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limites

Module by: diego diaz torres. E-mail the author

Summary: limites

lim x → 3 = 2 x 2 - 2 x - 12 x 2 + 4 x - 21 lim x → 3 = 2 x 2 - 2 x - 12 x 2 + 4 x - 21
(1)
⇒ lim x → 3 = ( x - 3 x + 2 x + 7 ( x - 3 = x + 2 x + 7 lim x → 3 = ( 3 + 2 3 + 7 = lim x → 3 = 1 2 ⇒ lim x → 3 = ( x - 3 x + 2 x + 7 ( x - 3 = x + 2 x + 7 lim x → 3 = ( 3 + 2 3 + 7 = lim x → 3 = 1 2
(2)

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