I’m sure you remember the quadratic formula: x
=
−b±b2−4ac2ax=−b±b2−4ac2a size 12{ { { - b +- sqrt {b rSup { size 8{2} } - 4 ital "ac"} } over {2a} } } {}. Back when we were doing quadratic equations, if we wound up with a negative number under that square root, we just gave up. But now we can solve these equations!
Use the quadratic formula to solve:
2
x
2
+
6
x
+
5
=
0
2
x
2
+6x+5=0.
Use the quadratic formula to solve:
x
2
-
2
x
+
5
=
0
x
2
-2x+5=0.
Check one of your answers to #2.
Solve by completing the square:
2
x
2
+
10
x
+
17
=
0
2
x
2
+10x+17=0.
- a. In general, what has to be true for a quadratic equation to have two non-real roots?
- b. What is the relationship between the two non-real roots?
- c. Is it possible to have a quadratic equation with one non-real root?
"This is the "main" book in Kenny Felder's "Advanced Algebra II" series. This text was created with a focus on 'doing' and 'understanding' algebra concepts rather than simply hearing about them in […]"