Suppose we have two waves, with the same amplitude but different wavelengths
and velocities and we add them
y
1
=
A
sin
[
2
π
λ
1
(
x
−
v
1
t
)
]
y
1
=
A
sin
[
2
π
λ
1
(
x
−
v
1
t
)
]
y
2
=
A
sin
[
2
π
λ
2
(
x
−
v
2
t
)
]
.
y
2
=
A
sin
[
2
π
λ
2
(
x
−
v
2
t
)
]
.
Then
y
1
+
y
2
=
A
(
sin
[
2
π
λ
1
(
x
−
v
1
t
)
]
+
sin
[
2
π
λ
2
(
x
−
v
2
t
)
]
)
.
y
1
+
y
2
=
A
(
sin
[
2
π
λ
1
(
x
−
v
1
t
)
]
+
sin
[
2
π
λ
2
(
x
−
v
2
t
)
]
)
.
Lets
rewrite using wave number and angular frequency
y
1
+
y
2
=
y
=
A
(
sin
[
(
k
1
x
−
ω
1
t
)
]
+
sin
[
(
k
2
x
−
ω
2
t
)
]
)
.
y
1
+
y
2
=
y
=
A
(
sin
[
(
k
1
x
−
ω
1
t
)
]
+
sin
[
(
k
2
x
−
ω
2
t
)
]
)
.
Now
we will use
sin
(
θ
+
φ
)
+
sin
(
θ
−
φ
)
=
2
sin
θ
cos
φ
sin
(
θ
+
φ
)
+
sin
(
θ
−
φ
)
=
2
sin
θ
cos
φ
and set
θ
+
φ
=
k
1
x
−
ω
1
t
θ
+
φ
=
k
1
x
−
ω
1
t
θ
−
φ
=
k
2
x
−
ω
2
t
.
θ
−
φ
=
k
2
x
−
ω
2
t
.
We
can rearrange to get
2
θ
=
(
k
1
+
k
2
)
x
−
(
ω
1
+
ω
2
)
t
2
θ
=
(
k
1
+
k
2
)
x
−
(
ω
1
+
ω
2
)
t
2
φ
=
(
k
1
−
k
2
)
x
−
(
ω
1
−
ω
2
)
t
.
2
φ
=
(
k
1
−
k
2
)
x
−
(
ω
1
−
ω
2
)
t
.
By
substituting we can then see that
y
=
2
A
(
cos
[
k
1
−
k
2
2
x
−
ω
1
−
ω
2
2
t
]
×
sin
[
k
1
+
k
2
2
x
−
ω
1
+
ω
2
2
t
]
)
.
y
=
2
A
(
cos
[
k
1
−
k
2
2
x
−
ω
1
−
ω
2
2
t
]
×
sin
[
k
1
+
k
2
2
x
−
ω
1
+
ω
2
2
t
]
)
.
Now
set
Δ
k
=
k
1
−
k
2
Δ
k
=
k
1
−
k
2
Δ
ω
=
ω
1
−
ω
2
Δ
ω
=
ω
1
−
ω
2
k
=
k
1
+
k
2
2
k
=
k
1
+
k
2
2
ω
=
ω
1
+
ω
2
2
ω
=
ω
1
+
ω
2
2
and
we can rewrite the wave as
y
=
2
A
cos
(
x
Δ
k
2
−
t
Δ
ω
2
)
sin
(
k
x
−
ω
t
)
.
y
=
2
A
cos
(
x
Δ
k
2
−
t
Δ
ω
2
)
sin
(
k
x
−
ω
t
)
.
The above equation shows beats. For example you can set
t
=
0
t
=
0
and see that you get
y
=
2
A
cos
(
x
Δ
k
2
)
sin
(
k
x
)
.
y
=
2
A
cos
(
x
Δ
k
2
)
sin
(
k
x
)
.
Likewise
you could pick
x
=
0
x
=
0
and get the same figure, but now the horizontal axis is time
y
=
2
A
cos
(
−
t
Δ
ω
2
)
sin
(
−
ω
t
)
y
=
2
A
cos
(
−
t
Δ
ω
2
)
sin
(
−
ω
t
)
or
y
=
2
A
cos
(
t
Δ
ω
2
)
sin
(
−
ω
t
)
.
y
=
2
A
cos
(
t
Δ
ω
2
)
sin
(
−
ω
t
)
.
You
get a traveling wave that has an oscillating amplitude.
When we look at
y
=
2
A
cos
(
x
Δ
k
2
−
t
Δ
ω
2
)
sin
(
k
x
−
ω
t
)
y
=
2
A
cos
(
x
Δ
k
2
−
t
Δ
ω
2
)
sin
(
k
x
−
ω
t
)
we see that there are two velocities. One, referred to as the phase velocity,
is the speed of the individual wave
crests:
v
p
=
ω
k
=
ν
λ
.
v
p
=
ω
k
=
ν
λ
.
The group velocity is the velocity of the envelope
v
g
=
Δ
ω
Δ
k
→
d
ω
d
k
v
g
=
Δ
ω
Δ
k
→
d
ω
d
k
Energy and momentum normally move with the group velocity.