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Sample Test: 2 Equations and 2 Unknowns

Module by: Kenny M. Felder. E-mail the author

Summary: A sample test on solving simultaneous equations.

Exercise 1

Evan digs into his pocket to see how much pizza he can afford. He has $3.00, exactly enough for two slices. But it is all in dimes and nickels! Counting carefully, Evan discovers that he has twice as many dimes as nickels.

  • a. Identify and clearly label the variables.
  • b. Write two equations that represent the two statements in the question.
  • c. Solve these equations to find how many nickels and dimes Evan has.

Exercise 2

Black Bart and the Sheriff are having a gunfight at high noon. They stand back to back, and start walking away from each other: Bart at 4 feet per second, the Sheriff at 6 feet per second. When they turn around to shoot, they find that they are 55 feet away from each other.

Figure 1
Picture of the hypothetical duel in the example.
  • a. Write the equation d=rtd=rt size 12{d= ital "rt"} {} for Bart.
  • b. Write the equation d=rtd=rt size 12{d= ital "rt"} {} for the Sheriff.
  • c. Solve, to answer the question: for how long did they walk away from each other?
  • d. How far did Bart walk?

Exercise 3

Mrs. Verbatim the English teacher always assigns 5 short stories (2,000 words each) for every novel (60,000 words each) that she assigns. This year she has decided to assign a total of 350,000 words of reading to her students. How many books and how many short stories should she select?

  • a. Identify and clearly label the variables.
  • b. Write two equations that represent the two conditions that Mrs. V imposed.
  • c. Solve these equations to find the number of works she will be assigning.

Exercise 4

Solve by graphing. Answers may be approximate. (But use the graph paper and get as close as you can.)

y = x 2 3 y = x 2 3 size 12{y=x rSup { size 8{2} } - 3} {}

y = x + 2 y = x + 2 size 12{y= - lline x rline +2} {}

Exercise 5

Solve, using substitution.

3x + y = 2 3x + y = 2 size 12{3x+y= - 2} {}

6x 2y = 12 6x 2y = 12 size 12{6x - 2y="12"} {}

Exercise 6

Solve, using elimination.

2x + 3y = 11 2x + 3y = 11 size 12{2x+3y= - "11"} {}

3x 6y = 4 3x 6y = 4 size 12{3x - 6y=4 { size 8{1} } wideslash { size 8{2} } } {}

Exercise 7

Solve any way you like.

2x = 6y + 12 2x = 6y + 12 size 12{2x=6y+"12"} {}

x 9 = 3y x 9 = 3y size 12{x - 9=3y} {}

Exercise 8

Solve any way you like.

2y + 3x = 20 2y + 3x = 20 size 12{2y+3x="20"} {}

y + x = 6 y + x = 6 size 12{ { size 8{1} } wideslash { size 8{2} } y+x=6} {}

Exercise 9

  • a. Solve for xx size 12{x} {}. (*No credit without showing your work!)

ax + by = e ax + by = e size 12{ ital "ax"+ ital "by"=e} {}

cx + dy = f cx + dy = f size 12{ ital "cx"+ ital "dy"=f} {}

  • b. Use the formula you just derived to find xx size 12{x} {} in these equations.

3x + 4y = 7 3x + 4y = 7 size 12{3x+4y=7} {}

2x + 3y = 11 2x + 3y = 11 size 12{2x+3y="11"} {}

Extra credit:

Redo #9. If you used elimination before, use substitution. If you used substitution, use elimination.

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