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  • GETSenPhaseMaths display tagshide tags

    This module is included inLens: Siyavula: Mathematics (Gr. 7-9)
    By: SiyavulaAs a part of collection: "Mathematics Grade 7"

    Collection Review Status: In Review

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Fractions - 09

Module by: Siyavula Uploaders. E-mail the author

MATHEMATICS

Common fractions

EDUCATOR SECTION

Memorandum

24.1 ( )

or

x

+

_

  • (i) = 7272 size 12{ { { size 8{7} } over { size 8{2} } } } {} x 307307 size 12{ { { size 8{"30"} } over { size 8{7} } } } {} - 10

= 2101421014 size 12{ { { size 8{"210"} } over { size 8{"14"} } } } {} - 10

= 15 – 10

s = 5

  1. (i) = 32 - 11 3434 size 12{ { { size 8{3} } over { size 8{4} } } } {}

v = 20 1414 size 12{ { { size 8{1} } over { size 8{4} } } } {}

  1. (i) = 234234 size 12{ { { size 8{"23"} } over { size 8{4} } } } {} x 4747 size 12{ { { size 8{4} } over { size 8{7} } } } {}

= 237237 size 12{ { { size 8{"23"} } over { size 8{7} } } } {}

p = 3 2727 size 12{ { { size 8{2} } over { size 8{7} } } } {}

26. a) Method: Cancel out

Answer: 1818 size 12{ { { size 8{1} } over { size 8{8} } } } {}

b) 125125 size 12{ { { size 8{1} } over { size 8{"25"} } } } {}

LEANER SECTION

Content

ACTIVITY: Mixed calculations [LO 1.10]

24. MIXED CALCULATIONS

24.1 Do you still remember?

  • Write down the order of operations below:

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24.2 Now apply this to the following:

(i) s=312×42723of15s=312×42723of15 size 12{s=3 { { size 8{1} } over { size 8{2} } } times 4 { { size 8{2} } over { size 8{7} } } - { { size 8{2} } over { size 8{3} } } `"of"`"15"} {}

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(ii) v=12of64712+414v=12of64712+414 size 12{v= { { size 8{1} } over { size 8{2} } } `"of"`"64" - left (7 { { size 8{1} } over { size 8{2} } } +4 { { size 8{1} } over { size 8{4} } } right )} {}

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(iii) p=534÷318134p=534÷318134 size 12{p=5 { { size 8{3} } over { size 8{4} } } div left (3 { { size 8{1} } over { size 8{8} } } - 1 { { size 8{3} } over { size 8{4} } } right )} {}

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25. Time for self-assessment

Figure 1
Figure 1 (graphics1.png)

26. BRAIN-TEASERS!

a) What is the answer of the following? Try and solve it without long calculations!

o = 1 1 2 × 1 1 3 × 1 1 4 × 1 1 5 × 1 1 6 × 1 1 7 × 1 1 8 o = 1 1 2 × 1 1 3 × 1 1 4 × 1 1 5 × 1 1 6 × 1 1 7 × 1 1 8 size 12{o= left (1 - { { size 8{1} } over { size 8{2} } } right ) times left (1 - { { size 8{1} } over { size 8{3} } } right ) times left (1 - { { size 8{1} } over { size 8{4} } } right ) times left (1 - { { size 8{1} } over { size 8{5} } } right ) times left (1 - { { size 8{1} } over { size 8{6} } } right ) times left (1 - { { size 8{1} } over { size 8{7} } } right ) times left (1 - { { size 8{1} } over { size 8{8} } } right )} {}

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b) If you continue with the pattern to. . . 11251125 size 12{ times left (1 - { { size 8{1} } over { size 8{"25"} } } right )} {}, what will the answer be then?

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Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.10: We know this when the learner uses a range of strategies to check solutions and judges the reasonableness of solutions.

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