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  <name>Eyeglasses</name>
  <metadata>
  <md:version>1.1</md:version>
  <md:created>2005/10/26 13:03:43.835 GMT-5</md:created>
  <md:revised>2005/10/26 13:05:12.772 GMT-5</md:revised>
  <md:authorlist>
      <md:author id="padley">
      <md:firstname>Paul</md:firstname>
      
      <md:surname>Padley</md:surname>
      <md:email>padley@rice.edu</md:email>
    </md:author>
  </md:authorlist>

  <md:maintainerlist>
    <md:maintainer id="padley">
      <md:firstname>Paul</md:firstname>
      
      <md:surname>Padley</md:surname>
      <md:email>padley@rice.edu</md:email>
    </md:maintainer>
  </md:maintainerlist>
  
  <md:keywordlist>
    <md:keyword>Eyeglasses</md:keyword>
    <md:keyword>Geometric Optics</md:keyword>
  </md:keywordlist>

  <md:abstract>Some notes about eyeglasses</md:abstract>
</metadata>
  <content>
<para id="id30752482">
   First a little nomenclature. Optometrists (and opthamologists) use the
   dioptric power measured in diopters. A diopter is
   <m:math display="inline">
     <m:mrow>
       <m:mn>1</m:mn>
       <m:mo form="infix">/</m:mo>
       <m:mi>f</m:mi>
     </m:mrow>
   </m:math>
   where f is measured in meters. The focal length of lenses in contact is
   <m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:msub>
             <m:mi>f</m:mi>
             <m:mn>1</m:mn>
           </m:msub>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:msub>
             <m:mi>f</m:mi>
             <m:mn>2</m:mn>
           </m:msub>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>
   or using dioptric power
   <m:math mode="display" display="block">
     <m:mrow>
       <m:mi>D</m:mi>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:msub>
           <m:mi>D</m:mi>
           <m:mn>1</m:mn>
         </m:msub>
         <m:mo form="infix">+</m:mo>
         <m:msub>
           <m:mi>D</m:mi>
           <m:mn>2</m:mn>
         </m:msub>
       </m:mrow>
     </m:mrow>
   </m:math>
   A "normal" eye will focus an object at infinity onto the retina with
   the lens relaxed. As objects come closer the lens of the eye is made to bulge
   to keep the object in focus. A nearsighted person (such as certain
   Phys 201 prof's) has an eye that focuses the object at infinity in front of
   the retina. This person has a far point beyond which things are focused
   incorrectly. By using a lens that casts the object at infinity onto the far
   point this problem can be corrected. Say someone's far point is at 2m. In this
   case we want
   <m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:msub>
             <m:mi>s</m:mi>
             <m:mi>o</m:mi>
           </m:msub>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:msub>
             <m:mi>s</m:mi>
             <m:mi>i</m:mi>
           </m:msub>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math><m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mi>∞</m:mi>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mrow>
             <m:mo form="prefix">−</m:mo>
             <m:mn>2</m:mn>
           </m:mrow>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>
   a corrective lens with
   <m:math display="inline">
     <m:mrow>
       <m:mi>f</m:mi>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mrow>
           <m:mo form="prefix">−</m:mo>
           <m:mn>2</m:mn>
         </m:mrow>
         <m:mo/>
         <m:mi>m</m:mi>
       </m:mrow>
     </m:mrow>
   </m:math>
   or
   <m:math display="inline">
     <m:mrow>
       <m:mi>D</m:mi>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mo form="prefix">−</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mn>2</m:mn>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>Diopters.
   Notice that the desired focal length is the far point (with the correct choice
   of sign)Of course in practice we need to take into account the
   distance between the glasses and the eye, but the above is valid for a contact
   lens. In the case of eyeglasses you need to subtract off the distance
   between the lense and the eye. For example if the distance between the eye and
   the glasses is 2cm then the above
   becomes<m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mi>∞</m:mi>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mrow>
             <m:mo form="prefix">−</m:mo>
             <m:mn>1.98</m:mn>
           </m:mrow>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>
</para>
<para id="id35014065">
   
</para>
<para id="id15976259">
   A far sighted person focuses objects at infinity behind the retina. Their eye
   can accommodate the object at infinity but they have trouble with nearby
   points. A normal eye should be able to focus objects as close as 25cm. A far
   sighted person can focus to a near point that is greater than 25cm and so we
   need to take the 25cm point and make it look like it is at the near point. Say
   some one has a near point of 125cm then
   <m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mrow>
             <m:mo form="prefix">−</m:mo>
             <m:mn>1.25</m:mn>
           </m:mrow>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mn>.25</m:mn>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>
   which is
   <m:math display="inline">
     <m:mrow>
       <m:mo form="prefix">+</m:mo>
       <m:mn>3.2</m:mn>
     </m:mrow>
   </m:math>Diopters.   Of
   course again we should correct for the distance between the glasses and the
   eye, which if that is 2cm makes the
   equation:<m:math mode="display" display="block">
     <m:mrow>
       <m:mfrac>
         <m:mn>1</m:mn>
         <m:mi>f</m:mi>
       </m:mfrac>
       <m:mo form="infix">=</m:mo>
       <m:mrow>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mrow>
             <m:mo form="prefix">−</m:mo>
             <m:mn>1.23</m:mn>
           </m:mrow>
         </m:mfrac>
         <m:mo form="infix">+</m:mo>
         <m:mfrac>
           <m:mn>1</m:mn>
           <m:mn>.23</m:mn>
         </m:mfrac>
       </m:mrow>
     </m:mrow>
   </m:math>
   Finally their are old guys like me who need bifocals.  As one ages, the eye
   lens becomes more rigid and it is harder and harder for it to deform and focus
   on close in objects.  Then if you are also nearsighted, then you have to
   resort to bifocals.
</para>
</content>
</document>
