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Phasors: Lissajous Figures

Module by: Louis Scharf. E-mail the author

Note:

This module is part of the collection, A First Course in Electrical and Computer Engineering. The LaTeX source files for this collection were created using an optical character recognition technology, and because of this process there may be more errors than usual. Please contact us if you discover any errors.

Lissajous figures are figures that are turned out on the face of an oscilloscope when sinusoidal signals with different amplitudes and different phases are applied to the time base (real axis) and deflection plate (imaginary axis) of the scope. The electron beam that strikes the phosphorous face then had position

z(t)=Axcos(ωt+φx)+jAycos(ωt+φy).z(t)=Axcos(ωt+φx)+jAycos(ωt+φy). (1)

In this representation, Axcos(ωt+φx)Axcos(ωt+φx) is the “x-coordinate of the point,” and Aycos(ωt+φ)Aycos(ωt+φ) is the “y-coordinate of the point.” As time runs from 0 to infinity, the point z(t)z(t) turns out a trajectory like that of Figure 1. The figure keeps overwriting itself because z(t)z(t) repeats itself every 2πω2πω seconds. Do you see why?

Figure 1: Lissajous Figure on Oscilloscope Screen
Figure one is a cartesian graph with horizontal axis labeled Re and vertical axis labeled Im. On the graph is an oval-shaped curve centered about the origin diagonally with its longer portions sticking into the third and first quadrant. In the first quadrant, a point on the oval indicates movement in the counter-clockwise direction with an arrow pointing towards the bottom-left of the screen, and is labeled z(t).

Exercise 1

Find the intercepts that the Lissajous figure makes with the real and imaginary axes in Figure 1. At what values of time are these intercepts made?

Exercise 2

Show that the Lissajous figure z(t)=Axcos(ωt+φx)+z(t)=Axcos(ωt+φx)+jAycos(ωt+φy)jAycos(ωt+φy) is just the rotating phasor Aej(ωt+φ)Aej(ωt+φ) when Ax=Ay=AAx=Ay=A, φx=φφx=φ, and φy=φ+π2φy=φ+π2.

Two-Phasor Representation. We gain insight into the shape of the Lissajous figure if we use Euler's formulas to write z(t)z(t) as follows:

z ( t ) = A x 2 [ e j ( ω t + φ x ) + e - j ( ω t + φ x ) ] + j A y 2 [ e j ( ω t + φ y ) + e - j ( ω t + φ y ) ] = [ A x e j φ x + j A y e j φ y 2 ] e j ω t + [ A x e - j φ x + j A y e - j φ y 2 ] e - j ω t . z ( t ) = A x 2 [ e j ( ω t + φ x ) + e - j ( ω t + φ x ) ] + j A y 2 [ e j ( ω t + φ y ) + e - j ( ω t + φ y ) ] = [ A x e j φ x + j A y e j φ y 2 ] e j ω t + [ A x e - j φ x + j A y e - j φ y 2 ] e - j ω t . (2)

This representation is illustrated in Figure 2. It consists of two rotating phasors, with respective phasors B 1 B 1 and B 2 B 2 :

z(t)=B1ejωt+B2e-jωt B 1 = A x e j φ x + j A y e j φ y 2 B 2 = A x e - j φ x + j A y e - j φ y 2 z(t)=B1ejωt+B2e-jωt B 1 = A x e j φ x + j A y e j φ y 2 B 2 = A x e - j φ x + j A y e - j φ y 2 (3)
Figure 2: Two-Phasor Representation of a Lissajous Figure
Figure two is a cartesian graph with six arrows beginning at the origin and pointing away in various directions. The first points with a shallow negative slope into the fourth quadrant, and is labeled A_x/2 e^(-jΦ_x). The second extends into the first quadrant with a shallow positive slope and is labeled A_x/2 e^(jΦ_x). The third arrow extends into the first quadrant with a slightly stronger positive slope than the second arrow, and is labeled B_2. Across this arrow is a small direction arrow indicating movement in the clockwise direction. The fourth arrow extends into the first quadrant with a much stronger positive slope than the third and second arrows, and is labeled B_1. Across this arrow is a direction arrow indicating movement in the counter-clockwise direction. The fifth arrow extends into the first quadrant with an even stronger positive slope than the fourth, and is labeled j(A_y/2) e^(-jΦ_y). The sixth and final arrow extends into the second quadrant with a very sharp negative slope, and is labeled  j(A_y/2) e^(jΦ_y)

As t t increases, the phasors rotate past each other where they constructively add to produce large excursions of z(t)z(t) from the origin, and then they rotate to antipodal positions where they destructively add to produce near approaches of z(t)z(t) to the origin.

In electromagnetics and optics, the representations of z(t)z(t) given in Equation 1 and Equation 3 are called, respectively, linear and circular representations of elliptical polarization. In the linear representation, the x x- and y y-components of zz vary along the horizontal and vertical lines. In the circular representation, two phasors rotate in opposite directions to turn out circular trajectories whose sum produces the same effect.

Exercise 3

(MATLAB) Write a MATLAB program to compute and plot the Lissajous figure z(t)z(t) when Ax=1/2,Ay=1,φx=0Ax=1/2,Ay=1,φx=0, and φy=π/6φy=π/6. Discretize t t appropriately and choose an appropriate range of values for t t.

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