Foundation
We begin with our knowledge of the structure
and properties of atoms. We know that atoms have a nuclear
structure, meaning that all of the positive charge and virtually
all of the mass of the atom are concentrated in a nucleus which is
a very small fraction of the volume of the atom. In addition, we
know that many of the properties of atoms can be understood by a
model in which the electrons in the atom are arranged in
“shells” about the nucleus, with each shell farther
from the nucleus that the previous. The electrons in outer shells
are more weakly attached to the atom than the electrons in the
inner shells, and only a limited number of electrons can fit in
each shell. Within each shell are subshells, each of which can also
hold a limited number of electrons. The electrons in different
subshells have different energies and different locations for
motion about the nucleus. We also assume a knowledge of the a
Lewis structure model for chemical bonding
based on valence shell electron pair sharing and the octet rule. A
covalent chemical bond is formed when the two bonded atoms share a
pair of valence shell electrons between them. In general, atoms of
Groups IV through VII bond so as to complete an octet of valence
shell electrons. We finally assume the Electron
Domain Model for understanding and predicting
molecular geometries. The pairs of valence shell electrons are
arranged in bonding and non-bonding domains, and these domains are
separated in space to minimize electron-electron repulsions. This
electron domain arrangement determines the molecular
geometry.
Goals
We should expect that the properties of
molecules, and correspondingly the substances which they comprise,
should depend on the details of the structure and bonding in these
molecules. Now that we have developed an understanding of the
relationship between molecular structure and chemical bonding, we
analyze physical properties of the molecules and compounds of these
molecules to relate to this bonding and structure. Simple examples
of physical properties which can be related to molecular properties
are the melting and boiling temperatures. These vary dramatically
from substance to substance, even for substances which appear
similar in molecular formulae, with some melting temperatures in
the hundreds or thousands of degrees Celsius and others well below
0°C. We seek to understand these variations by analyzing
molecular structures.
To develop this understanding, we will have to
apply more details of our understanding of atomic structure and
electronic configurations. In our covalent bonding model, we have
assumed that atoms “share” electrons to form a bond.
However, our knowledge of the properties of atoms reveals that
different atoms attract electrons with different strengths,
resulting in very strong variations in ionization energies, atomic
radii, and electron affinities. We seek to incorporate this
information into our understanding of chemical bonding
Observation 1: Compounds of Groups I and II
We begin by analyzing compounds formed from
elements from Groups I and II (e.g.
sodium and magnesium). These compounds are not currently part of
our Lewis structure model. For example, Sodium, with a single
valence electron, is unlikely to gain seven additional electrons to
complete an octet. Indeed, the common valence of the alkali metals
in Group I is 1, not 7, and the common valence of the alkaline
earth metals is 2, not 6. Thus, our current model of bonding does
not apply to elements in these groups.
To develop an understanding of bonding in
these compounds, we focus on the halides of these elements. In
Table 1, we compare physical
properties of the chlorides of elements in Groups I and II to the
chlorides of the elements of Groups IV, V, and VI, and we see
enormous differences. All of the alkali halides and alkaline earth
halides are solids at room temperature and have melting points in
the hundreds of degrees centigrade. The melting point of
NaClNaCl
is 808°C, for example. By contrast, the melting points of the
non-metal halides from Periods 2 and 3, such as
CCl4CCl4,
PCl3PCl3,
and
SCl2SCl2,
are below 0°C, so that these materials are liquids at room
temperature. Furthermore, all of these compounds have low boiling
points, typically in the range of 50°C to 80°C.
Melting Points and Boiling Points of Chloride
Compounds
| |
Melting Point (°C) |
Boiling Point (°C) |
| LiClLiCl
|
610 |
1382 |
| BeCl2BeCl2 |
405 |
488 |
| CCl4CCl4 |
-23 |
77 |
| NCl3NCl3 |
-40 |
71 |
| OCl2OCl2 |
-20 |
4 |
| FClFCl |
-154 |
-101 |
| NaClNaCl |
808 |
1465 |
| MgCl2MgCl2 |
714 |
1418 |
| SiCl4SiCl4 |
-68 |
57 |
| PCl3PCl3 |
-91 |
74 |
| SCl2SCl2 |
-122 |
59 |
| Cl2Cl2 |
-102 |
-35 |
| KClKCl |
772 |
1407 |
| CaCl2CaCl2 |
772 |
>1600 |
Second, the non-metal halide liquids are
electrical insulators, that is, they do not conduct an electrical
current. By contrast, when we melt an alkali halide or alkaline
earth halide, the resulting liquid is an excellent electrical
conductor. This indicates that these molten compounds consist of
ions, whereas the non-metal halides do not.
We must conclude that the bonding of atoms in
alkali halides and alkaline earth halides differs significantly
from bonding in non-metal halides. We need to extend our valence
shell electron model to account for this bonding, and in
particular, we must account for the presence of ions in the molten
metal halides. Consider the prototypical example of
NaClNaCl.
We have already deduced that Cl atoms react so as to form a
complete octet of valence shell electrons. Such an octet could be
achieved by covalently sharing the single valence shell electron
from a sodium atom. However, such a covalent sharing is clearly
inconsistent with the presence of ions in molten sodium chloride.
Furthermore, this type of bond would predict that
NaClNaCl
should have similar properties to other covalent chloride
compounds, most of which are liquids at room temperature. By
contrast, we might imagine that the chlorine atom completes its
octet by taking the valence shell electron from a sodium atom,
without covalent sharing. This would account for the presence of
Na+Na+
and
Cl-Cl-
ions in molten sodium chloride.
In the absence of a covalent sharing of an
electron pair, though, what accounts for the stability of sodium
chloride as a compound? It is relatively obvious that a negatively
charged chloride ion will be attracted electrostatically to a
positively charged sodium ion. We must also add to this model,
however, the fact that individual molecules of
NaClNaCl
are not generally observed at temperatures less than 1465°C,
the boiling point of sodium chloride. Note that, if solid sodium
chloride consists of individual sodium ions in proximity to
individual chloride ions, then each positive ion is not simply
attracted to a single specific negative ion but rather to all of
the negative ions in its near vicinity. Hence, solid sodium
chloride cannot be viewed as individual
NaClNaCl
molecules, but must be viewed rather as a lattice of positive
sodium ions interacting with negative chloride ions. This type of
“ionic” bonding, which derives from the electrostatic
attraction of interlocking lattices of positive and negative ions,
accounts for the very high melting and boiling points of the alkali
halides.
We can now draw modified Lewis structures to
account for ionic bonding, but these are very different from our
previous drawings. Sodium chloride can be represented as shown in
Figure 1.
This indicates explicitly that the bonding is
due to positive-negative ion attraction, and not due to sharing of
an electron pair. The only sense in which the
Na+Na+
ion has obeyed an octet rule is perhaps that, in having emptied its
valence shell of electrons, the remaining outer shell of electrons
in the ion has the same octet as does a neon atom. We must keep in
mind, however, that the positive sodium ion is attracted to many
negative chloride ions, and not just the single chloride ion
depicted in the Lewis structure.
Observation 2: Molecular Dipole Moments
Our Lewis model of bonding, as currently
developed, incorporates two extreme views of the distribution of
electrons in a bond. In a covalent bond, we have assumed up to this
point that the electron pair is shared perfectly. In complete
contrast, in ionic bonding we have assumed that the electrons are
not shared at all. Rather, one of the atoms is assumed to entirely
extract one or more electrons from the other. We might expect that
a more accurate description of the reality of chemical bonds falls
in general somewhere between these two extremes. To observe this
intermediate behavior, we can examine molecular dipole
moments.
An electric dipole is a spatial separation of
positive and negative charges. In the simplest case, a positive
charge
+QQ
and a negative charge
-QQ
separated by a distance
RR produce a
measurable dipole moment,
μμ
equal to
Q×R×QR.
An electric field can interact with an electric dipole and can even
orient the dipole in the direction of the field.
We might initially expect that molecules do
not in general have dipole moments. Each atom entering into a
chemical bond is electrically neutral, with equal numbers of
positive and negative charges. Consequently, a molecule formed from
neutral atoms must also be electrically neutral. Although electron
pairs are shared between bonded nuclei, this does not affect the
total number of negative charges. We might from these simple
statements that molecules would be unaffected by electric or
magnetic fields, each molecule behaving as a single uncharged
particle.
This prediction is incorrect, however. To
illustrate, a stream of water can be deflected by an electrically
charged object near the stream, indicating that individual water
molecules exhibit a dipole moment. A water molecule is rather more
complicated than a simple separation of a positive and negative
charges, however. Recall though that a water molecule has equal
total numbers of positive and negative charges, consisting of three
positively charged nuclei surrounded by ten electrons.
Nevertheless, measurements reveal that water has a dipole moment of
6.17×10-30Cm=1.85debye6.17-30Cm1.85debye.
(The debye is a unit used to measure dipole moments:
1debye=3.33
×10-30Cm1debye3.33
-30Cm.)
Water is not unique: the molecules of most substances have dipole
moments. A sampling of molecules and their dipole moments is given
in
Table 2.
Dipole Moments of Specific Molecules
| |
μ (debye) |
| H2OH2O |
1.85 |
| HFHF |
1.91 |
| HClHCl |
1.08 |
| HBrHBr |
0.80 |
| HIHI |
0.42 |
| COCO |
0.12 |
| CO2CO2 |
0 |
| NH3NH3 |
1.47 |
| PH3PH3 |
0.58 |
| AsH3AsH3 |
0.20 |
| CH4CH4 |
0 |
| NaClNaCl |
9.00 |
Focusing again on the water molecule, how can
we account for the existence of a dipole moment in a neutral
molecule? The existence of the dipole moment reveals that a water
molecule must have an internal separation of positive partial
charge
+δδ
and negative partial charge
-δδ.
Thus, it must be true that the electrons in the covalent bond
between hydrogen and oxygen are not
equally shared. Rather, the shared
electrons must spend more time in the vicinity of one nucleus than
the other. The molecule thus has one region where, on average,
there is a net surplus of negative charge and one region where, on
average, there is a compensating surplus of positive charge, thus
producing a molecular dipole. Additional observations reveal that
the oxygen "end" of the molecule holds the partial negative charge.
Hence, the covalently shared electrons spend more time near the
oxygen atom than near the hydrogen atoms. We conclude that oxygen
atoms have a greater ability to attract the shared electrons in the
bond than do hydrogen atoms.
We should not be surprised by the fact that
individual atoms of different elements have differing abilities to
attract electrons to themselves. We have previously seen that
different atoms have greatly varying ionization energies,
representing great variation in the extent to which atoms cling to
their electrons. We have also seen great variation in the electron
affinities of atoms, representing variation in the extent to which
atoms attract an added electron. We now define the
electronegativity of an atom as the
ability of the atom to attract electrons in a chemical bond. This
is different than either ionization energy or electron affinity,
because electronegativity is the attraction of electrons
in a chemical bond, whereas
ionization energy and electron affinity refer to removal and
attachment of electrons in free atoms. However, we can expect
electronegativity to be correlated with electron affinity and
ionization energy. In particular, the electronegativity of an atom
arises from a combination of properties of the atom, including the
size of the atom, the charge on the nucleus, the number of
electrons about the nuclei, and the number of electrons in the
valence shell.
Because electronegativity is an abstractly
defined property, it cannot be directly measured. In fact, there
are many definitions of electronegativity, resulting in many
different scales of electronegativities. However, relative
electronegativities can be observed indirectly by measuring
molecular dipole moments: in general, the greater the dipole
moment, the greater the separation of charges must be, and
therefore, the less equal the sharing of the bonding electrons must
be.
With this in mind, we refer back to the
dipoles given in
Table 2. There
are several important trends in these data. Note that each hydrogen
halide
(
HFHF,
HClHCl,
HBrHBr,
and
HIHI)
has a significant dipole moment. Moreover, the dipole moments
increase as we move
up the
periodic table in the halogen group. We can conclude that fluorine
atoms have a greater electronegativity than do chlorine atoms,
etc. Note also that
HFHF
has a greater dipole moment than
H2OH2O,
which is in turn greater than that of
NH3NH3.
We can conclude that electronegativity increases as we move
across the periodic table from
left to right in a single period. These trends hold generally in
comparisons of the electronegativities of the individual elements.
One set of relative electronegativities of atoms in the first three
rows of the periodic table is given in
Table 3.
Electronegativities of Selected Atoms
| |
χ |
| H |
2.1 |
| He |
- |
| Li |
1.0 |
| Be |
1.5 |
| B |
2.0 |
| C |
2.5 |
| N |
3.0 |
| O |
3.5 |
| F |
4.0 |
| Ne |
- |
| Na |
0.9 |
| Mg |
1.2 |
| Al |
1.5 |
| Si |
1.8 |
| P |
2.1 |
| S |
2.5 |
| Cl |
3.0 |
| Ar |
- |
| K |
0.8 |
| Ca |
1.0 |
Observation 3: Dipole Moments in Polyatomic Molecules
We might reasonably expect from our analysis
to observe a dipole moment in any molecule formed from atoms with
different electronegativities. Although this must be the case for a
diatomic molecule, this is not necessarily true for a polyatomic
molecule,
i.e. one with more than two atoms. For example, carbon is
more electronegative than hydrogen. However, the simplest molecule
formed from carbon and hydrogen
(
e.g.
CH4CH4)
does
not possess a dipole moment,
as we see in
Table 2. Similarly,
oxygen is significantly more electronegative than carbon, yet
CO2CO2
is a non-polar molecule. An analysis of molecular dipole moments in
polyatomic molecules requires us to apply our understanding of
molecular geometry.
Note that each
COCO
bond is expected to be polar, due to the unequal sharing of the
electron pairs between the carbon and the oxygen. Thus, the carbon
atom should have a slight positive charge and the oxygen atom a
slight negative charge in each
COCO
bond. However, since each oxygen atom should have the same net
negative charge, neither end of the molecule would display a
greater affinity for an electric field. Moreover, because
CO2CO2
is linear, the dipole in one
COCO
bond is exactly offset by the dipole in the opposite direction due
to the other
COCO
bond. As measured by an electric field from a distance, the
CO2CO2
molecule does not appear to have separated positive and negative
charges and therefore does not display polarity. Thus, in
predicting molecular dipoles we must take into account both
differences in electronegativity, which affect bond polarity, and
overall molecular geometry, which can produce cancellation of bond
polarities.
Using this same argument, we can rationalize
the zero molecular dipole moments observed for other molecules,
such as methane, ethene and acetylene. In each of these molecules,
the individual
CHCH
bonds are polar. However, the symmetry of the molecule produces a
cancellation of these bond dipoles overall, and none of these
molecules have a molecular dipole moment.
As an example of how a molecular property like
the dipole moment can affect the macroscopic property of a
substance, we can examine the boiling points of various compounds.
The boiling point of a compound is determined by the strength of
the forces between molecules of the compound: the stronger the
force, the more energy is required to separate the molecules, the
higher the temperature required to provide this energy. Therefore,
molecules with strong intermolecular forces have high boiling
points.
We begin by comparing molecules which are
similar in size, such as the hydrides
SiH4SiH4,
PH3PH3,
and
SH2SH2
from the third period. The boiling points at standard pressure for
these molecules are, respectively, -111.8°C, -87.7°C, and
-60.7°C. All three compounds are thus gases at room
temperature and well below. These molecules have very similar
masses and have exactly the same number of electrons. However, the
dipole moments of these molecules are very different. The dipole
moment of
SiH4SiH4,
is 0.0D, the dipole moment of
PH3PH3
is 0.58D, and the dipole moment of
SH2SH2
is 0.97D. Note that, for these similar molecules, the higher the
dipole moment, the higher the boiling point. Thus, molecules with
larger dipole moments generally have stronger intermolecular forces
than similar molecules with smaller dipole moments. This is because
the positive end of the dipole in one molecule can interact
electrostatically with the negative end of the dipole in another
molecules, and vice versa.
We note, however, that one cannot generally
predict from dipole moment information only the relative boiling
points of compounds of very dissimilar molecules
Review and Discussion Questions
Problem 1Compare and contrast the chemical and physical
properties of
KClKCl
and
CCl4CCl4,
and compare and contrast how the chemical bonding model can be used
to account for these properties.
Problem 2Why is the dipole moment of
NaClNaCl
extremely large?
Problem 3
Explain why
COCO
has a dipole moment but
CO2CO2
does not.
Problem 4
Explain why an atom with a high ionization
energy is expected to have a high electronegativity. Explain why an
atom with a high electron affinity is expected to have a high
electronegativity.
Problem 5
Would you predict that a Kr atom has high
electronegativity or low electronegativity? Predict the relative
electronegativity of Kr and F.
Problem 6
Explain why S has a greater electronegativity
than P but a smaller electronegativity than O.
Problem 7
N atoms have a high electronegativity.
However, N atoms have no electron affinity, meaning that N atoms do
not attract electrons. Explain how and why these facts are not
inconsistent.
Problem 8
Explain why compounds formed from elements
with large differences in electronegativities are ionic.
Problem 9
Explain why ionic compounds have much higher
melting points than covalent compounds.
"General Chemistry course in Braille."