Skip to content Skip to navigation

Connexions

You are here: Home » Content » Design Decisions for Audio Localization Implementation

Navigation

Recently Viewed

This feature requires Javascript to be enabled.

Design Decisions for Audio Localization Implementation

Module by: Elizabeth Gregory, Joseph Cole. E-mail the authors

User rating (How does the rating system work?)
Ratings

Ratings allow you to judge the quality of modules. If other users have ranked the module then its average rating is displayed below. Ratings are calculated on a scale from one star (Poor) to five stars (Excellent).

How to rate a module

Hover over the star that corresponds to the rating you wish to assign. Click on the star to add your rating. Your rating should be based on the quality of the content. You must have an account and be logged in to rate content.

:
(0 ratings)

Summary: In this section, we will go over the design decisions we had to make in the course of our project, including determining how many microphones we should use, as well as the spacing of the array.

Note: Your browser may not currently support MathML. See our browser support page for additional details. You can always view the correct math in the PDF version.

With the theory out of the way, we have to face the real world and set more constraints.

The Number of Microphones

In this project, we are using the TI TMS320C6211 DSK board. This board has two channels that sample at 48 kHz and another channel that samples at 8 kHz. Since we are not interpolating our signals, the sampling frequency is increasingly critical, so we can only use two microphones. Figure 1 shows what happens to the beampattern when we use reduced sampling frequency.

Figure 1
Beampattern with Reduced Sampling Frequency
Beampattern with Reduced Sampling Frequency (figure9.jpg)

Array Spacing

In order to find the best array spacing (theoretically), we have to go through a few calculations. In our most extreme case, the signals will be hitting our array from 180°. This gives us perfect destructive interference, as our phase difference will be π. Therefore, we only need half of the wavelength:

d=λ2 d λ 2 (1)
We can find λ by dividing the frequency of our sine wave (500 Hz) by the speed of sound (346.287 m/s):
λ=cf=346.287500=0.69 λ c f 346.287 500 0.69 (2)
and our array spacing dd ends up being 0.345 m.

Content actions

Give Feedback:

E-mail the module authors | Rate module ( How does the rating system work?)

Rating system

Ratings

Ratings allow you to judge the quality of modules. If other users have ranked the module then its average rating is displayed below. Ratings are calculated on a scale from one star (Poor) to five stars (Excellent).

How to rate a module

Hover over the star that corresponds to the rating you wish to assign. Click on the star to add your rating. Your rating should be based on the quality of the content. You must have an account and be logged in to rate content.

(0 ratings)

Download:

Add module to:

My Favorites (?)

'My Favorites' is a special kind of lens which you can use to bookmark modules and collections directly in Connexions. 'My Favorites' can only be seen by you, and collections saved in 'My Favorites' can remember the last module you were on. You need a Connexions account to use 'My Favorites'.

| A lens (?)

Definition of a lens

Lenses

A lens is a custom view of Connexions content. You can think of it as a fancy kind of list that will let you see Connexions through the eyes of organizations and people you trust.

What is in a lens?

Lens makers point to Connexions materials (modules and collections), creating a guide that includes their own comments and descriptive tags about the content.

Who can create a lens?

Any individual Connexions member, a community, or a respected organization.

What are tags? tag icon

Tags are descriptors added by lens makers to help label content, attaching a vocabulary that is meaningful in the context of the lens.

| External bookmarks