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Non-overlapping Received Signals

Module by: Don Johnson

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If we restrict to observing rt r t over 0T 0 T , the minimum P e P e receiver computes N 0 2ln π i +<si*,r>si*22 N 0 2 π i s i * r s i * 2 2 and chooses the largest. Here, <si*,r>=0T s i * trtdt s i * r t 0 T s i * t r t si*2=0T s i * 2tdt s i * 2 t 0 T s i * t 2 When we have a binary signal set, the probability of error is given by P e =Qs0*s1*2 N 0 P e Q s 0 * s 1 * 2 N 0

One question of interest is what the "best" signal set at the transmitter to use to maximize the performance. We want to find the s i t s i t that maximizes s0*s1*2 s 0 * s 1 * 2 for a given channel model. As usual, we constrain the transmitter signal energies by si2E s i 2 E . Now s0*s1*2=0T s 0 * 2t2 s 0 * t s 1 * t+ s 1 * 2tdt s 0 * s 1 * 2 t 0 T s 0 * t 2 2 s 0 * t s 1 * t s 1 * t 2 As s i * = s i * h CH s i * s i h CH , we have s i * t s j * tdt= h CH tα s i αdα h CH tβ s j βdβdt t s i * t s j * t t α h CH t α s i α β h CH t β s j β Interchanging the order of integration, this integral can be written as h CH tα h CH tβdt s i α s j βdαdβ β α t h CH t α h CH t β s i α s j β Defining the innermost integral as Q CH αβ Q CH α β , we can write the squared distance between the received signals as

s0*s1*2= Q CH αβ s 0 α s 0 β s 0 α s 1 β s 0 β s 1 α+ s 1 α s 1 βdαdβ= Q CH αβ s 0 α s 1 α s 0 β s 1 βdαdβ=s0s1 Q CH 2 s 0 * s 1 * 2 β α Q CH α β s 0 α s 0 β s 0 α s 1 β s 0 β s 1 α s 1 α s 1 β β α Q CH α β s 0 α s 1 α s 0 β s 1 β Q CH s 0 s 1 2 (1)
where x Q CH Q CH x denotes the norm induced by Q CH αβ Q CH α β . x Q CH 2= Q CH αβxαxβdαdβ Q CH x 2 β α Q CH α β x α x β This quantity is a valid inner product because Q CH αβ Q CH α β is a positive-definite, symmetric function of αα and ββ. The relevant inner product can be written as s0s1 Q CH 2= s 0 Q CH 22< Q CH , s 0 >+ s 1 Q CH 2 Q CH s 0 s 1 2 Q CH s 0 2 2 Q CH s 0 s 1 Q CH s 1 2 Therefore, if we require s 0 Q CH 2= s 1 Q CH 2 Q CH s 0 2 Q CH s 1 2 , the maximum value of this norm occurs when < Q CH , s 0 >=- s 1 Q CH 2 Q CH s 0 s 1 Q CH s 1 2 . In other words, s 0 =- s 1 s 0 s 1 . Consequently, antipodal signals still have the best performance. Because of the weighting function Q CH ·· Q CH · · in the inner product, certain signals are better than others. We seek to find those signals. According to Mercer's theorem, Q CH αβ Q CH α β may be represented in an orthogonal expansion. Q CH αβ=j=1 λ j φ j α φ j β Q CH α β j 1 λ j φ j α φ j β where φ j t φ j t and λ j λ j are the eigenfunctions and eigenvalues of Q CH αβ Q CH α β . As s 0 t=j=1 s 0 j φ j t s 0 t j 1 s 0 j φ j t , the squared norm of a signal can be written s 0 Q CH 2= Q CH αβ s 0 α s 0 βdαdβ=j=1 λ j s 0 j 2 Q CH s 0 2 β α Q CH α β s 0 α s 0 β j 1 λ j s 0 j 2 When we have an antipodal signal set, s0s1 Q CH 2=4 λ j s 0 j 2 Q CH s 0 s 1 2 4 λ j s 0 j 2 . To constrain the energy of s 0 t s 0 t means that s 0 j 2 E 0 s 0 j 2 E 0 . If h CH tτ=δtτ h CH t τ δ t τ , Q CH αβ=δαβ λ j =1 Q CH α β δ α β λ j 1 for all jj. Consequently, the distance with respect to Q CH αβ Q CH α β is maximized for any signal having energy E 0 E 0 . On the other hand, if the λ j λ j are not identical, the values of the representation s 0 j s 0 j affect the distance. To maximize this distance, set s 0 j =0 s 0 j 0 except for that component corresponding to the largest eigenvalue λ max λ max . Best results are obtained, therefore, when s 0 t=E φ m t s 0 t E φ m t , where λ max =maxj{ λ j } λ max j λ j . In this case, s0s1 Q CH 2=4 λ max E Q CH s 0 s 1 2 4 λ max E . With this optimum signal selection, P e =Q2 λ max E N 0 P e Q 2 λ max E N 0

Example 1

Consider a multipath channel that has the impulse response h CH tτ=δtτ+aδtτΔ h CH t τ δ t τ a δ t τ Δ where ΔΔ is the delay in the multipath and aa is the gain (usually less than one). The kernal Q CH αβ Q CH α β becomes in this case Q CH αβ=1+a2δαβ+aδαβΔ+aδαβ+Δ Q CH α β 1 a 2 δ α β a δ α β Δ a δ α β Δ The eigenfunctions of this kernal are determined by the equation λφt=1+a2φt+aφtΔ+aφt+Δ λ φ t 1 a 2 φ t a φ t Δ a φ t Δ The solutions of this equation are sinusoids having frequencies harmonically related to ΔΔ. φ k t=Asin2πkΔt+Bcos2πkΔt φ k t A 2 k Δ t B 2 k Δ t λ k =1+a2 λ k 1 a 2 In principal, any signal represented by a Fourier series having a period of ΔΔ would yield the smallest probability of error over this multipath channel.

When this solution is considered in detail, no time-limited solution to the eigenequation exists. Thus, this analysis does not yield a realistic signal set for transmitting digital information over a multipath channel. However, this result does suggest that a time-limited version of this signal set would result in a receiver insensitive to the multipath. Consider the antipodal signal set s 0 t=ETΔif0t<TΔ0ifTΔt<T s 0 t E T Δ 0 t T Δ 0 T Δ t T s 1 t=- s 0 t s 1 t s 0 t The signal s 0 * t s 0 * t is given by s 0 * t=ETΔif0t<Δ1+aETΔifΔt<TΔaETΔifTΔt<T s 0 * t E T Δ 0 t Δ 1 a E T Δ Δ t T Δ a E T Δ T Δ t T The probability of error obtained when a receiver uses this signal in its matched filter is P e =Q2E N 0 1+a22aΔTΔ P e Q 2 E N 0 1 a 2 2 a Δ T Δ The probability of error of the optimum (unobtainable) receiver is given by P e =Q21+a2E N 0 P e Q 2 1 a 2 E N 0 Thus, the suboptimum receiver can perform almost as well as the optimum one under certain conditions (i.e., ΔΔ small compared to TΔ T Δ ).

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