.7778
C
0.55556
F
17.7778
which means we multiply each temperature Fahrenheit by
0.555560.55556 and then subtract
17.77817.778. As you might have expected,
you multiply the mean temperature in Fahrenheit by 0.555560.55556
and then subtract 17.77817.778 to get the mean in
Centigrade. That is,
0.55556×54-17.7778=12.222
0.55556
54
17.7778
12.222
The same is true for the median. Note that this relationship holds even
if the mean and median are not identical as they are in
Table 1.
The formula for the standard deviation is just as simple: the standard
deviation of degrees Centigrade is equal to the standard deviation in degrees
Fahrenheit times 0.555560.55556. Since the variance
is the standard deviaton squared, the variance in degrees Centigrade is equal
to 0.5555620.555562
times the variance of degrees Fahrenheit.
To sum up, if a variable XX has a mean of
mm, a standard deviation of ss,
and a variance of s2s2
then a new variable YY created using the linear transformation
Y=bX+A
Y
b
X
A
will have a mean of
bμ+A
b
μ
A
, a standard deviation of
bs
b
s
, and a variance of
b2s2
b
2
s
2
.