The basis of probability theory is a set of events - sample
space - and a systematic set of numbers - probabilities -
assigned to each event. The key aspect of the theory is the
system of assigning probabilities. Formally, a sample
space is the set ΩΩ
of all possible outcomes
ω i
ω i
of an experiment. An event is a collection of
sample points ω
i ω
i determined by some
set-algebraic rules governed by the laws of Boolean algebra.
Letting AA and
BB denote events, these laws are
Union:
A⋃B={ω|ω∈A∨ω∈B}
Union:
A
B
ω
ω
A
ω
B
Intersection:
A⋂B={ω|ω∈A∧ω∈B}
Intersection:
A
B
ω
ω
A
ω
B
Complement:
A′={ω|ω∉A}
Complement:
A
ω
ω
A
A⋃B′=A′⋂B′
A
B
A
B
The null set ∅ is the complement
of ΩΩ. Events are said to
be mutually exclusive if there is no element
common to both events:
A⋂B=∅
A
B
.
Associated with each event
A
i
A
i
is a
probability measure
Pr
A
i
A
i
, sometimes denoted by
π
i
π
i
, that obeys the
axioms of probability.
-
Pr
A
i
≥0
A
i
0
-
PrΩ=1
Ω
1
- If
A⋂B=∅
A
B
, then
PrA⋃B=PrA+PrB
A
B
A
B
.
The consistent set of probabilities
Pr·
·
assigned to events are known as the
a
priori probabilities. From the axioms,
probability assignments for Boolean expressions can be
computed. For example, simple Boolean manipulations (
A⋃B=A⋃A′B
A
B
A
A
B
) lead to
PrA⋃B=PrA+PrB-PrA⋂B
A
B
A
B
A
B
(1)
Suppose
PrB≠0
B
0
. Suppose we know that the event
BB has occurred; what is the
probability that event
AA has
also occurred? This calculation is known as the
conditional probability of
AA given
BB and is denoted by
PrA|B
B
A
. To evaluate conditional probabilities, consider
BB to be the sample space rather
than
ΩΩ. To obtain a
probability assignment under these circumstances consistent
with the axioms of probability, we must have
PrA|B=PrA⋂BPrB
B
A
A
B
B
(2)
The event is said to be
statistically independent
of
BB if
PrA|B=PrA
B
A
A
: the occurrence of the event
BB does not change the
probability that
AA occurred.
When independent, the probability of their intersection
PrA⋂B
A
B
is given by the product of the
a
priori probabilities
PrAPrB
A
B
. This property is necessary and sufficient for the
independence of the two events. As
PrA|B=PrA⋂BPrB
B
A
A
B
B
and
PrB|A=PrA⋂BPrA
A
B
A
B
A
, we obtain
Bayes' Rule.
PrB|A=PrA|BPrBPrA
A
B
B
A
B
A
(3)