Recall from (Reference) that the convolution integral
y
(
t
)
=
∫
-
∞
∞
x
(
τ
)
h
(
t
-
τ
)
d
τ
y
(
t
)
=
∫
-
∞
∞
x
(
τ
)
h
(
t
-
τ
)
d
τ
(1)
has the Fourier Transform:
Y
(
j
Ω
)
=
H
(
j
Ω
)
X
(
j
Ω
)
Y
(
j
Ω
)
=
H
(
j
Ω
)
X
(
j
Ω
)
(2)
where H(jΩ)H(jΩ) and X(jΩ)X(jΩ) are the Fourier Transforms of h(t)h(t) and x(t)x(t), respectively. Solving for H(jΩ)H(jΩ) gives the frequency response:
H
(
j
Ω
)
=
Y
(
j
Ω
)
X
(
j
Ω
)
H
(
j
Ω
)
=
Y
(
j
Ω
)
X
(
j
Ω
)
(3)
The frequency response, the Fourier Transform of the impulse response of a filter, is useful since it gives a highly descriptive representation of the properties of the filter. The frequency response can be considered to be the gain of the filter, expressed as a function of frequency. The magnitude of the frequency response evaluated at Ω=Ω0Ω=Ω0, |H(jΩ0)||H(jΩ0)| gives the factor the frequency component of x(t)x(t) at Ω=Ω0Ω=Ω0 would be scaled by. The phase of the frequency response at Ω=Ω0Ω=Ω0, ∠H(jΩ0)∠H(jΩ0) gives the phase shift the component of x(t)x(t) at Ω=Ω0Ω=Ω0 would undergo. This idea will be discussed in greater detail in (Reference). A lowpass filter is a filter which only passes low frequencies, while attenuating or filtering out higher frequencies. A highpass filter would do just the opposite, it would filter out low frequencies and allow high frequencies to pass. Figure 1 shows examples of these various filter types.