We will focus on linear operators in 301.
- Definition 1: linear
An operator
OO is
linear if
We can combine requirements 2
and 3 into:
O
γ
1
x1+
γ
2
x2=
γ
1
Ox1+
γ
2
Ox2
O
γ
1
x
1
γ
2
x
2
γ
1
O
x
1
γ
2
O
x
2
(1)
Figure 6 is equivalent to
Figure 7.
Check for
linearity/nonlinearity.
All matrix multiply operators
are linear.
y=Ax
y
A
x
(2)
where
x∈ℂN
x
N
,
y∈ℂN
y
N
, and
A
A is
N×N
N
N
(
Figure 8).
Verify the 3 conditions for
y=∑k=0N−1akxk
y
k
0
N
1
a
k
x
k
(3)
where
ak
a
k
are the columns of matrix
AA,
A=a0a1…a
N
-
1
A
a
0
a
1
…
a
N
-
1
.
- Let
x=0
x
0
, then all
xk=0
x
k
0
. This implies that
y=0
y
0
.
- Show
Ax1+x2=Ax1+Ax2
A
x
1
x
2
A
x
1
A
x
2
.
LHS=∑k=0N−1ak
x
1
k+
x
2
k=∑k=0N−1ak
x
1
k+∑k=0N−1ak
x
2
k=Ax1+Ax2=RHS
LHS
k
0
N
1
a
k
x
1
k
x
2
k
k
0
N
1
a
k
x
1
k
k
0
N
1
a
k
x
2
k
A
x
1
A
x
2
RHS
(4)
- Show
Aγx=γAx
A
γ
x
γ
A
x
LHS=∑k=0N−1akγxk=γ∑k=0N−1akxk=γAx=RHS
LHS
k
0
N
1
a
k
γ
x
k
γ
k
0
N
1
a
k
x
k
γ
A
x
RHS
(5)
Only matrix multiply operators
are linear.
Upshot of Facts 1 and
2: The Study of linear operators in
ℂN
ℂ
N
is equivalent to the study
N×N
N
N
matrices.