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<!DOCTYPE document PUBLIC "-//CNX//DTD CNXML 0.5 plus MathML//EN" "http://cnx.rice.edu/cnxml/0.5/DTD/cnxml_mathml.dtd">
<document xmlns="http://cnx.rice.edu/cnxml" xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="None">
  <name>Acid-Base Equilibrium</name>
  <metadata>
  <md:version>1.1</md:version>
  <md:created>2005/01/10 17:07:11 US/Central</md:created>
  <md:revised>2005/01/13 21:15:25.467 US/Central</md:revised>
  <md:authorlist>
      <md:author id="jshutch">
      <md:firstname>John</md:firstname>
      <md:othername>Steven</md:othername>
      <md:surname>Hutchinson</md:surname>
      <md:email>jshutch@rice.edu</md:email>
    </md:author>
  </md:authorlist>

  <md:maintainerlist>
    <md:maintainer id="jshutch">
      <md:firstname>John</md:firstname>
      <md:othername>Steven</md:othername>
      <md:surname>Hutchinson</md:surname>
      <md:email>jshutch@rice.edu</md:email>
    </md:maintainer>
    <md:maintainer id="jsilv">
      <md:firstname>Jeffrey</md:firstname>
      
      <md:surname>Silverman</md:surname>
      <md:email>jsilv@rice.edu</md:email>
    </md:maintainer>
  </md:maintainerlist>
  
  <md:keywordlist>
    <md:keyword>acid ionization equilibrium constant</md:keyword>
    <md:keyword>autoionization</md:keyword>
    <md:keyword>binary acids</md:keyword>
    <md:keyword>carboxylic acids</md:keyword>
    <md:keyword>equilibrium</md:keyword>
    <md:keyword>hydrolysis</md:keyword>
    <md:keyword>Le Chatelier's Principle</md:keyword>
    <md:keyword>Le Châtelier's Principle</md:keyword>
    <md:keyword>oxyacids</md:keyword>
  </md:keywordlist>

  <md:abstract/>
</metadata>

  <content>
<section id="id3924661">
<name>Foundation</name>
<para id="id4534070">We have developed an understanding of 
<term>equilibrium</term> involving phase transitions and involving
reactions entirely in the gas phase. We will assume an
understanding of the principles of dynamic equilibrium, reaction
equilibrium constants, and 
<term>Le Châtelier's Principle</term>. To understand
application of these principles to reactions in solution, we will
now assume a definition of certain classes of substances as being
either acids or bases. An acid is a substance whose molecules
donate positive hydrogen ions (protons) to other molecules or ions.
When dissolved in pure water, acid molecules will transfer a
hydrogen ion to a water molecule or to a cluster of several water
molecules. This increases the concentration of
<m:math><m:msup><m:mi>H</m:mi><m:mo>+</m:mo></m:msup></m:math>
ions in the solution. A base is a substance whose molecules accept
hydrogen ions from other molecules. When dissolved in pure water,
base molecules will accept a hydrogen ion from a water molecule,
leaving behind an increased concentration of
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ions in the solution. To understand what determines acid-base
behavior, we will assume an understanding of the bonding,
structure, and properties of individual molecules.</para>
</section>
<section id="id4559135">
<name>Goals</name>
<para id="id4559142">Acids and bases are very common substances
whose properties vary greatly. Many acids are known to be quite
corrosive, with the ability to dissolve solid metals or burn flesh.
Many other acids, however, are not only benign but vital to the
processes of life. Far from destroying biological molecules, they
carry out reactions critical for organisms. Similarly, many bases
are caustic cleansers while many others are medications to calm
indigestion pains.</para>
<para id="id4562806">In this concept study, we will develop an
understanding of the characteristics of molecules which make them
either acids or bases. We will examine measurements about the
relative strengths of acids and bases, and we will use these to
develop a quantitative understanding of the relative strengths of
acids and bases. From this, we can develop a qualitative
understanding of the properties of molecules which determine
whether a molecule is a strong acid or a weak acid, a strong base
or a weak base. This understanding is valuable in predicting the
outcomes of reactions, based on the relative quantitative strengths
of acids and bases. These reactions are commonly referred to as
neutralization reactions. A surprisingly large number of reactions,
particularly in organic chemistry, can be understood as transfer of
hydrogen ions from acid molecules to base molecules.</para>
</section>
<section id="id4349532">
<name>Observation 1: Strong Acids and Weak Acids</name>
<para id="id4349540">From the definition of an acid given in the
Foundation, a typical acid can be written as
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>,
representing the hydrogen ion which will be donated and the rest of
the molecule which will remain as a negative ion after the
donation. The typical reaction of an acid in aqueous solution
reacting with water can be written as</para>
<equation id="eqn1"><m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>→</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math></equation>
<para id="id4425222">In this reaction,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>
represents an acid molecule dissolved in aqueous solution.
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>
is a notation to indicate that the donated proton has been
dissolved in solution. Observations indicate that the proton is
associated with several water molecules in a cluster, rather than
attached to a single molecule.
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math> is
a simplified notation to represent this result. Similarly, the
<m:math><m:mrow><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>
ion is solvated by several water molecules. <cnxn target="eqn1"/> is referred to as 
<term>acid ionization</term>.</para>
<para id="id6504439"><cnxn target="eqn1"/>
implies that a 0.1M solution of the acid
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>
in water should produce
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>
ions in solution with a concentration of 0.1M. In fact, the
concentration of
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>
ions,
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>,
can be measured by a variety of techniques. Chemists commonly use a
measure of the
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>
ion concentration called the
<m:math><m:ci>pH</m:ci></m:math>, defined
by:</para>
<para id="id6516568"><m:math display="block"><m:apply><m:eq/><m:ci>pH</m:ci><m:apply><m:minus/><m:apply><m:log/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply></m:apply></m:apply></m:math></para>
<para id="id6516573">We now observe the concentration
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
produced by dissolving a variety of acids in solution at a
concentration of 0.1M, and the results are tabulated in <cnxn target="table1"/>.</para>

<table id="table1">
<name>H3O+ pH for 0.1M Acid Solutions</name>
<tgroup cols="3">
<thead>
<row>
<entry>Acid</entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
(M)</entry>
<entry>pH</entry>
</row>
</thead>
<tbody>
<row>
<entry>
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>S</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Br</m:mi></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math></entry>
<entry>0.1</entry>
<entry>1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">6.2<m:sep/>-3</m:cn></m:math></entry>
<entry>2.2</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">7<m:sep/>-6</m:cn></m:math></entry>
<entry>5.1</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi><m:mi>O</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">1<m:sep/>-6</m:cn></m:math></entry>
<entry>5.8</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">5.5<m:sep/>-3</m:cn></m:math></entry>
<entry>2.3</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">5.5<m:sep/>-3</m:cn></m:math></entry>
<entry>2.3</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.8<m:sep/>-2</m:cn></m:math></entry>
<entry>1.6</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(acetic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-3</m:cn></m:math></entry>
<entry>2.9</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(propionic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.1<m:sep/>-3</m:cn></m:math></entry>
<entry>2.9</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id4277459">Note that there are several acids listed for
which
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn>0.1</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>,
and
<m:math><m:apply><m:eq/><m:ci>pH</m:ci><m:cn>1</m:cn></m:apply></m:math>.
This shows that, for these acids, the acid ionization is complete:
essentially every acid molecule is ionized in the solution
according to <cnxn target="eqn1"/>. However,
there are other acids listed for which
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
is considerably less than 0.1M and the pH is considerably greater
than 1. For each of these acids, therefore, not all of the acid
molecules ionize according to <cnxn target="eqn1"/>. In fact, it is clear in <cnxn target="table1"/> that in these acids the vast
majority of the acid molecules do not ionize, and only a small
percentage does ionize.</para>
<para id="id4308791">From these observations, we distinguish two
classes of acids: 
<term>strong acids</term> and 
<term>weak acids</term>. Strong acids are those for which nearly
100% of the acid molecules ionize, whereas weak acids are those for
which only a small percentage of molecules ionize. There are seven
strong acids listed in <cnxn target="table1"/>.
From many observations, it is possible to determine that these
seven acids are the only commonly observed strong acids. The vast
majority of all substances with acidic properties are weak acids.
We seek to characterize weak acid ionization quantitatively and to
determine what the differences in molecular properties are between
strong acids and weak acids.</para>
</section>
<section id="id6197875">
<name>Observation 2: Percent Ionization in Weak Acids</name>
<para id="id4934568"><cnxn target="table1"/>
shows that the pH of 0.1M acid solutions varies from one weak acid
to another. If we dissolve 0.1 moles of acid in a 1.0L solution,
the fraction of those acid molecules which will ionize varies from
weak acid to weak acid. For a few weak acids, using the data in
<cnxn target="table1"/> we calculate the
percentage of ionized acid molecules in 0.1M acid solutions in
<cnxn target="table2"/>.</para>

<table id="table2">
<name>Percent Ionization of 0.1M Acid Solutions</name>
<tgroup cols="3">
<thead>
<row>
<entry>Acid</entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
(M)</entry>
<entry>% ionization</entry>
</row>
</thead>
<tbody>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">6.2<m:sep/>-3</m:cn></m:math></entry>
<entry>6.2%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">7<m:sep/>-6</m:cn></m:math></entry>
<entry>0.007%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi><m:mi>O</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">1<m:sep/>-6</m:cn></m:math></entry>
<entry>0.001%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">5.5<m:sep/>-3</m:cn></m:math></entry>
<entry>5.5%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">5.5<m:sep/>-3</m:cn></m:math></entry>
<entry>5.5%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.8<m:sep/>-2</m:cn></m:math></entry>
<entry>28.2%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(acetic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-3</m:cn></m:math></entry>
<entry>1.3%</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(propionic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.1<m:sep/>-3</m:cn></m:math></entry>
<entry>1.1%</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id6652712">We might be tempted to conclude from <cnxn target="table2"/> that we can characterize the
strength of each acid by the percent ionization of acid molecules
in solution. However, before doing so, we observe the pH of a
single acid, nitrous acid, in solution as a function of the
concentration of the acid.</para>
<equation id="eqn2"><m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>→</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>2</m:mn><m:mo>-</m:mo></m:msubsup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math></equation>
<para id="id4154468">In this case, "concentration of the
acid" refers to the number of moles of acid that we dissolved
per liter of water. Our observations are listed in <cnxn target="table3"/>, which gives
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>,
pH, and percent ionization as a function of nitrous acid
concentration.</para>

<table id="table3">
<name>% Ionization of Nitrous Acid</name>
<tgroup cols="4">
<thead>
<row>
<entry>
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>
(M)</entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math></entry>
<entry>pH</entry>
<entry>% Ionization</entry>
</row>
</thead>
<tbody>
<row>
<entry>0.50</entry>
<entry><m:math><m:cn type="e-notation">1.7<m:sep/>-2</m:cn></m:math></entry>
<entry>1.8</entry>
<entry>3.3%</entry>
</row>
<row>
<entry>0.20</entry>
<entry><m:math><m:cn type="e-notation">1.0<m:sep/>-2</m:cn></m:math></entry>
<entry>2.0</entry>
<entry>5.1%</entry>
</row>
<row>
<entry>0.10</entry>
<entry><m:math><m:cn type="e-notation">7.0<m:sep/>-3</m:cn></m:math></entry>
<entry>2.2</entry>
<entry>7.0%</entry>
</row>
<row>
<entry>0.050</entry>
<entry><m:math><m:cn type="e-notation">4.8<m:sep/>-3</m:cn></m:math></entry>
<entry>2.3</entry>
<entry>9.7%</entry>
</row>
<row>
<entry>0.020</entry>
<entry><m:math><m:cn type="e-notation">2.9<m:sep/>-3</m:cn></m:math></entry>
<entry>2.5</entry>
<entry>14.7%</entry>
</row>
<row>
<entry>0.010</entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-3</m:cn></m:math></entry>
<entry>2.7</entry>
<entry>20.0%</entry>
</row>
<row>
<entry>0.005</entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-3</m:cn></m:math></entry>
<entry>2.9</entry>
<entry>26.7%</entry>
</row>
<row>
<entry>0.001</entry>
<entry><m:math><m:cn type="e-notation">4.9<m:sep/>-4</m:cn></m:math></entry>
<entry>3.3</entry>
<entry>49.1%</entry>
</row>
<row>
<entry>0.0005</entry>
<entry><m:math><m:cn type="e-notation">3.0<m:sep/>-4</m:cn></m:math></entry>
<entry>3.5</entry>
<entry>60.8%</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id6647456">Surprisingly, perhaps, the percent ionization
varies considerably as a function of the concentration of the
nitrous acid. We recall that this means that the fraction of
molecules which ionize, according to <cnxn target="eqn2"/>, depends on how many acid molecules
there are per liter of solution. Since some but not all of the acid
molecules are ionized, this means that nitrous acid molecules are
present in solution at the same time as the negative nitrite ions
and the positive hydrogen ions. Recalling our observation of
equilibrium in gas phase reactions, we can conclude that <cnxn target="eqn2"/> achieves equilibrium for each
concentration of the nitrous acid.</para>
<para id="id6647470">Since we know that gas phase reactions come to
equilibrium under conditions determined by the equilibrium
constant, we might speculate that the same is true of reactions in
aqueous solution, including acid ionization. We therefore define an
analogy to the gas phase reaction equilibrium constant. In this
case, we would not be interested in the pressures of the
components, since the reactants and products are all in solution.
Instead, we try a function composed of the equilibrium
concentrations:</para>

<equation id="eqn3">
<m:math><m:apply><m:eq/>
<m:ci>K</m:ci>
<m:apply><m:divide/>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>2</m:mn><m:mo>-</m:mo></m:msubsup><m:mo>]</m:mo></m:mrow></m:ci></m:apply>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci>&gt;<m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply></m:apply></m:apply>
</m:math>
</equation>

<para id="id4949521">The concentrations at equilibrium can be
calculated from the data in <cnxn target="table3"/> for nitrous acid.
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
is listed and
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>2</m:mn><m:mo>-</m:mo></m:msubsup><m:mo>]</m:mo></m:mrow></m:ci><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply></m:math>.
Furthermore, if
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>
is the initial concentration of the acid defined by the number of
moles of acid dissolved in solution per liter of solution, then
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>A</m:mi><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:minus/><m:ci><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:ci><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply></m:apply></m:math>.
Note that the contribution of
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>]</m:mo></m:mrow></m:math>
to the value of the function <m:math><m:ci type="fn">K</m:ci></m:math> is simply a
constant. This is because the "concentration" of water
in the solution is simply the molar density of water,
<m:math><m:apply><m:eq/><m:apply><m:divide/><m:ci><m:msub><m:mi>n</m:mi><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi></m:mrow></m:msub></m:ci><m:ci>V</m:ci></m:apply><m:apply><m:times/><m:cn>55.5</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>,
which is not affected by the presence or absence of solute. All of
the relevant concentrations, along with the function in <cnxn target="eqn3"/> are calculated and tabulated in
<cnxn target="table4"/>.</para>

<table id="table4">
<name>Equilibrium Concentrations and K for Nitrous Acid</name>
<tgroup cols="5">
<thead>
<row>
<entry>
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>
(M)</entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math></entry>
<entry>
<m:math><m:mo>[</m:mo><m:mrow><m:mi>N</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>2</m:mn><m:mo>-</m:mo></m:msubsup><m:mo>]</m:mo></m:mrow></m:math></entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:math></entry>
<entry><m:math><m:ci type="fn">K</m:ci></m:math></entry>
</row>
</thead>
<tbody>
<row>
<entry>0.50</entry>
<entry><m:math><m:cn type="e-notation">1.7<m:sep/>-2</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.7<m:sep/>-2</m:cn></m:math></entry>
<entry>0.48</entry>
<entry><m:math><m:cn type="e-notation">1.0<m:sep/>-5</m:cn></m:math></entry>
</row>
<row>
<entry>0.20</entry>
<entry><m:math><m:cn type="e-notation">1.0<m:sep/>-2</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.0<m:sep/>-2</m:cn></m:math></entry>
<entry>0.19</entry>
<entry><m:math><m:cn type="e-notation">9.9<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.10</entry>
<entry><m:math><m:cn type="e-notation">7.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">7.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">9.3<m:sep/>-2</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">9.6<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.050</entry>
<entry><m:math><m:cn type="e-notation">4.8<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">4.8<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">4.5<m:sep/>-2</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">9.4<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.020</entry>
<entry><m:math><m:cn type="e-notation">2.9<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.9<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">4.5<m:sep/>-2</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">9.4<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.010</entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">8.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">8.9<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.005</entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">3.6<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">8.8<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.001</entry>
<entry><m:math><m:cn type="e-notation">4.9<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">4.9<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">5.1<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">8.5<m:sep/>-6</m:cn></m:math></entry>
</row>
<row>
<entry>0.0005</entry>
<entry><m:math><m:cn type="e-notation">3.0<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">3.0<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">8.5<m:sep/>-6</m:cn></m:math></entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id4422451">We note that the function
<m:math><m:ci type="fn">K</m:ci></m:math> in <cnxn target="eqn3"/> is approximately, though only
approximately, the same for all conditions analyzed in <cnxn target="table3"/>. Variation of the concentration by
a factor of 1000 produces a change in <m:math><m:ci type="fn">K</m:ci></m:math> of only 10%
to 15%. Hence, we can regard the function <m:math><m:ci type="fn">K</m:ci></m:math> as a
constant which approximately describes the acid ionization
equilibrium for nitrous acid. By convention, chemists omit the
constant concentration of water from the equilibrium expression,
resulting in the 
<term>acid ionization equilibrium constant</term>,
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>,
defined as:</para>

<equation id="eqn4">
<m:math><m:apply><m:eq/>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:ci>
<m:apply><m:divide/>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>2</m:mn><m:mo>-</m:mo></m:msubsup><m:mo>]</m:mo></m:mrow></m:ci></m:apply>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply></m:apply>
</m:math>
</equation>

<para id="id4175660">From an average of the data in <cnxn target="table4"/>, we can calculate that, at
25°C for nitrous acid,
<m:math><m:apply><m:eq/><m:ci><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:ci><m:cn type="e-notation">5<m:sep/>-4</m:cn></m:apply></m:math>.
Acid ionization constants for the other weak acids in <cnxn target="table2"/> are listed in <cnxn target="table5"/>.</para>

<table id="table5">
<name>Weak Acid Ionization Constants, Ka and pKa</name>
<tgroup cols="3">
<thead>
<row>
<entry>Acid</entry>
<entry>
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math></entry>
<entry>
p<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math></entry>
</row>
</thead>
<tbody>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">5<m:sep/>-4</m:cn></m:math></entry>
<entry>3.3</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">4.9<m:sep/>-10</m:cn></m:math></entry>
<entry>9.3</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi><m:mi>O</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.3<m:sep/>-11</m:cn></m:math></entry>
<entry>10.6</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">3.5<m:sep/>-4</m:cn></m:math></entry>
<entry>3.4</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>C</m:mi><m:mi>N</m:mi></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">3.5<m:sep/>-4</m:cn></m:math></entry>
<entry>3.4</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.1<m:sep/>-2</m:cn></m:math></entry>
<entry>2.0</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(acetic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.7<m:sep/>-5</m:cn></m:math></entry>
<entry>4.8</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
(propionic acid)</entry>
<entry><m:math><m:cn type="e-notation">1.4<m:sep/>-5</m:cn></m:math></entry>
<entry>4.9</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id6470677">We make two final notes about the results in
<cnxn target="table5"/>. First, it is clear the
larger the value of
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>,
the stronger the acid. That is, when
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>
is a larger number, the percent ionization of the acid is larger,
and vice versa. Second, the values of
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>
very over many orders of magnitude. As such, it is often convenient
to define the quanity
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>,
analogous to pH, for purposes of comparing acid strengths:</para>
<equation id="eqn5"><m:math><m:apply><m:eq/><m:ci><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:ci><m:apply><m:minus/><m:apply><m:log/><m:ci><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:ci></m:apply></m:apply></m:apply></m:math></equation>
<para id="id4326057">The value of
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>
for each acid is also listed in <cnxn target="table5"/>. Note that a small value of
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>
implies a large value of
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>
and thus a stronger acid. Weaker acids have larger values of
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>.
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>
and
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>
thus give a simple quantitative comparison of the strength of weak
acids.</para>
</section>
<section id="id4255485">
<name>Observation 3: Autoionization of Water</name>
<para id="id4325350">Since we have the ability to measure pH for
acid solutions, we can measure pH for pure water as well. It might
seem that this would make no sense, as we would expect
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
to equal zero exactly in pure water. Surprisingly, this is
incorrect: a measurement on pure water at 25°C yields
<m:math><m:apply><m:eq/><m:ci>pH</m:ci><m:cn>7</m:cn></m:apply></m:math>,
so that
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn type="e-notation">1.0<m:sep/>-7</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>.
There can be only one possible source for these ions: water
molecules. The process</para>
<equation id="eqn6"><m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>→</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup>
<m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math></equation>
<para id="id6539821">is referred to as the 
<term>autoionization</term> of water. Note that, in this reaction,
some water molecules behave as acid, donating protons, while other
acid molecules behave as base, accepting protons.</para>
<para id="id4196908">Since at equilibrium
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn type="e-notation">1.0<m:sep/>-7</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>,
it must also be true that
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn type="e-notation">1.0<m:sep/>-7</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>.
We can write the equilibrium constant for <cnxn target="eqn6"/>, following our previous convention
of omitting the pure water from the expression, and we find that,
at 25°C,</para>
<equation id="eqn7"><m:math><m:apply><m:eq/><m:ci><m:msub><m:mi>K</m:mi><m:mi>w</m:mi></m:msub></m:ci>
<m:apply><m:times/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply><m:apply><m:times/><m:cn type="e-notation">1.0<m:sep/>-14</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math></equation>
<para id="id4385688">(In this case, the subscript "w"
refers to "water".)</para>
<para id="id4547285"><cnxn target="eqn6"/> occurs
in pure water but must also occur when ions are dissolved in
aqueous solutions. This includes the presence of acids ionized in
solution. For example, we consider a solution of 0.1M acetic acid.
Measurements show that, in this solution
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn type="e-notation">1.3<m:sep/>-3</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>
and
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:apply><m:times/><m:cn type="e-notation">7.7<m:sep/>-12</m:cn><m:ci>M</m:ci></m:apply></m:apply></m:math>.
We note two things from this observation: first, the value of
<m:math><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
is considerably less than in pure water; second, the autoionization
equilibrium constant remains the same at <m:math><m:cn type="e-notation">1.0<m:sep/>-14</m:cn></m:math>.
From these notes, we can conclude that the autoionization
equilibrium of water occurs in acid solution, but the extent of
autoionization is suppressed by the presence of the acid in
solution.</para>
<para id="id4406060">We consider a final note on the autoionization
of water. The pH of pure water is 7 at 25°C. Adding any acid
to pure water, no matter how weak the acid, must increase
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>,
thus producing a pH below 7. As such, we can conclude that, for all
acid solutions, pH is less than 7, or on the other hand, any
solution with pH less than 7 is acidic.</para>
</section>
<section id="id4973082">
<name>Observation 4: Base Ionization, Neutralization and Hydrolysis
of Salts</name>
<para id="id4096773">We have not yet examined the behavior of base
molecules in solution, nor have we compared the relative strengths
of bases. We have defined a base molecule as one which accepts a
positive hydrogen ion from another molecule. One of the most common
examples is ammonia,
<m:math><m:mrow><m:mi>N</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>.
When ammonia is dissolved in aqueous solution, the following
reaction occurs:</para>
<equation id="eqn8"><m:math><m:mrow><m:mi>N</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo><m:mo>→</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>H</m:mi><m:mn>4</m:mn><m:mo>+</m:mo></m:msubsup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math></equation>
<para id="id4601020">Due to the lone pair of electrons on the
highly electronegative N atom,
<m:math><m:mrow><m:mi>N</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>
molecules will readily attach a free hydrogen ion forming the
ammonium ion
<m:math><m:mrow><m:mi>N</m:mi><m:msubsup><m:mi>H</m:mi><m:mn>4</m:mn><m:mo>+</m:mo></m:msubsup></m:mrow></m:math>.
When we measure the concentration of
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
for various initial concentration of
<m:math><m:mrow><m:mi>N</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>
in water, we observe the results in <cnxn target="table6"/>. We should anticipate that a base
ionization equilibrium constant might exist comparable to the acid
ionization equilibrium constant, and in <cnxn target="table6"/>, we have also calculated the value
of the function
<m:math><m:msub><m:mi>K</m:mi><m:mi>b</m:mi></m:msub></m:math>
defined as:</para>

<equation id="eqn9">
<m:math>
<m:apply><m:eq/>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>b</m:mi></m:msub></m:ci>
<m:apply><m:divide/>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>N</m:mi><m:msubsup><m:mi>H</m:mi><m:mn>4</m:mn><m:mo>+</m:mo></m:msubsup><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>N</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply></m:apply>
</m:math>
</equation>

<table id="table6">
<name>Equilibrium Concentrations and Kb for Ammonia</name>
<tgroup cols="4">
<thead>
<row>
<entry>
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>
(M)</entry>
<entry>
<m:math><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math></entry>
<entry><m:math><m:msub><m:mi>K</m:mi><m:mi>b</m:mi></m:msub></m:math></entry>
<entry>pH</entry>
</row>
</thead>
<tbody>
<row>
<entry>0.50</entry>
<entry><m:math><m:cn type="e-notation">3.2<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-5</m:cn></m:math></entry>
<entry>11.5</entry>
</row>
<row>
<entry>0.20</entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-5</m:cn></m:math></entry>
<entry>11.3</entry>
</row>
<row>
<entry>0.10</entry>
<entry><m:math><m:cn type="e-notation">1.4<m:sep/>-3</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">2.0<m:sep/>-5</m:cn></m:math></entry>
<entry>11.1</entry>
</row>
<row>
<entry>0.050</entry>
<entry><m:math><m:cn type="e-notation">9.7<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.9<m:sep/>-5</m:cn></m:math></entry>
<entry>11.0</entry>
</row>
<row>
<entry>0.020</entry>
<entry><m:math><m:cn type="e-notation">6.0<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.9<m:sep/>-5</m:cn></m:math></entry>
<entry>10.8</entry>
</row>
<row>
<entry>0.010</entry>
<entry><m:math><m:cn type="e-notation">4.2<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.9<m:sep/>-5</m:cn></m:math></entry>
<entry>10.6</entry>
</row>
<row>
<entry>0.005</entry>
<entry><m:math><m:cn type="e-notation">3.0<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.9<m:sep/>-5</m:cn></m:math></entry>
<entry>10.5</entry>
</row>
<row>
<entry>0.001</entry>
<entry><m:math><m:cn type="e-notation">1.3<m:sep/>-4</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.8<m:sep/>-5</m:cn></m:math></entry>
<entry>10.1</entry>
</row>
<row>
<entry>0.0005</entry>
<entry><m:math><m:cn type="e-notation">8.7<m:sep/>-5</m:cn></m:math></entry>
<entry><m:math><m:cn type="e-notation">1.8<m:sep/>-5</m:cn></m:math></entry>
<entry>9.9</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id4365763">Given that we have dissolved a base in pure
water, we might be surprised to discover the presence of positive
hydrogen ions,
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>,
in solution, but a measurement of the pH for each of the solutions
reveals small amounts. The pH for each solution is also listed in
<cnxn target="table6"/>. The source of these
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>
ions must be the autoionization of water. Note, however, that in
each case in basic solution, the concentration of
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup></m:mrow></m:math>
ions is less than that in pure water. Hence, the presence of the
base in solution has suppressed the autoionization. Because of
this, in each case the pH of a basic solution is greater than
7.</para>
<para id="id4977545">Base ionization is therefore quite analogous
to acid ionization observed earlier. We now consider a comparison
of the strength of an acid to the strength of a base. To do so, we
consider a class of reactions called "neutralization
reactions" which occur when we mix an acid solution with a
base solution. Since the acid donates protons and the base accepts
protons, we might expect, when mixing acid and base, to achieve a
solution which is no longer acidic or basic. For example, if we mix
together equal volumes of 0.1M
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>
and 0.1M
<m:math><m:mrow><m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>,
the following reaction occurs:</para>
<equation id="eqn10"><m:math><m:mrow>
<m:mi>H</m:mi><m:mi>Cl</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>→</m:mo>
<m:msup><m:mi>Na</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:msup><m:mi>Cl</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo>
</m:mrow></m:math></equation>
<para id="id6635619">The resultant solution is simply a salt
solution with
<m:math><m:mrow><m:mi>Na</m:mi><m:ci>Cl</m:ci></m:mrow></m:math>
dissolved in water. This solution has neither acidic nor basic
properties, and the pH is 7; hence the acid and base have
neutralized each other. In this case, we have mixed together a
strong acid with a strong base. Since both are strong and since we
mixed equal molar quantities of each, the neutralization reaction
is essentially complete.</para>
<para id="id4176861">We next consider mixing together a weak acid
solution with a strong base solution, again with equal molar
quantities of acid and base. As an example, we mix 100ml of 0.1M
acetic acid
(<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>)
solution with 100ml of 0.1M sodium hydroxide. In this discussion,
we will abbreviate the acetic acid molecular formula
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
as
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>
and the acetate ion
<m:math><m:mrow><m:mi>C</m:mi><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:msup><m:mi>O</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
as
<m:math><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup></m:math>.
The reaction of
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>
and
<m:math><m:mrow><m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
is:</para>
<equation id="eqn11"><m:math><m:mrow>
<m:mi>H</m:mi><m:mi>A</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>→</m:mo>
<m:msup><m:mi>Na</m:mi><m:mo>+</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo>
</m:mrow></m:math></equation>
<para id="id4507309">
<m:math><m:mrow><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo></m:mrow></m:math>
is the acetate ion in solution, formed when an acetic acid molecule
donates the positive hydrogen ion. We have thus created a salt
solution again, in this case of sodium acetate in water. Note that
the volume of the combined solution is 200ml, so the concentration
of sodium acetate
(<m:math><m:mrow><m:mi>Na</m:mi><m:mi>A</m:mi></m:mrow></m:math>)
in solution is 0.050M.</para>
<para id="id4335544">Unlike our previous
<m:math><m:mrow><m:mi>Na</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>
salt solution, a measurement in this case reveals that the pH of
the product salt solution is 9.4, so the solution is basic. Thus,
mixing equal molar quantities of strong base with weak acid
produces a basic solution. In essence, the weak acid does not fully
neutralize the strong base. To understand this, we examine the
behavior of sodium acetate in solution. Since the pH is greater
than 7, then there is an excess of
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ions in solution relative to pure water. These ions must have come
from the reaction of sodium acetate with the water. Therefore, the
negative acetate ions in solution must behave as a base, accepting
positive hydrogen ions:</para>
<equation id="eqn12"><m:math><m:mrow>
<m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>O</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>→</m:mo>
<m:mi>H</m:mi><m:mi>A</m:mi><m:mo>(</m:mo><m:mi>aq</m:mi><m:mo>)</m:mo><m:mo>+</m:mo>
<m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>(</m:mo><m:mi>l</m:mi><m:mo>)</m:mo>
</m:mrow></m:math></equation>
<para id="id4943024">The reaction of an ion with water to form
either an acid or a base solution is referred to as 
<term>hydrolysis</term>. From this example, the salt of a weak acid
behaves as a base in water, resulting in a pH greater than
7.</para>
<para id="id2990889">To understand the extent to which the
hydrolysis of the negative ion occurs, we need to know the
equilibrium constant for this reaction. This turns out to be
determined by the acid ionization constant for
<m:math><m:mrow><m:mi>H</m:mi><m:mi>A</m:mi></m:mrow></m:math>.
To see this, we write the equilibrium constant for the hydrolysis
of
<m:math><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup></m:math>
as</para>

<equation id="eqn13">
<m:math>
<m:apply><m:eq/>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>h</m:mi></m:msub></m:ci>
<m:apply><m:divide/>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>A</m:mi><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply>
<m:ci><m:mrow><m:mo>[</m:mo><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply></m:apply>
</m:math>
</equation>

<para id="id4507243">Multiplying numerator and denominator by
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>,
we find that</para>

<equation id="eqn14">
<m:math>
<m:apply><m:eq/>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>h</m:mi></m:msub></m:ci>
<m:apply><m:times/>
<m:apply><m:divide/>
<m:apply><m:times/>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>A</m:mi><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci></m:apply>
<m:ci><m:mrow><m:mo>[</m:mo><m:msup><m:mi>A</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply>
<m:apply><m:divide/>
<m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
<m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci>
</m:apply></m:apply>
<m:apply><m:divide/>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>w</m:mi></m:msub></m:ci>
<m:ci><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:ci>
</m:apply></m:apply>
</m:math>
</equation>

<para id="id4584939">Therefore, for the hydrolysis of acetate ions
in solution,
<m:math><m:apply><m:eq/><m:ci><m:msub><m:mi>K</m:mi><m:mi>h</m:mi></m:msub></m:ci><m:cn type="e-notation">5.8<m:sep/>-10</m:cn></m:apply></m:math>.
This is fairly small, so the acetate ion is a very weak
base.</para>
</section>
<section id="obs5">
<name>Observation 5: Acid strength and molecular properties</name>
<para id="id4339700">We now have a fairly complete quantitative
description of acid-base equilibrium. To complete our understanding
of acid-base equilibrium, we need a predictive model which relates
acid strength or base strength to molecular properties. In general,
we expect that the strength of an acid is related either to the
relative ease by which it can donate a hydrogen ion or by the
relative stability of the remaining negative ion formed after the
departure of the hydrogen ion.</para>
<para id="id4604071">To begin, we note that there are three basic
categories of acids which we have examined in this study. First,
there are simple 
<term>binary acids</term>: <list id="list1" type="inline"><item><m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math></item>
<item><m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:math></item>
<item><m:math><m:mrow><m:mi>H</m:mi><m:mi>Br</m:mi></m:mrow></m:math></item>
<item><m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi></m:mrow></m:math></item></list>.
Second, there are acids formed from main group elements combined
with one or more oxygen atoms, such
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>S</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>
or
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>.
These are called 
<term>oxyacids</term>. Third, there are the 
<term>carboxylic acids</term>, organic molecules which contain the
carboxylic functional group in <cnxn target="fig1"/>.</para>

 <figure id="fig1">
	<name>Carboxylic Functional Group</name>
	<media type="application/postscript" src="fig1.eps">
	  <media type="image/png" src="fig1.png"/>
	</media>
      </figure>

<para id="id4183802">We consider first the simple binary acids.
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Br</m:mi></m:mrow></m:math>,
and
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi></m:mrow></m:math>
are all strong acids, whereas
<m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math>
is a weak acid. In comparing the experimental values of
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>
values in <cnxn target="table7"/>, we note that
the acid strength increases in the order
<m:math><m:apply><m:lt/><m:ci><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:ci><m:ci><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:ci><m:ci><m:mrow><m:mi>H</m:mi><m:mi>Br</m:mi></m:mrow></m:ci><m:ci><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi></m:mrow></m:ci></m:apply></m:math>.
This means that the hydrogen ion can more readily separate from the
covalent bond with the halogen atom (X) as we move down the
periodic table. This is reasonable, because the strength of the H-X
bond also decreases as we move down the periodic table, as shown in
<cnxn target="table7"/>.</para>

<table id="table7">
<name>H-X Bond Strengths and pKa</name>
<tgroup cols="3">
<thead>
<row>
<entry/>
<entry>
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math></entry>
<entry>Bond Energy
(<m:math><m:apply><m:divide/><m:ci>kJ</m:ci><m:ci>mol</m:ci></m:apply></m:math>)</entry>
</row>
</thead>
<tbody>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>F</m:mi></m:mrow></m:math></entry>
<entry>3.1</entry>
<entry>567.7</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:math></entry>
<entry>-6.0</entry>
<entry>431.6</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Br</m:mi></m:mrow></m:math></entry>
<entry>-9.0</entry>
<entry>365.9</entry>
</row>
<row>
<entry>
<m:math><m:mrow><m:mi>H</m:mi><m:mi>I</m:mi></m:mrow></m:math></entry>
<entry>-9.5</entry>
<entry>298.0</entry>
</row>
</tbody>
</tgroup>
</table>
<para id="id4296869">The decreasing strength of the H-X bond is
primarily due to the increase is the size of the X atom as we move
down the periodic table. We conclude that one factor which
influences acidity is the strength of the H-X bond: a weaker bond
produces a stronger acid, and vice versa.</para>
<para id="id4248198">In the acids in the other two categories, the
hydrogen atom which ionizes is attached directly to an oxygen atom.
Thus, to understand acidity in these molecules, we must examine
what the oxygen atom is in turn bonded to. It is very interesting
to note that, in examining compounds like R-O-H, where R is an atom
or group of atoms, we can get either acidic or basic properties.
For examples,
<m:math><m:mrow><m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
is a strong base, whereas
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>
is a weak acid. This means that, when
<m:math><m:mrow><m:mi>Na</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>
ionizes in solution, the Na-O linkage ionizes, whereas when
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>
ionizes in solution, the H-O bond ionizes.</para>
<para id="id4560504">To understand this behavior, we compare the
strength of the simple oxyacids
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>I</m:mi></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Br</m:mi></m:mrow></m:math>,
and
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>.
The
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>'s
for these acids are found experimentally to be, respectively, 10.6,
8.6, and 7.5. The acid strength for
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>X</m:mi></m:mrow></m:math>
increases as we move up the periodic table in the halogen group.
This means that the H-O bond ionizes more readily when the oxygen
atom is bonded to a more electronegative atom.</para>
<para id="id4570617">We can add to this observation by comparing
the strengths of the acids
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi><m:mi>O</m:mi></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math>,
and
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>.
(Note that the molecular formulae are more commonly written as
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:mi>O</m:mi></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math>,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>,
and
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>.
We have written them instead to emphasize the molecular structure.)
The
<m:math><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:math>'s
of these acids are, respectively, 7.5, 2.0, -2.7, and -8.0.
In each case, the molecule with more oxygen atoms on the central Cl
atom is the stronger acid:
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi><m:mi>O</m:mi></m:mrow></m:math>
is more acidic than
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>,

<foreign>etc</foreign>. A similar result is found in comparing the
oxyacids of nitrogen.
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math>,
nitric acid, is one of the strong acids, whereas
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>N</m:mi><m:mi>O</m:mi></m:mrow></m:math>,
nitrous acid, is a weak acid. Since oxygen atoms are very strongly
electronegative, these trends add to our observation that
increasing electronegativity of the attached atoms increases the
ionization of the O-H bond.</para>
<para id="id4576537">Why would electronegativity play a role in
acid strength? There are two conclusions we might draw. First, a
greater electronegativity of the atom or atoms attached to the H-O
in the oxyacid apparently results in a weaker H-O bond, which is
thus more readily ionized. We know that an electronegative atom
polarizes bonds by drawing the electrons in the molecule towards
it. In this case, the Cl in
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>
and the Br in
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Br</m:mi></m:mrow></m:math>
must polarize the H-O bond, weakening it and facilitating the
ionization of the hydrogen. In comparing
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>
to
<m:math><m:mrow><m:mi>H</m:mi><m:mi>O</m:mi><m:mi>Cl</m:mi><m:mi>O</m:mi></m:mrow></m:math>,
the added oxygen atom must increase the polarization of the H-O
bond, thus weakening the bond further and increasing the extent of
ionization.</para>
<para id="id4354530">A second conclusion has to do with the ion
created by the acid ionization. The negative ion produced has a
surplus electron, and the relative energy of this ion will depend
on how readily that extra electron is attracted to the atoms of
ion. The more electronegative those atoms are, the stronger is the
attraction. Therefore, the
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>Cl</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ion can more readily accommodate the negative charge than can the
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>Br</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ion. And the
<m:math><m:mrow><m:mi>O</m:mi><m:mi>Cl</m:mi><m:msup><m:mi>O</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ion can more readily accommodate the negative charge than can the
<m:math><m:mrow><m:mi>O</m:mi><m:msup><m:mi>Cl</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>
ion.</para>
<para id="id4505529">We conclude that the presence of strongly
electronegative atoms in an acid increases the polarization of the
H-O bond, thus facilitating ionization of the acid, and increases
the attraction of the extra electron to the negative ion, thus
stabilizing the negative ion. Both of these factors increase the
acid strength. Chemists commonly use both of these conclusions in
understanding and predicting relative acid strength.</para>
<para id="id4279691">The relative acidity of carbon compounds is a
major subject of organic chemistry, which we can only visit briefly
here. In each of the carboxylic acids, the H-O group is attached to
a carbonyl C=O group, which is in turn bonded to other atoms. The
comparison we observe here is between carboxylic acid molecules,
denoted as
<m:math><m:mrow><m:mi>R</m:mi><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>,
and other organic molecules containing the H-O group, such as
alcohols denoted as
<m:math><m:mrow><m:mi>R</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>.
(R is simply an atom or group of atoms attached to the functional
group.) The former are obviously acids whereas the latter group
contains molecules which are generally extremely weak acids. One
interesting comparison is for the acid and alcohol when R is the
benzene ring,
<m:math><m:mrow><m:msub><m:mi>C</m:mi><m:mn>6</m:mn></m:msub><m:msub><m:mi>H</m:mi><m:mn>5</m:mn></m:msub></m:mrow></m:math>.
Benzoic acid,
<m:math><m:mrow><m:msub><m:mi>C</m:mi><m:mn>6</m:mn></m:msub><m:msub><m:mi>H</m:mi><m:mn>5</m:mn></m:msub><m:mi>C</m:mi><m:mi>O</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>,
has
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:ci><m:cn>4.2</m:cn></m:apply></m:math>,
whereas phenol,
<m:math><m:mrow><m:msub><m:mi>C</m:mi><m:mn>6</m:mn></m:msub><m:msub><m:mi>H</m:mi><m:mn>5</m:mn></m:msub><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>,
has
<m:math><m:apply><m:eq/><m:ci><m:mrow><m:mi>p</m:mi><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:mrow></m:ci><m:cn>9.9</m:cn></m:apply></m:math>.
Thus, the presence of the doubly bonded oxygen atom on the carbon
atom adjacent to the O-H clearly increases the acidity of the
molecule, and thus increases ionization of the O-H bond.</para>
<para id="id6541380">This observation is quite reasonable in the
context of our previous conclusion. Adding an electronegative
oxygen atom in near proximity to the O-H bond both increases the
polarization of the O-H bond and stabilizes the negative ion
produced by the acid ionization. In addition to the
electronegativity effect, carboxylate anions,
<m:math><m:mrow><m:mi>R</m:mi><m:mi>C</m:mi><m:mi>O</m:mi><m:msup><m:mi>O</m:mi><m:mo>-</m:mo></m:msup></m:mrow></m:math>,
exhibit resonance stabilization, as seen in <cnxn target="fig2"/>.</para>

 <figure id="fig2">
	<media type="application/postscript" src="fig2.eps">
	  <media type="image/png" src="fig2.png"/>
	</media>
      </figure>

<para id="id4577087">The resonance results in a sharing of the
negative charge over several atoms, thus stabilizing the negative
ion. This is a major contributing factor in the acidity of
carboxylic acids versus alcohols.</para>
</section>
<section id="id4618594">
<name>Review and Discussion Questions</name>
<exercise id="ex1"><problem><para id="id4618601">Strong acids have a higher percent ionization
than do weak acids. Why don't we use percent ionization as a
measure of acid strength, rather than
<m:math><m:msub><m:mi>K</m:mi><m:mi>a</m:mi></m:msub></m:math>?</para></problem></exercise>
<exercise id="ex2"><problem>
<para id="id4263430">Using the data in <cnxn target="table4"/> for nitrous acid, plot
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
versus
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>,
the initial concentration of the acid, and versus
<m:math><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:math>
the equilibrium concentration of the acid. On a second graph, plot
<m:math><m:apply><m:power/><m:ci><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:ci><m:cn>2</m:cn></m:apply></m:math>
versus
<m:math><m:msub><m:mi>c</m:mi><m:mn>0</m:mn></m:msub></m:math>,
the initial concentration of the acid, and versus
<m:math><m:mrow><m:mo>[</m:mo><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub><m:mo>]</m:mo></m:mrow></m:math>
the equilibrium concentration of the acid. Which of these results
gives a straight line? Using the equilibrium constant expression,
explain your answer.</para></problem></exercise>
<exercise id="ex3"><problem>
<para id="id4215262">Using Le Châtelier's principle,
explain why the concentration of
<m:math><m:mrow><m:mo>[</m:mo><m:mi>O</m:mi><m:msup><m:mi>H</m:mi><m:mo>-</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
is much lower in acidic solution than it is in neutral
solution.</para></problem></exercise>
<exercise id="ex4"><problem>
<para id="id4253252">We considered mixing a strong base with a weak
acid, but we did not consider mixing a strong acid with a weak
acid. Consider mixing 0.1M
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math>
and 0.1M
<m:math><m:mrow><m:mi>H</m:mi><m:mi>N</m:mi><m:msub><m:mi>O</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math>.
Predict the pH of the solution and the percent ionization of the
nitrous acid. Rationalize your prediction using Le
Châtelier's principle.</para></problem></exercise>
<exercise id="ex5"><problem>
<para id="id2483459">Imagine taking a 0.5M solution of nitrous acid
and slowing adding water to it. Looking at <cnxn target="table3"/>, we see that, as the concentration
of nitrous acid decreases, the percent ionization increases. By
contrast,
<m:math><m:mrow><m:mo>[</m:mo><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:msup><m:mi>O</m:mi><m:mo>+</m:mo></m:msup><m:mo>]</m:mo></m:mrow></m:math>
decreases. Rationalize these results using Le
Châtelier's principle.</para></problem></exercise>
<exercise id="ex6"><problem>
<para id="id3862459">We observed that mixing a strong acid and a
strong base, in equal amounts and concentrations, produces a
neutral solution, and that mixing a strong base with a weak acid,
in equal amounts and concentrations, produces a basic solution.
Imagine mixing a weak acid and a weak base, in equal amounts and
concentrations. Predict whether the resulting solution will be
acidic, basic, or neutral, and explain your prediction.</para></problem></exercise>
<exercise id="ex7"><problem>
<para id="id4606449">Using the electronegativity arguments
presented <cnxn target="obs5">above</cnxn>,
explain why, in general, compounds like M-O-H are bases rather than
acids, when M is a metal atom. Predict the relationship between the
properties of the metal atom M and the strength of the base
<m:math><m:mrow><m:mi>M</m:mi><m:mi>O</m:mi><m:mi>H</m:mi></m:mrow></m:math>.</para></problem></exercise>
<exercise id="ex8"><problem>
<para id="id4606467">Ionization of sulfuric acid
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>S</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>
produces
<m:math><m:mrow><m:mi>H</m:mi><m:mi>S</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>4</m:mn><m:mo>-</m:mo></m:msubsup></m:mrow></m:math>,
which is also an acid. However,
<m:math><m:mrow><m:mi>H</m:mi><m:mi>S</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>4</m:mn><m:mo>-</m:mo></m:msubsup></m:mrow></m:math>
is a much weaker acid than
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>S</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>.
Using the conclusions from <cnxn target="obs5">above</cnxn>, explain why
<m:math><m:mrow><m:mi>H</m:mi><m:mi>S</m:mi><m:msubsup><m:mi>O</m:mi><m:mn>4</m:mn><m:mo>-</m:mo></m:msubsup></m:mrow></m:math>
is a much weaker acid.</para></problem></exercise>
<exercise id="ex9"><problem>
<para id="id4375338">Predict and explain the relative acid
strengths of
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub><m:mi>S</m:mi></m:mrow></m:math>
and
<m:math><m:mrow><m:mi>H</m:mi><m:mi>Cl</m:mi></m:mrow></m:math>.
Predict and explain the relative acid strengths of
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>P</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>
and
<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>3</m:mn></m:msub><m:mi>As</m:mi><m:msub><m:mi>O</m:mi><m:mn>4</m:mn></m:msub></m:mrow></m:math>.</para></problem></exercise>
<exercise id="ex10"><problem>
<para id="id4547336">Using arguments from <cnxn target="obs5">above</cnxn>, predict and
explain the relative acidity of <cnxn target="fig3a">phenol</cnxn> and <cnxn target="fig3b">methanol</cnxn>.</para>
 <figure id="fig3" orient="vertical">
       <subfigure id="fig3a">
	<name>Phenol</name>
	<media type="application/postscript" src="fig3a.eps">
	  <media type="image/png" src="fig3a.png"/>
	</media>
        </subfigure>
       <subfigure id="fig3b">
	<name>Methanol</name>
	<media type="application/postscript" src="fig3b.eps">
	  <media type="image/png" src="fig3b.png"/>
	</media>
        </subfigure>
      </figure></problem></exercise>
</section>
</content>
</document>
