Analyze the following lines of code. Refer to Two's Complement and Fractional Arithmetic for 16-bit Processors, Addressing Modes for TI TMS320C55x, and the Mnemonic Instruction Set manual for help.

	1  FIR_len .set    3
        2
	3  ; Assume: 
	4  ;   BK03 = FIR_len
	5  ;   firStateIndex is stored at memory location 1008h 
	6  ;   AR2 = 1000h
	7  ;   AR3 = 1004h
	8  ;   FRCT = 1
        9
	10      BSET	AR3LC		; sets circular addressing for AR3
        11      mov  mmap(AR3), BSA23
        12      mov  #firStateIndex, AR4
        13      mov  *AR4, AR3
	14      mov     LO(AC0),*AR3+
        15      mov     #0, AC0
	16      rpt    #(FIR_len-1)
	17      macm     *AR2+,*AR3+,AC0
	
      

Anything following a ";" is considered a comment. In this case, the comments indicate the contents of the auxiliary registers, the BK03 register, and the address registers before the execution of the first instruction, mov. The line FIR_len .set 3 defines the name FIR_len as equal to 3. The BK03 register contains the length of the circular buffer we want to use for auxiliary register 0 through 3. The BSET AR3LC modifies the increment operator + so that it behaves as a circular buffer. This means circular addressing will be used for AR3. Refer to Section 6.11 of the CPU Reference Guide for help on circular addressing.

Note that any number followed by an "h" or preceded with a 0x represents a hexadecimal value.

Assume that the data memory is initialized as follows starting at location 1000h.

After familiarizing yourself with the mov, rpt, and macm instructions, step through each line of code and record the values of the accumulator AC0 and auxiliary registers AR2 and AR3 in the spaces provided in Figure 2. Additionally, record the value of the memory contents after all three instructions have been "executed" in the blank data memory table in (Reference).

When working through the exercise, take into account that the accumulator AC0 is a 40-bit register, and that the multiplier is in the fractional arithmetic mode. In this mode, integers on the DSP are interpreted as fractions, and the multiplier will treat them accordingly. This is done by shifting the result of the integer multiplier in the ALU left one bit. (All the arithmetic is fractional in these examples.) Multiplies performed by the ALU (via the macm instruction) produce a result that is twice what you would expect if you just multiplied the two integers together. DSP numerical representation and arithmetic are described further in Two's Complement and Fractional Arithmetic for 16-bit Processors.