A photon is a quantum of EM radiation. Its energy is given by E=hfE=hf and is related to the frequency ff and wavelength λλ size 12{λ} {} of the radiation by
E=hf=hcλ(energy of a photon),E=hf=hcλ(energy of a photon), size 12{E = ital "hf"= { { ital "hc"} over {λ} } } {}
(1)where EE size 12{E} {} is the energy of a single photon and cc size 12{c} {} is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is
h= 4.14 × 10–15
eV ⋅ s.h= 4.14 × 10–15
eV ⋅ s. size 12{h =" 4" "." "14 " times " 10" rSup { size 8{"–15"} } " eV " cdot " s"} {}
(2)Since many wavelengths are stated in nanometers (nm), it is also useful to know that
hc= 1240 eV ⋅ nm.hc= 1240 eV ⋅ nm. size 12{ ital "hc" =" 1240 eV " cdot " nm"} {}
(3)These will make many calculations a little easier.
All EM radiation is composed of photons. Figure 1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and γγ size 12{γ} {} rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies.
Table 1: Representative Energies for Submicroscopic Effects (Order of Magnitude Only)
| Rotational energies of molecules |
10
−
5
10
−
5
size 12{"10" rSup { size 8{ - 5} } } {}
eV
|
| Vibrational energies of molecules |
0.1 eV |
| Energy between outer electron shells in atoms |
1 eV |
| Binding energy of a weakly bound molecule |
1 eV |
| Energy of red light |
2 eV |
| Binding energy of a tightly bound molecule |
10 eV |
| Energy to ionize atom or molecule |
10 to 1000 eV |
Photons act as individual quanta and interact with individual electrons, atoms, molecules, and so on. The energy a photon carries is, thus, crucial to the effects it has. Table 1 lists representative submicroscopic energies in eV. When we compare photon energies from the EM spectrum in Figure 1 with energies in the table, we can see how effects vary with the type of EM radiation.
Gamma rays, a form of nuclear and cosmic EM radiation, can have the highest frequencies and, hence, the highest photon energies in the EM spectrum. For example, a γγ size 12{γ} {}-ray photon with f= 1021
Hzf= 1021
Hz size 12{f"= 10" rSup { size 8{"21"} } " Hz"} {} has an energy E=hf=6.63× 10–13
J=4.14 MeV.E=hf=6.63× 10–13
J=4.14 MeV. size 12{E = ital "hf""= 6" "." "63 " times " 10" rSup { size 8{"–13"} } " J"=4 "." "14"`"MeV"} {} This is sufficient energy to ionize thousands of atoms and molecules, since only 10 to 1000 eV are needed per ionization. In fact, γγ size 12{γ} {} rays are one type of ionizing radiation, as are x rays and UV, because they produce ionization in materials that absorb them. Because so much ionization can be produced, a single γγ size 12{γ} {}-ray photon can cause significant damage to biological tissue, killing cells or damaging their ability to properly reproduce. When cell reproduction is disrupted, the result can be cancer, one of the known effects of exposure to ionizing radiation. Since cancer cells are rapidly reproducing, they are exceptionally sensitive to the disruption produced by ionizing radiation. This means that ionizing radiation has positive uses in cancer treatment as well as risks in producing cancer.
High photon energy also enables γγ size 12{γ} {} rays to penetrate materials, since a collision with a single atom or molecule is unlikely to absorb all the γγ size 12{γ} {} ray’s energy. This can make γγ size 12{γ} {} rays useful as a probe, and they are sometimes used in medical imaging. x rays, as you can see in Figure 1, overlap with the low-frequency end of the γγ size 12{γ} {} ray range. Since x rays have energies of keV and up, individual x-ray photons also can produce large amounts of ionization. At lower photon energies, x rays are not as penetrating as γγ size 12{γ} {} rays and are slightly less hazardous. X rays are ideal for medical imaging, their most common use, and a fact that was recognized immediately upon their discovery in 1895 by the German physicist W. C. Roentgen (1845–1923). (See Figure 2.) Within one year of their discovery, x rays (for a time called Roentgen rays) were used for medical diagnostics. Roentgen received the 1901 Nobel Prize for the discovery of x rays.
Once again, we find that conservation of energy allows us to consider the initial and final forms that energy takes, without having to make detailed calculations of the intermediate steps. Example 1 is solved by considering only the initial and final forms of energy.
While γγ size 12{γ} {} rays originate in nuclear decay, x rays are produced by the process shown in Figure 3. Electrons ejected by thermal agitation from a hot filament in a vacuum tube are accelerated through a high voltage, gaining kinetic energy from the electrical potential energy. When they strike the anode, the electrons convert their kinetic energy to a variety of forms, including thermal energy. But since an accelerated charge radiates EM waves, and since the electrons act individually, photons are also produced. Some of these x-ray photons obtain the kinetic energy of the electron. The accelerated electrons originate at the cathode, so such a tube is called a cathode ray tube (CRT), and various versions of them are found in older TV and computer screens as well as in x-ray machines.
Find the maximum energy in eV of an x-ray photon produced by electrons accelerated through a potential difference of 50.0 kV in a CRT like the one in Figure 3.
Strategy
Electrons can give all of their kinetic energy to a single photon when they strike the anode of a CRT. (This is something like the photoelectric effect in reverse.) The kinetic energy of the electron comes from electrical potential energy. Thus we can simply equate the maximum photon energy to the electrical potential energy—that is, hf=qV.hf=qV. (We do not have to calculate each step from beginning to end if we know that all of the starting energy qVqV is converted to the final form hf.hf.)
Solution
The maximum photon energy is hf=qVhf=qV size 12{ ital "hf"= ital "qV"} {}, where qq is the charge of the electron and VV is the accelerating voltage. Thus,
hf
=
(
1
.
60
×
10
–19
C
)
(
50.0
×
10
3
V
)
.
hf
=
(
1
.
60
×
10
–19
C
)
(
50.0
×
10
3
V
)
.
size 12{ ital "hf" = \( 1 "." "60 " times " 10" rSup { size 8{"-19"} } " C" \) \( "50" "." "0 " times " 10" rSup { size 8{3} } " V" \) } {}
(4)From the definition of the electron volt, we know 1 eV = 1.60 × 10–19 J1 eV = 1.60 × 10–19 J, where 1 J=1 C⋅V.1 J=1 C⋅V. size 12{1" J"=1`C cdot V} {} Gathering factors and converting energy to eV yields
hf
=
(
50.0
×
10
3
)
(
1.60
×
10
–19
C
⋅
V
)
(
1 eV
1.60
×
10
–19
C
⋅
V
)
=
(
50.0
×
10
3
)
(
1 eV
)
=
50.0 keV.
hf
=
(
50.0
×
10
3
)
(
1.60
×
10
–19
C
⋅
V
)
(
1 eV
1.60
×
10
–19
C
⋅
V
)
=
(
50.0
×
10
3
)
(
1 eV
)
=
50.0 keV.
(5)Discussion
This example produces a result that can be applied to many similar situations. If you accelerate a single elementary charge, like that of an electron, through a potential given in volts, then its energy in eV has the same numerical value. Thus a 50.0-kV potential generates 50.0 keV electrons, which in turn can produce photons with a maximum energy of 50 keV. Similarly, a 100-kV potential in an x-ray tube can generate up to 100-keV x-ray photons. Many x-ray tubes have adjustable voltages so that various energy x rays with differing energies, and therefore differing abilities to penetrate, can be generated.
Figure 4 shows the spectrum of x rays obtained from an x-ray tube. There are two distinct features to the spectrum. First, the smooth distribution results from electrons being decelerated in the anode material. A curve like this is obtained by detecting many photons, and it is apparent that the maximum energy is unlikely. This decelerating process produces radiation that is called bremsstrahlung (German for braking radiation). The second feature is the existence of sharp peaks in the spectrum; these are called characteristic x rays, since they are characteristic of the anode material. Characteristic x rays come from atomic excitations unique to a given type of anode material. They are akin to lines in atomic spectra, implying the energy levels of atoms are quantized. Phenomena such as discrete atomic spectra and characteristic x rays are explored further in Atomic Physics.
Ultraviolet radiation (approximately 4 eV to 300 eV) overlaps with the low end of the energy range of x rays, but UV is typically lower in energy. UV comes from the de-excitation of atoms that may be part of a hot solid or gas. These atoms can be given energy that they later release as UV by numerous processes, including electric discharge, nuclear explosion, thermal agitation, and exposure to x rays. A UV photon has sufficient energy to ionize atoms and molecules, which makes its effects different from those of visible light. UV thus has some of the same biological effects as γγ size 12{γ} {} rays and x rays. For example, it can cause skin cancer and is used as a sterilizer. The major difference is that several UV photons are required to disrupt cell reproduction or kill a bacterium, whereas single γγ size 12{γ} {}-ray and X-ray photons can do the same damage. But since UV does have the energy to alter molecules, it can do what visible light cannot. One of the beneficial aspects of UV is that it triggers the production of vitamin D in the skin, whereas visible light has insufficient energy per photon to alter the molecules that trigger this production. Infantile jaundice is treated by exposing the baby to UV (with eye protection), called phototherapy, the beneficial effects of which are thought to be related to its ability to help prevent the buildup of potentially toxic bilirubin in the blood.
Short-wavelength UV is sometimes called vacuum UV, because it is strongly absorbed by air and must be studied in a vacuum. Calculate the photon energy in eV for 100-nm vacuum UV, and estimate the number of molecules it could ionize or break apart.
Strategy
Using the equation E=hfE=hf size 12{E = ital "hf"} {} and appropriate constants, we can find the photon energy and compare it with energy information in Table 1.
Solution
The energy of a photon is given by
E=hf=hcλ.E=hf=hcλ. size 12{E = ital "hf" = { { ital "hc"} over {λ} } } {}
(6)Using hc= 1240 eV ⋅ nm,hc= 1240 eV ⋅ nm, size 12{ ital "hc" =" 1240 eV " cdot " nm"} {} we find that
E=hcλ=1240 eV ⋅ nm100 nm= 12.4 eV.E=hcλ=1240 eV ⋅ nm100 nm= 12.4 eV. size 12{E = { { ital "hc"} over {λ} } = { {"1240 eV " cdot " nm"} over {"100 nm"} } =" 12" "." "4 eV"} {}
(7)Discussion
According to Table 1, this photon energy might be able to ionize an atom or molecule, and it is about what is needed to break up a tightly bound molecule, since they are bound by approximately 10 eV. This photon energy could destroy about a dozen weakly bound molecules. Because of its high photon energy, UV disrupts atoms and molecules it interacts with. One good consequence is that all but the longest-wavelength UV is strongly absorbed and is easily blocked by sunglasses. In fact, most of the Sun’s UV is absorbed by a thin layer of ozone in the upper atmosphere, protecting sensitive organisms on Earth. Damage to our ozone layer by the addition of such chemicals as CFC’s has reduced this protection for us.
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