r
⊥
≡
(
E
0
r
E
0
i
)
⊥
=
n
i
cos
θ
i
−
n
t
cos
θ
t
n
i
cos
θ
i
+
n
t
cos
θ
t
r
⊥
≡
(
E
0
r
E
0
i
)
⊥
=
n
i
cos
θ
i
−
n
t
cos
θ
t
n
i
cos
θ
i
+
n
t
cos
θ
t
t
⊥
≡
(
E
0
t
E
0
i
)
⊥
=
2
n
i
cos
θ
i
n
i
cos
θ
i
+
n
t
cos
θ
t
t
⊥
≡
(
E
0
t
E
0
i
)
⊥
=
2
n
i
cos
θ
i
n
i
cos
θ
i
+
n
t
cos
θ
t
r
∥
≡
(
E
0
r
E
0
i
)
∥
=
n
t
cos
θ
i
−
n
i
cos
θ
t
n
t
cos
θ
i
+
n
i
cos
θ
t
r
∥
≡
(
E
0
r
E
0
i
)
∥
=
n
t
cos
θ
i
−
n
i
cos
θ
t
n
t
cos
θ
i
+
n
i
cos
θ
t
t
∥
≡
(
E
0
t
E
0
i
)
∥
=
2
n
i
cos
θ
i
n
t
cos
θ
i
+
n
i
cos
θ
t
t
∥
≡
(
E
0
t
E
0
i
)
∥
=
2
n
i
cos
θ
i
n
t
cos
θ
i
+
n
i
cos
θ
t
Lets put these equations to work and figure out something practical. Consider
light reflecting off a surface, such as the road in front of you when you are
driving a car. The light hitting the road surface can have any polarization
but that will be some addition of light that has
E
⃗
E
⃗
⊥
⊥
and
∥
∥
to the plane of incidence. From
r
∥
≡
(
E
0
r
E
0
i
)
∥
=
n
t
cos
θ
i
−
n
i
cos
θ
t
n
t
cos
θ
i
+
n
i
cos
θ
t
r
∥
≡
(
E
0
r
E
0
i
)
∥
=
n
t
cos
θ
i
−
n
i
cos
θ
t
n
t
cos
θ
i
+
n
i
cos
θ
t
and
r
⊥
≡
(
E
0
r
E
0
i
)
⊥
=
n
i
cos
θ
i
−
n
t
cos
θ
t
n
i
cos
θ
i
+
n
t
cos
θ
t
r
⊥
≡
(
E
0
r
E
0
i
)
⊥
=
n
i
cos
θ
i
−
n
t
cos
θ
t
n
i
cos
θ
i
+
n
t
cos
θ
t
we see there is an angle where there is no
∥
∥
and only
⊥
⊥
light, namely
n
t
cos
θ
i
−
n
i
cos
θ
t
=
0
n
t
cos
θ
i
−
n
i
cos
θ
t
=
0
or
n
t
cos
θ
i
=
n
i
cos
θ
t
.
n
t
cos
θ
i
=
n
i
cos
θ
t
.
Now we can use Snell's law rewritten as
sin
θ
i
n
t
=
sin
θ
t
n
i
sin
θ
i
n
t
=
sin
θ
t
n
i
and multiply both sides to get
n
t
cos
θ
i
=
n
i
cos
θ
t
n
t
cos
θ
i
=
n
i
cos
θ
t
n
t
cos
θ
i
sin
θ
i
n
t
=
n
i
cos
θ
t
sin
θ
t
n
i
n
t
cos
θ
i
sin
θ
i
n
t
=
n
i
cos
θ
t
sin
θ
t
n
i
cos
θ
i
sin
θ
i
=
cos
θ
t
sin
θ
t
cos
θ
i
sin
θ
i
=
cos
θ
t
sin
θ
t
which can only be true if
θ
t
=
π
/
2
−
θ
i
.
θ
t
=
π
/
2
−
θ
i
.
In this case Snell's law can be written
n
t
n
i
=
sin
θ
i
sin
θ
t
=
sin
θ
i
sin
(
π
/
2
−
θ
i
)
=
tan
θ
i
n
t
n
i
=
sin
θ
i
sin
θ
t
=
sin
θ
i
sin
(
π
/
2
−
θ
i
)
=
tan
θ
i
The angle that gives this effect is known as Brewster's angle
θ
i
≡
θ
B
r
e
w
s
t
e
r
=
tan
−
1
n
t
n
i
θ
i
≡
θ
B
r
e
w
s
t
e
r
=
tan
−
1
n
t
n
i
At this angle light is completely polarized, it only has
E
⃗
E
⃗
⊥
⊥
to the plane of incidence (or parallel to the surface). Thus the glare you get
from reflected light tends to be polarized in this way. In 1929 Edwin Land
invented a method for making celluoid filters to filter out light with given
polarizations. He then manufactured sunglasses with these polarizers lined up
to filter out the
E
⊥
E
⊥
light and thereby reduce glare.
Look at the Fresnel equations again and examine what happens when
θ
i
θ
i
approaches 90 degrees. The reflection approaches 1 (ignore the signs) Thus at
Glancing incidence you get lots of reflection. In fact X-ray telescopes use
this to focus the x-rays onto their detector.
Another effect, if
n
i
>
n
t
n
i
>
n
t
then there is an angle of incidence beyond which light is only reflected. That
is the angle where
θ
t
=
90
θ
t
=
90
degrees.
n
t
sin
θ
t
=
n
i
sin
θ
i
n
t
sin
θ
t
=
n
i
sin
θ
i
θ
t
→
π
/
2
θ
t
→
π
/
2
sin
θ
t
→
1
sin
θ
t
→
1
sin
θ
i
→
n
t
n
i
sin
θ
i
→
n
t
n
i
The critical angle at which this occurs is
θ
c
=
sin
−
1
n
t
n
i
θ
c
=
sin
−
1
n
t
n
i