As you are probably aware, you have to be very careful when
handling MOS circuits, to be sure that you are properly
grounded, and that you do not transfer any static electricity to
the chip. The standard human-body model assumes a
static charge transfer of about 0.1 micro-Coulombs (
10-7C
10
-7
C
) upon static
electricity discharge between a human and a chip. This does not seem
like enough charge to do any harm until we remember the old formula:
Q=CV
Q
C
V
(1)
or
V=QC
V
Q
C
(2)
Last time I looked
10-7
10
-7
divided by
10-14
10
-14
is about
107
10
7
volts! Add to this the fact that the
gate oxide thickness is only about
10-6cm
10
-6
cm
, so that we have
electric fields in the gate oxide which are on the order of
1013Vcm
10
13
V
cm
! No wonder the things break. This problem is called
electrostatic discharge, or ESD, and is one
of the major concerns of IC manufacturers. Protecting against
ESD is still very much a "black art" and is something
that people are still studying quite a bit. JFET's are much more
rugged structures, and have much higher gate capacitances, and
are not nearly so prone to ESD failure.
Since we are on the subject of problems, lets take a look at one
more "glitch" that plagues IC designers. We have to go back to
the CMOS circuit. Remember, the moat/substrate junction is
reverse biased, so we will have an electric field in the
depletion region of that junction, pointing as shown in Figure 1. Suppose, somehow, we have one or more stray
electrons in the p-type substrate. They will be swept across the
substrate/moat junction by the electric field, and be attracted
to the moat contact by
Vdd
Vdd
. Let's focus on what happens as the electron
flows out the VDD
VDD
contact (Figure 2). As the
electron moves through the (resistive) n-type moat material, it
develops a voltage drop between the n-type material under the
source, and the VDD
VDD
contact (Which is also at the source
potential since they are connected together by the interconnect
on the surface of the wafer.) Electron flow in one direction
means current flow in the other and so this makes the region
under the source slightly negative with respect to the source
region itself. This, of course, forward biases the source/moat
junction slightly, which causes a hole or two to be injected
into the moat from the p-source (Figure 3). The
holes will be attracted by the field across the moat-substrate
depletion layer, and, once they get there, they will be swept
into the p-substrate (Figure 4). Once the holes
get into the p-substrate, they will be attracted to the ground
connection so that they can leave the semiconductor. As these
holes flow past the n-source, and through the resistive
p-substrate, they build up a potential between the ground
contact (Figure 5), and the material under the
source with a polarity which tends to forward bias the
source-substrate junction, and cause electrons to be injected
into the substrate. The electrons, in turn, are attracted to the
field across the substrate-moat junction (Figure 6). Some of the electrons may recombine in the
p-region, but in today's high-quality substrates, there are very
few active recombination centers, and so even though the
electrons are minority carriers, they have quite a long minority
carrier lifetime, and most of them make it to the substrate-moat
junction.and are swept into the moat. Once inside the n-moat,
the electrons are then attracted to the +
VddVdd
contact, where, of course, they build up a bigger forward bias
across the source-moat junction, causing more holes to be
emitted from the source into the moat (Figure 7). These holes are swept across the
moat-substrate junction, flow to the ground contact and, well
... you get the idea! It does not take long before we have a
dead short circuit between Vdd and ground. This is not healthy
for integrated circuit chips in the least, and is a process
called latch up (Figure 8).
There is an interesting circuit you can draw which shows what is
happening from a somewhat different point of view. Note that we
can consider the p-source, n-moat, and p-substrate as a pnp
bipolar transistor. Also the n-source, p-substrate and n-moat
also make a fine npn bipolar transistor. The two transistors are
intermingled however, with the base of the pnp and the
collectors of the npn sharing the same n-moat, and the collector
of the pnp and the base of the npn sharing the p-substrate. The
n-moat and p-substrates are both collectors
and bases at the same time. A little
careful inspection of the cross section of the CMOS inverter
will lead you to the following schematic shown in Figure 9. We need something to get this circuit started,
so say we have a little collector current coming out of the top
pnp transistor. This current flows down, through the resistor to
ground. As it flows through the resistor it builds up a little
voltage which forward biases the base-emitter junction of the
lower, npn, transistor, and causes some collector current to
flow into it. This current comes from
VddVdd
through the upper resistor, and builds up a voltage across that
resistor which will forward bias the base-emitter junction of
the top, pnp, transistor. This, in turn, causes some additional
collector current to flow out of the pnp transistor, and away we
go! Latch-up is bad, and is something which IC designers work
very hard to avoid.
You might wonder what actually starts a
circuit going into latch-up. Refer back to the CMOS inverter, and note
that the n-drain on the NMOS is connected to the output. The
output could be a real output, going beyond
the chip into the "real world". If the "customer" who is using
the chip is careless, and somehow drags the output down below
ground, the drain/p-substrate junction will be forward biased,
electrons will be injected into the p-substrate, and we are back
at Figure 1. IC designers try to keep the n-moat/
VddVdd
contact as close to the PMOS source, and the p-substrate/ground
contact as close to the NMOS source as they can to reduce the
resistance between the contact and the source regions, and hence
lower the chance of the circuit going into latch-up.