- Definition 1:
t Distribution
If
Z is a random variable that is
N(
0,1
)
N(
0,1
)
, if
U is a random variable that is
χ
2
(
r
)
χ
2
(
r
)
, and if
Z and
U are independent, then
T=
Z
U/r
=
X
¯
−μ
S/
n
T=
Z
U/r
=
X
¯
−μ
S/
n
(1)
has a
t distribution with
r degrees of freedom.
Where
μ
μ
is the population mean,
x
¯
x
¯
is the sample mean and s is the estimator for population standard deviation (i.e., the sample variance) defined by
s
2
=
1
N−1
∑
i=1
N
(
x
i
−
x
¯
)
2
.
s
2
=
1
N−1
∑
i=1
N
(
x
i
−
x
¯
)
2
.
(2)
If
σ=s
σ=s
,
t=z
t=z
, the distribution becomes the normal distribution. As N increases, Student’s t distribution approaches
the normal distribution. It can be derived by transforming student’s z-distribution using
z≡
x
¯
−μ
s
z≡
x
¯
−μ
s
and then defining
t=z
n−1
.
t=z
n−1
.
The resulting probability and cumulative distribution functions are:
f(
t
)=
Γ[
(
r+1
)/2
]
πr
Γ(
r/2
)
(
1+
t
2
/r
)
(
r+1
)/2
,
f(
t
)=
Γ[
(
r+1
)/2
]
πr
Γ(
r/2
)
(
1+
t
2
/r
)
(
r+1
)/2
,
(3)
F(
t
)=
1
2
+
1
2
[
I(
1;
1
2
r,
1
2
)−I(
r
r+
t
2
,
1
2
r,
1
2
)
]sgn(
t
)=
1
2
−
itB(
−
t
2
r
;
1
2
,
1
2
(
1−r
)
)Γ(
1
2
(
r+1
)
)
2
π
| t |Γ(
1
2
r
)
F(
t
)=
1
2
+
1
2
[
I(
1;
1
2
r,
1
2
)−I(
r
r+
t
2
,
1
2
r,
1
2
)
]sgn(
t
)=
1
2
−
itB(
−
t
2
r
;
1
2
,
1
2
(
1−r
)
)Γ(
1
2
(
r+1
)
)
2
π
| t |Γ(
1
2
r
)
(4)
where,
-
r=n−1
r=n−1
is the number of degrees of freedom,
-
−∞<t<∞,
−∞<t<∞,
-
Γ(
z
)
Γ(
z
)
is the gamma function,
-
B(
a,b
)
B(
a,b
)
is the bets function,
-
I(
z;a,b
)
I(
z;a,b
)
is the regularized beta function defined by
I(
z;a,b
)=
B(
z;a,b
)
B(
a,b
)
.
I(
z;a,b
)=
B(
z;a,b
)
B(
a,b
)
.
The effect of degree of freedom on the t distribution is illustrated in the four t distributions on the Figure 1.
In general, it is difficult to evaluate the distribution function of T. Some values are usually given in the tables. Also observe that the graph of the p.d.f. of T is symmetrical with respect to the vertical axis t =0 and is very similar to the graph of the p.d.f. of the standard normal distribution
N(
0,1
)
N(
0,1
)
. However the tails of the t distribution are heavier that those of a normal one; that is, there is more extreme probability in the t distribution than in the standardized normal one.
Because of the symmetry of the t distribution about t =0, the mean (if it exists) must be equal to zero. That is, it can be shown that
E(
T
)=0
E(
T
)=0
when
r≥2
r≥2
. When r=1 the t distribution is the Cauchy distribution, and thus both the variance and mean do not exist.