Inside Collection (Course): Lectures on Analog Electronics
Summary: AE_Tutorial 12 gives the design problems on Audio & Radio Frequency Oscillators.
AE_Tutorial 12. Problems on OSCILLATORS
Problems have been taken from:
“Microelectronic Circuit Design” by R.C.Jaeger and T.N. Blalock, 2nd Edition, McGraw Hill,2006.
“Microelectronic Circuits- Analysis & Design”, Muhammad H. Rashid, Thomson, Indian Edition, 1999.
Problem (1)Wien Bridge Oscillator
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This is called Diode amplitude stabilization of a Wien Bridge Oscillator.
Determine frequency of oscillation & the amplitude of the oscillation.
[Ans:- 9.95 kHz,3.0V]
When the diodes are off,the gain of the amplifier is
So that loop gain >1 and the oscillations grow.
When diode turn ON, the gain is
PROBLEM(2)
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Design the Colpitt’s for oscillation frequency
Step(1) Choose
Step(2) Calculate L from
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Step(3) Calculate RF & RL.
Let RL=100kΩ Therefore RF=
Step(4) Determine R1______Let A=10
Step(5) Determmine gm
PROBLEM(3) Colpitts Oscillator Using BJT
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Calculate (i) Frequency of oscillation.
(ii)Check the Barkhausen criteria.
(iii)Determine R2.
Solution:-
RFC acts as a open circuit And CB and CE acts as a short circuit.
Therefore the Equivalent Circuit is :-
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From the nodal equations we get equating the imaginary parts
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Equating Real parts we get
For large values of
Gain
Subs
For
Sub (4) in (3)
(i)This
(ii)Frequency of oscillation=
(iii)
PROBLEM(4)LC-Tuned MOS Oscillator
Design an oscillator at
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For oscillation Loop Gain= 1∠0˚
Step(1) Choose a suitable value of C:
Let C=0.01μF
Step(2) Calculate the value of L from
Step(3) Find the value of R1 from Eq
Step(4)
PROBLEM(5)
Design a Hartley Oscillator at fo=5MHz.USE 2N3822 n-JFET whose parameters are
Load Resistance is RL=100Ω
The circuit is:-
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Practically it is implemented in the following manner:-
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The incremental circuit is given in Figure 10.
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Solution:-
BY analysis:-
We take
PROBLEM(6)CRYSTAL OSCILLATOR
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This is a Colpitts-derived op-amp crystal oscillator which uses crystal as an inductor.
This uses a 2 MHz crystal oscillator
Find the frequency of oscillator.
Given
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Equivalent Circuit of Crystal Oscillator:
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This can also be expressed as:
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Effective Capacitance Ceq is parallel with
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It is given that 2MHz crystal is used. Hence the result is self consistent.
This is the frequency of the Crystal Oscillator.