Boron compounds, BX3, are strong Lewis acids and as such form stable addition compounds with Lewis bases, in particular those with nitrogen donor ligands.
In principle these Lewis acid-base complexes should be similar to their isolobal hydrocarbon analogs, however, whereas the dipole in ethane is zero (by symmetry) the dipole in H3NBH3 is 5.2 D as a consequence of the difference in the Pauling electronegativities (i.e., B = 2.04 and N = 3.04). It is this dipole that generally differentiates the B-N compounds from their C-C analogs.
Homolytic cleavage of the C-C bond in ethane will yield two neutral methyl radicals, Equation 2. In contrast, heterolytic cleavage will result in the formation of two charged species, Equation 3. Thus, the products either have a net spin, Equation 2, or a net charge, Equation 3. By contrast, cleavage of the B-N bond in H3N-BH3 either yields products with both spin and charge, Equation 4, or neither, Equation 5. Heterolytic cleavage of the B-N bond yields neutral compounds, Equation 4, while hemolytic cleavage results in the formation of radical ions, Equation 5.
The difference in bond strength between H3N-BH3 and ethane is reflected in the difference in bond lengths (Table 1).
| Compound | Bond length (Å) | Bond strength (kcal/mol) |
| H3C-CH3 | 1.533 | 89 |
| H3N-BH3 | 1.658 | 31 |













