A second, and some people think more accurate, way to find
VT
VT
is to look at the characteristics of
the MOS transistor in is linear regime. The test
circuit looks like what you see in Figure 1. In
this case, Vds
Vds
is kept quite small (0.2 Volts or so)
and the gate voltage
Vgs
Vgs
is swept over some range. If you look
back at equation in another module, which we can slightly re-write we see
that
I
d
=
μ
s
c
ox
W
V
ds
L
V
gs
-
V
T
I
d
μ
s
c
ox
W
V
ds
L
V
gs
V
T
(1)
This equation will obviously give us a linear plot of
Id
Id
as a function of
Vgs
Vgs
, which will look something like
Figure 2. Obviously, this is a device with
a threshold voltage of about 2 volts. Can you figure out what
kk is for this transistor? If not,
go back a re-read some stuff.
Now let's address a fundamental question concerning all of this:
So What? What do we have here? One answer is that we have
another device which in some way looks like the bipolar
transistor we studied in the last chapter. In the saturation
regime, the device looks and acts like a current source, and
could probably be used as an amplifier. It is pretty easy to
make a small signal model. The drain acts like a current source,
which is controlled by
Vgs
Vgs
. What should we do about the gate
terminal? The gate really is not connected to anything inside
the transistor, so it looks just like an open circuit. (In fact,
there is a capacitance
C
gate
=
c
ox
A
gate
C
gate
c
ox
A
gate
, where
A
gate
=WL
A
gate
W
L
, the area of the gate, but in most low frequency
linear applications, this capacitance is not significant.) Thus
our small signal model for the MOSFET, if it is operating in it
saturation mode, is as seen in Figure 3.
This seems to be a pretty good amplifier. It has infinite input
impedance (and hence will not load down the previous stage of
the amplifier) and it has a nice (but non-linear) voltage
controlled current source for its output. A figure in the section
on MOS regimes shows that as
Vds
Vds
is increased, the channel length
does, in fact, get a bit shorter. The
increased Vds
Vds
makes the pinch off
region expand a bit, which, of course, robs from the channel
region. A shorter channel means slightly less channel
resistance, and so
Id
Id
actually
increases a bit with increasing
Vds
Vds
instead of staying constant. We saw
from the bipolar transistor, that when this occurs, we must add
a resistor in parallel with our current source. Thus, let's
complete the model with an additional
ro
ro
but in fact, we will put it in with a
dashed line, because except for very short channel devices, it
has very little effect on device performance (Figure 4).
The MOSFET has several advantages over the bipolar
transistor. One of the main ones, as we shall see, is that it is much
easier to make. You only need two n-regions in a single p-type
substrate. It is basically a surface device. This means you do not
have to pile up different layers of n and p type material as you do
with the bipolar transistor. Finally, we shall see that a variation on
the MOSFET technology offers a huge advantage
over bipolar devices when it comes to building logic circuits with a
large number of gates (VLSI and ULSI circuits).
To see why this is so, we have to digress for just a little bit,
and discuss logic circuits.