Now, let’s try going backward. Rewrite the following expressions as
(x+something)2(x+something)2 size 12{ \( x+"something" \) rSup { size 8{2} } } {}, or as
(x−something)2(x−something)2 size 12{ \( x - "something" \) rSup { size 8{2} } } {}, or as
(x+something)(x−something)(x+something)(x−something) size 12{ \( x+"something" \) \( x - "something" \) } {}. In each case, check your answer by multiplying back to see if you get the original expression.
- a. x2−8x+16=x2−8x+16= size 12{x rSup { size 8{2} } - 8x+"16"={}} {} ____________
- Check by multiplying back: _______________
- b. x2−25=x2−25= size 12{x rSup { size 8{2} } - "25"={}} {} ____________
- Check by multiplying back: _______________
- c. x2+2x+1=x2+2x+1= size 12{x rSup { size 8{2} } +2x+1={}} {} ____________
- Check by multiplying back: _______________
- d. x2−20x+100=x2−20x+100= size 12{x rSup { size 8{2} } - "20"x+"100"={}} {} ____________
- Check by multiplying back: _______________
- e. 4x2−9=4x2−9= size 12{4x rSup { size 8{2} } - 9={}} {} ____________
- Check by multiplying back: _______________
"This is the "main" book in Kenny Felder's "Advanced Algebra II" series. This text was created with a focus on 'doing' and 'understanding' algebra concepts rather than simply hearing about them in […]"