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Series de Fourier y los Sistemas LTI

Module by: Justin Romberg. E-mail the authorTranslated By: Fara Meza, Erika Jackson

Based on: Fourier Series and LTI Systems by Justin Romberg

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Introduciendo las Series de Fourier a los Sistemas LTI

Antes de ver este modulo, usted debería familiarizarse con los conceptos de Eigenfunciones de los sistemas LTI. Recuerde, para sistema LTI tenemos la siguiente relación

Figura 1: Señales de entrada y salida para nuestro sitema LTI.
Figura 1 (simpleLTIsys.png)

donde st s t es una eigenfunción de . Su eigenvalor correspondiente Hs H s pueden ser calculado usando la respuesta de impulso ht h t Hs=-hτ-sτdτ H s τ h τ s τ

Así, usando la expansión de las series de Fourier para ft f t periódica donde usamos la entrada ft=n c n ω 0 nt f t n c n ω 0 n t en el sistema,

Figura 2: Sistema LTI
Figura 2 (Transferfunc.png)

nuestra salida yt y t será yt=nH ω 0 n c n ω 0 nt y t n H ω 0 n c n ω 0 n t Podemos ver que al aplicar las ecuaciones de expansión de series de fourier, podemos ir de ft f t a c n c n y viceversa, y es lo mismo para la salida, yt y t

Efectos de las Series de Fourier

Podemos pensar de un sistema LTI como el ir moldeando el contenido de la frecuencia de la entrada. Mantenga en mente el sistema básico LTI que presentamos en figura 2. El sistema LTI, , multiplica todos los coeficientes de Fourier y los escala.

Dado los coeficientes de Fourier de la entrada c n c n y los eigen valores del sistema H w 0 n H w 0 n , las series de Fourier de la salida, es H w 0 n c n H w 0 n c n (una simple multiplicación de termino por termino).

note:

los eigenvalores, H w 0 n H w 0 n describen completamente lo que un sistema LTI le hace a una señal periódica con periodo T=2π w 0 T 2 w 0

Ejemplo 1

¿Qué hace este sistema?

Figura 3
Figura 3 (fslti_f1.png)

Ejemplo 2

Y, ¿esté sistema?

Figura 4
(a) (b)
Figura 4(a) (fslti_f2.png)Figura 4(b) (fslti_f3.png)

Examples

Ejemplo 3: El circuito RC

ht=1RC-tRCut h t 1 R C t R C u t

¿Qué es lo que este sistema hace a las series de fourier de la ft f t ?

Calcula los eigenvalores de este sistema

Hs=-hτ-sτdτ=01RC-τRC-sτdτ=1RC0-τ1RC+sdτ=1RC11RC+s-τ1RC+s|τ=0=11+RCs H s τ h τ s τ τ 0 1 R C τ R C s τ 1 R C τ 0 τ 1 R C s 1 R C 1 1 R C s τ 0 τ 1 R C s 1 1 R C s (1)

Ahora, decimos que a este circuito RC lo alimentamos con una entrada ft f t periódica (con periodo T=2π w 0 T 2 w 0 ).

Vea los eigen valores para s= w 0 n s w 0 n |H w 0 n|=1|1+RC w 0 n|=11+R2C2 w 0 2n2 H w 0 n 1 1 R C w 0 n 1 1 R 2 C 2 w 0 2 n 2

El circuito RC es un sistema pasa bajas: pasa frecuencias bajas n n alrededor de 0 0) atenúa frecuencias altas ( n n grandes).

Ejemplo 4: Pulsó cuadrado a través del Circuito RC

  • Señal de entrada : tomando las series de Fourier ft f t c n =12sinπ2nπ2n c n 1 2 2 n 2 n 1t 1 t en n=0 n 0
  • Sistema : Eigenvalores H w 0 n=11+RC w 0 n H w 0 n 1 1 R C w 0 n
  • Señal de salida: tomando las series de Fourier de yt y t d n =H w 0 n c n =11+RC w 0 n12sinπ2nπ2n d n H w 0 n c n 1 1 R C w 0 n 1 2 2 n 2 n

d n =11+RC w 0 n12sinπ2nπ2n d n 1 1 R C w 0 n 1 2 2 n 2 n yt= d n w 0 nt y t n d n w 0 n t

¿Qué podemos decir sobre yt y t de d n d n ?

  1. ¿Es yt y t real?
  2. ¿ Es yt y t simétrico par? ¿simétrico impar?
  3. ¿Comó se yt y t ¿es mas “suave” que ft f t ? (el radio de descomposición de d n d n vs. c n c n )

d n =11+RC w 0 n12sinπ2nπ2n d n 1 1 R C w 0 n 1 2 2 n 2 n | d n |=11+RC w 0 2n212sinπ2nπ2n d n 1 1 R C w 0 2 n 2 1 2 2 n 2 n

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