A complex number is written in the form
a
+
b
i
a+bi where
a
a and
b
b are real numbers.
a
a is the “real part” and
b
i
bi is the “imaginary part.”
Examples are:
3
+
4
i
3+4i (
aa is 3,
b
b is 4) and
3
–
4
i
3–4i (
a
a is 3,
b
b is –4).
Is 4 a complex number? If so, what are
a
a and
b
b? If not, why not?
Is
i
i a complex number? If so, what are
a
a and
b
b? If not, why not?
Is
0
0 a complex number? If so, what are
a
a and
b
b? If not, why not?
All four operations—addition, subtraction, multiplication, and division—can be done to complex numbers, and the answer is always another complex number. So, for the following problems, let
X=3+4i
X
3
4
i
and
Y=5−12i
Y
5
12
i
. In each case, your answer should be a complex number, in the form
a+bi
a
b
i
.
Divide:
X
/
Y
X/Y. (*To get the answer in
a
+
b
i
a+bi form, you will need to use a trick we learned yesterday.)
The complex conjugate of a complex number
a+bi
a
b
i
is defined as
a−bi
a
b
i
. That is, the real part stays the same, and the imaginary part switches sign.
What is the complex conjugate of
(
5
–
12
i
)
(5–12i)?
What do you get when you multiply
(
5
–
12
i
)
(5–12i) by its complex conjugate?
Where have we used complex conjugates before?
For two complex numbers to be equal, there are two requirements: the real parts must be the same, and the imaginary parts must be the same. In other words,
2
+
3
i
2+3i is only equal to
2
+
3
i
2+3i. It is not equal to
2
+
3
i
2+3i or to
3
+
2
i
3+2i or to anything else. So it is very easy to see if two complex numbers are the same, as long as they are both written in
a
+
b
i
a+bi form: you just set the real parts equal, and the imaginary parts equal. (If they are not written in that form, it can be very tricky to tell: for instance, we saw earlier that
1i1i size 12{ { {1} over {i} } } {} is the same as
–i–i!)
If
2
+
3
i
=
m
+
n
i
2+3i=m+ni, and mm and
nn are both real numbers, what are mm and nn?
Solve for the real numbers xx and yy:
(
x
–
6
y
)
+
(
x
+
2
y
)
i
=
1
–3
i
(x–6y)+(x+2y)i=1–3i
Finally, remember…rational expressions? We can have some of those with complex numbers as well!
4+2i3+2i5−3i7−i4+2i3+2i5−3i7−i size 12{ { { left ( { {4+2i} over {3+2i} } right )} over { left ( { {5 - 3i} over {7 - i} } right )} } } {} Simplify. As always, your answer should be in the form
a
+
b
i
a+bi.
4+2i3+2i−5−3i7−i4+2i3+2i−5−3i7−i size 12{ { {4+2i} over {3+2i} } - { {5 - 3i} over {7 - i} } } {} Simplify.
"This is the "main" book in Kenny Felder's "Advanced Algebra II" series. This text was created with a focus on 'doing' and 'understanding' algebra concepts rather than simply hearing about them in […]"