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<document xmlns="http://cnx.rice.edu/cnxml" xmlns:md="http://cnx.rice.edu/mdml/0.4" xmlns:m="http://www.w3.org/1998/Math/MathML" xmlns:bib="http://bibtexml.sf.net/" id="id10375979">
  <name>Kai and Mai Spread Data</name>
  <metadata>
  <md:version>1.1</md:version>
  <md:created>2008/06/11 16:53:22.121 GMT-5</md:created>
  <md:revised>2008/06/20 13:43:15.133 GMT-5</md:revised>
  <md:authorlist>
      <md:author id="IMP2">
      <md:firstname/>
      
      <md:surname>IMP</md:surname>
      <md:email>cosborne@keypress.com</md:email>
    </md:author>
  </md:authorlist>

  <md:maintainerlist>
    <md:maintainer id="IMP2">
      <md:firstname/>
      
      <md:surname>IMP</md:surname>
      <md:email>cosborne@keypress.com</md:email>
    </md:maintainer>
    <md:maintainer id="KCP">
      <md:firstname/>
      
      <md:surname>Key</md:surname>
      <md:email>cosborne@keypress.com</md:email>
    </md:maintainer>
  </md:maintainerlist>
  
  <md:keywordlist>
    <md:keyword>IMP Year 1</md:keyword>
    <md:keyword>The Pit and the Pendulum</md:keyword>
  </md:keywordlist>

  <md:abstract/>
</metadata>
  <content>
    <section id="id-1110714651">
      <name>Intent </name>
      <para id="id7562830">Students continue exploring methods to measure the spread of a data set. In this activity, they calculate the sum of the absolute deviations from the mean.</para>
    </section>
    <section id="id-347467748863">
      <name>Mathematics </name>
      <para id="id11283802">As a measure of spread, the sum of absolute deviations from the mean has an advantage over the range in that it uses every data value, or datum, in a set. The sum of the absolute deviations divided by the number of data values is called the <term><cnxn document="m15620">mean absolute deviation</cnxn></term>. This statistic gives the average deviation from the mean of each data value.</para>
    </section>
    <section id="id-338480905438">
      <name>Progression</name>
      <para id="id12226336">Students will work individually on the activity and then share ideas and discuss the concepts of <emphasis>absolute value</emphasis> and <emphasis>mean absolute deviation</emphasis> as a class.</para>
    </section>
    <section id="id-331966930955">
      <name>Approximate Time</name>
      <para id="id11718547">25 minutes for activity (at home or in class)</para>
      <para id="id12434194">25 minutes for discussion </para>
    </section>
    <section id="id-832723108811">
      <name>Classroom Organization </name>
      <para id="id12298061">Individuals or groups, followed by whole-class discussion</para>
    </section>
    <section id="id-0724679530263">
      <name>Doing the Activity</name>
      <para id="id12226185">Assign this activity immediately after the discussion of <emphasis>Data Spread</emphasis>.</para>
    </section>
    <section id="id-0538111474728">
      <name>Discussing and Debriefing the Activity</name>
      <para id="id12912288">You might have students convene in their groups to compare their personal schemes for measuring spread (Question 4) as well as the numeric results from the various methods. Then ask each group to report on the method they like best.</para>
      <para id="id11409200">If students had trouble finding the appropriate numbers for each data set for Tai’s, Kai’s, and Mai’s methods, review the mechanics of each method.</para>
      <para id="id12298967">Then have the class discuss this question: <term>Which data set seems to be the most spread out from the mean? </term>The decision does not have to be made based on a statistical test, and the class need not reach agreement. Focus the discussion on <emphasis>why</emphasis> the class thinks a particular set is the most spread out.</para>
      <para id="id13073460">You might ask why students think Mai chose to remove the highest and lowest values. One possible reason is that Mai wants to eliminate the possibility of one or two extreme values skewing the results. If there are any competitive divers in class, you might ask about the scoring for diving competitions (the highest and lowest scores are not considered).</para>
      <para id="id10515934">Discussion of spread from the mean provides a nice opportunity to talk about <term><cnxn document="m15620">absolute value</cnxn></term>. For example, ask someone to describe how to apply Kai’s method to data set C: 12, 13, 13, 27, 27, 28. Use values above and below the mean (which is 20) to illustrate that in some cases you subtract the mean from the data item and in other cases you subtract the data item from the mean.</para>
      <para id="id10437419">Then ask, <term>How could you find the distance from the mean the same way in all cases?</term> If needed, suggest that students consider the idea of absolute value. Point out that |<emphasis>x</emphasis> – 20| (or |20 – <emphasis>x</emphasis>|) always gives a positive answer and measures how far a number <emphasis>x</emphasis> is from 20, whether <emphasis>x </emphasis>is greater than 20 or less than 20.</para>
      <para id="id11351082">Introduce the symbol
<m:math><m:semantics><m:mrow><m:mstyle fontsize="12pt"><m:mrow><m:mover accent="true"><m:mi>x</m:mi><m:mo stretchy="false">ˉ</m:mo></m:mover></m:mrow></m:mstyle><m:mrow/></m:mrow><m:annotation encoding="StarMath 5.0"> size 12{ { bar  {x}}} {}</m:annotation></m:semantics></m:math> (read “<emphasis>x</emphasis> bar”) for the mean, and use notation such as <emphasis>xi</emphasis> for a single piece of data. Then ask how one could write Kai’s method using this notation and the summation symbol.</para>
      <para id="id11688988">Students often enjoy seeing all this notation put together, using the summation notation developed in the <emphasis>Patterns</emphasis> unit, as</para>
      <para id="id11812409">
        <m:math>
          <m:semantics>
            <m:mrow/>
            <m:annotation encoding="StarMath 5.0">{}</m:annotation>
          </m:semantics>
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        <m:math>
          <m:semantics>
            <m:mrow>
              <m:mstyle fontsize="12pt">
                <m:mrow>
                  <m:mrow>
                    <m:munderover>
                      <m:mo stretchy="false">∑</m:mo>
                      <m:mstyle fontsize="8pt">
                        <m:mrow>
                          <m:mrow>
                            <m:mi>i</m:mi>
                            <m:mo stretchy="false">=</m:mo>
                            <m:mn>1</m:mn>
                          </m:mrow>
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                      <m:mstyle fontsize="8pt">
                        <m:mrow>
                          <m:mi>n</m:mi>
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                    <m:mrow>
                      <m:mo stretchy="false">∣</m:mo>
                      <m:mrow>
                        <m:msub>
                          <m:mi>x</m:mi>
                          <m:mstyle fontsize="8pt">
                            <m:mrow>
                              <m:mi>i</m:mi>
                            </m:mrow>
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                        </m:msub>
                        <m:mo stretchy="false">−</m:mo>
                        <m:mover accent="true">
                          <m:mi>x</m:mi>
                          <m:mo stretchy="false">ˉ</m:mo>
                        </m:mover>
                      </m:mrow>
                      <m:mo stretchy="false">∣</m:mo>
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            </m:mrow>
            <m:annotation encoding="StarMath 5.0"> size 12{ Sum cSub { size 8{i=1} }  cSup { size 8{n} }  { lline x rSub { size 8{i} } - { bar  {x}} rline } } {}</m:annotation>
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      </para>
      <para id="id10641102">Later you can compare this notation with the symbolic formula for standard deviation.</para>
      <para id="id11750475">Point out that, if Kai’s number is divided by <emphasis>n</emphasis>, it gives the <emphasis>average deviation</emphasis> from the mean; it tells, <emphasis>on the average,</emphasis> how far the numbers in a set are from their mean. Introduce the term <term><cnxn document="m15620">mean absolute deviation</cnxn></term> for this average, and have students express it using summation notation as</para>
      <para id="id8725087">
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                              <m:mi>i</m:mi>
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                              <m:mn>1</m:mn>
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                          <m:mrow>
                            <m:mi>n</m:mi>
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                        <m:mo stretchy="false">∣</m:mo>
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                            <m:mi>x</m:mi>
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                                <m:mi>i</m:mi>
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                          <m:mo stretchy="false">−</m:mo>
                          <m:mover accent="true">
                            <m:mi>x</m:mi>
                            <m:mo stretchy="false">ˉ</m:mo>
                          </m:mover>
                        </m:mrow>
                        <m:mo stretchy="false">∣</m:mo>
                      </m:mrow>
                    </m:mrow>
                    <m:mi>n</m:mi>
                  </m:mfrac>
                </m:mrow>
              </m:mstyle>
              <m:mrow/>
            </m:mrow>
            <m:annotation encoding="StarMath 5.0"> size 12{ {  { Sum cSub { size 8{i=1} }  cSup { size 8{n} }  { lline x rSub { size 8{i} } - { bar  {x}} rline } }  over  {n} } } {}</m:annotation>
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          <m:semantics>
            <m:mrow/>
            <m:annotation encoding="StarMath 5.0">{}</m:annotation>
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      </para>
      <para id="id11285747">Try to get students to articulate what this expression measures. It is a simplified version of what <term><cnxn document="m15620">standard deviation</cnxn></term> will tell them, which they will learn about next.</para>
      <para id="id12240233">Students will need their work on <emphasis>Kai and Mai Spread Data</emphasis> for use during the next activity, <emphasis>The Best Spread</emphasis>.</para>
    </section>
    <section id="id-340149235102">
      <name>Key Questions</name>
      <para id="id10569650">
        <term>Which data set seems to be the most spread out from the mean?</term>
      </para>
      <para id="id12297138">
        <term>How could you find the distance from the mean the same way in all cases?</term>
      </para>
    </section>
  </content>
</document>
