When we were first introduced to multiplication we saw that it was developed as a description for repeated addition.
4+4+4=3⋅4
4+4+4=3⋅4
Notice that there are three 4’s, that is, 4 appears 3 times. Hence, 3 times 4.
We know that algebra is generalized arithmetic. We can now make an important generalization.
When a number
a
a
is added repeatedly
n
n
times, we have
a+a+a+⋯+a
︸
a appears n times
a+a+a+⋯+a
︸
a appears n times
Then, using multiplication as a description for repeated addition, we can replace
a+a+a+⋯+a
︸
n times
with
na
a+a+a+⋯+a
︸
n times
with
na
For example:
x+x+x+x
x+x+x+x
can be written as
4x
4x
since
x
x
is repeatedly added 4 times.
x+x+x+x=4x
x+x+x+x=4x
r+r
r+r
can be written as
2r
2r
since
r
r
is repeatedly added 2 times.
r+r=2r
r+r=2r
The distributive property involves both multiplication and addition. Let’s rewrite
4(a+b).
4(a+b).
We proceed by reading
4(a+b)
4(a+b)
as a multiplication: 4 times the quantity
(a+b)
(a+b)
. This directs us to write
4(a+b)
=
(a+b)+(a+b)+(a+b)+(a+b)
=
a+b+a+b+a+b+a+b
4(a+b)
=
(a+b)+(a+b)+(a+b)+(a+b)
=
a+b+a+b+a+b+a+b
Now we use the commutative property of addition to collect all the
a's
a's
together and all the
b's
b's
together.
4(a+b)
=
a+a+a+a
︸
4a's
+
b+b+b+b
︸
4b's
4(a+b)
=
a+a+a+a
︸
4a's
+
b+b+b+b
︸
4b's
Now, using multiplication as a description for repeated addition, we have
4(a+b)
=
4a+4b
4(a+b)
=
4a+4b
We have distributed the 4 over the sum to both
a
a
and
b
b
.

a(b+c)=a⋅b+a⋅c
(b+c)
a=a⋅b+a⋅c
a(b+c)=a⋅b+a⋅c
(b+c)
a=a⋅b+a⋅c
The distributive property is useful when we cannot or do not wish to perform operations inside parentheses.
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