The major analytes (referenced as TCE, pentane, and ethane) are very well separated from each other, allowing for quantitative analysis. The peak areas of the peaks associated with these compounds are integrated by the computer automatically, and are listed in (Table 3) with respect to time.
Table 3: Peak area of pentane, TCE as a function of reaction time.
| Time/min |
Peak area of pentane |
Peak area of TCE |
| 0 |
5992.93 |
13464 |
| 5.92 |
6118.5 |
11591 |
| 11.25 |
5941.2 |
8891 |
| 16.92 |
5873.5 |
7055.6 |
| 24.13 |
5808.6 |
5247.4 |
| 32.65 |
5805.3 |
3726.3 |
| 43.65 |
5949.8 |
2432.8 |
| 53.53 |
5567.5 |
1492.3 |
| 64.72 |
5725.6 |
990.2 |
| 77.38 |
5624.3 |
550 |
| 94.13 |
5432.5 |
225.7 |
| 105 |
5274.4 |
176.8 |
Normalize TCE concentration with respect to peak area of pentane and then to the initial TCE concentration, and then calculate the nature logarithm of this normalized concentration, as shown in Table 4.
Table 4: Normalized TCE concentration as a function of reaction time.
| Time (min) |
TCE/pentane |
TCE/pentane/TCEinitial
|
ln(TCE/Pentane/TCEinitial)
|
| 0 |
2.2466 |
1.0000 |
0.0000 |
| 5.92 |
1.8944 |
0.8432 |
-0.1705 |
| 11.25 |
1.4965 |
0.6661 |
-0.4063 |
| 16.92 |
1.2013 |
0.5347 |
-0.6261 |
| 24.13 |
0.9034 |
0.4021 |
-0.9110 |
| 32.65 |
0.6419 |
0.2857 |
-1.2528 |
| 43.65 |
0.4089 |
0.1820 |
-1.7038 |
| 53.53 |
0.2680 |
0.1193 |
-2.1261 |
| 64.72 |
0.1729 |
0.0770 |
-2.5642 |
| 77.38 |
0.0978 |
0.0435 |
-3.1344 |
| 94.13 |
0.0415 |
0.0185 |
-3.9904 |
| 105 |
0.0335 |
0.0149 |
-4.2050 |
From a plot normalized TCE concentration against time shows the concentration profile of TCE during reaction (Figure 1), while the slope of the logarithmic plot provides the reaction rate constant ((Reference)).
From Figure 1, we can see that the linearity, i.e., the goodness of the assumption of first order reaction, is very much satisfied throughout the reaction. Thus, the reaction kinetic model is validated. Furthermore, the reaction rate constant can be calculated from the slope of the fitted line, i.e., kmeas = 0.0414 min-1. From this the kcat can be obtained, Equation 4.