Why use a term like half-life rather than lifetime? The answer can be found by examining Figure 1, which shows how the number of radioactive nuclei in a sample decreases with time. The time in which half of the original number of nuclei decay is defined as the half-life, t1/2t1/2 size 12{t rSub { size 8{1/2} } } {}. Half of the remaining nuclei decay in the next half-life. Further, half of that amount decays in the following half-life. Therefore, the number of radioactive nuclei decreases from NN size 12{N} {} to N/2N/2 size 12{N/2} {} in one half-life, then to N/4N/4 size 12{N/4} {} in the next, and to N/8N/8 size 12{N/8} {} in the next, and so on. If NN size 12{N} {} is a large number, then many half-lives (not just two) pass before all of the nuclei decay. Nuclear decay is an example of a purely statistical process. A more precise definition of half-life is that each nucleus has a 50% chance of living for a time equal to one half-life t1/2t1/2 size 12{t rSub { size 8{1/2} } } {}. Thus, if NN size 12{N} {} is reasonably large, half of the original nuclei decay in a time of one half-life. If an individual nucleus makes it through that time, it still has a 50% chance of surviving through another half-life. Even if it happens to make it through hundreds of half-lives, it still has a 50% chance of surviving through one more. The probability of decay is the same no matter when you start counting. This is like random coin flipping. The chance of heads is 50%, no matter what has happened before.
There is a tremendous range in the half-lives of various nuclides, from as short as 10−2310−23 size 12{"10" rSup { size 8{ - "23"} } } {} s for the most unstable, to more than 10161016 size 12{"10" rSup { size 8{"16"} } } {} y for the least unstable, or about 46 orders of magnitude. Nuclides with the shortest half-lives are those for which the nuclear forces are least attractive, an indication of the extent to which the nuclear force can depend on the particular combination of neutrons and protons. The concept of half-life is applicable to other subatomic particles, as will be discussed in Particle Physics. It is also applicable to the decay of excited states in atoms and nuclei. The following equation gives the quantitative relationship between the original number of nuclei present at time zero (N0N0 size 12{N rSub { size 8{0} } } {}) and the number (NN size 12{N} {}) at a later time tt size 12{t} {}:
N=N0e−λt,N=N0e−λt, size 12{N=N rSub { size 8{0} } e rSup { size 8{ - λt} } } {}
(1)where e=2.71828...e=2.71828... size 12{e=2 "." "71828" "." "." "." } {} is the base of the natural logarithm, and λλ size 12{λ} {} is the decay constant for the nuclide. The shorter the half-life, the larger is the value of λλ size 12{λ} {}, and the faster the exponential e−λte−λt size 12{e rSup { size 8{ - λt} } } {} decreases with time. The relationship between the decay constant λλ size 12{λ} {} and the half-life t1/2t1/2 size 12{t rSub { size 8{1/2} } } {} is
λ=
ln(2)
t1/2
≈
0.693t1/2.λ=
ln(2)
t1/2
≈
0.693t1/2. size 12{λ= { {0 "." "693"} over {t rSub { size 8{1/2} } } } } {}
(2)To see how the number of nuclei declines to half its original value in one half-life, let t=t1/2t=t1/2 size 12{t=t rSub { size 8{1/2} } } {} in the exponential in the equation N=N0e−λtN=N0e−λt
. This gives N=N0
e−λt
=N0e−0.693
=0.500N0N=N0
e−λt
=N0e−0.693
=0.500N0. For integral numbers of half-lives, you can just divide the original number by 2 over and over again, rather than using the exponential relationship. For example, if ten half-lives have passed, we divide NN size 12{N} {} by 2 ten times. This reduces it to N/1024N/1024 size 12{ {N} slash {"1024"} } {}. For an arbitrary time, not just a multiple of the half-life, the exponential relationship must be used.
Radioactive dating is a clever use of naturally occurring radioactivity. Its most famous application is carbon-14 dating. Carbon-14 has a half-life of 5730 years and is produced in a nuclear reaction induced when solar neutrinos strike 14N14N size 12{"" lSup { size 8{"14"} } N} {} in the atmosphere. Radioactive carbon has the same chemistry as stable carbon, and so it mixes into the ecosphere, where it is consumed and becomes part of every living organism. Carbon-14 has an abundance of 1.3 parts per trillion of normal carbon. Thus, if you know the number of carbon nuclei in an object (perhaps determined by mass and Avogadro’s number), you multiply that number by 1.3×10−121.3×10−12 to find the number of
14C14C nuclei in the object. When an organism dies, carbon exchange with the environment ceases, and
14C14C is not replenished as it decays. By comparing the abundance of
14C14C in an artifact, such as mummy wrappings, with the normal abundance in living tissue, it is possible to determine the artifact’s age (or time since death). Carbon-14 dating can be used for biological tissues as old as 50 or 60 thousand years, but is most accurate for younger samples, since the abundance of
14C14C nuclei in them is greater. Very old biological materials contain no
14C14C at all. There are instances in which the date of an artifact can be determined by other means, such as historical knowledge or tree-ring counting. These cross-references have confirmed the validity of carbon-14 dating and permitted us to calibrate the technique as well. Carbon-14 dating revolutionized parts of archaeology and is of such importance that it earned the 1960 Nobel Prize in chemistry for its developer, the American chemist Willard Libby (1908–1980).
One of the most famous cases of carbon-14 dating involves the Shroud of Turin, a long piece of fabric purported to be the burial shroud of Jesus (see Figure 2). This relic was first displayed in Turin in 1354 and was denounced as a fraud at that time by a French bishop. Its remarkable negative imprint of an apparently crucified body resembles the then-accepted image of Jesus, and so the shroud was never disregarded completely and remained controversial over the centuries. Carbon-14 dating was not performed on the shroud until 1988, when the process had been refined to the point where only a small amount of material needed to be destroyed. Samples were tested at three independent laboratories, each being given four pieces of cloth, with only one unidentified piece from the shroud, to avoid prejudice. All three laboratories found samples of the shroud contain 92% of the 14C14C size 12{"" lSup { size 8{"14"} } C} {} found in living tissues, allowing the shroud to be dated (see Example 1).
Calculate the age of the Shroud of Turin given that the amount of 14C14C size 12{"" lSup { size 8{"14"} } C} {} found in it is 92% of that in living tissue.
Strategy
Knowing that 92% of the 14C14C remains means that N/N0=0.92N/N0=0.92 size 12{N/N rSub { size 8{0} } =0 "." "92"} {}. Therefore, the equation N=N0e−λtN=N0e−λt size 12{N=N rSub { size 8{0} } e rSup { size 8{ - λt} } } {} can be used to find λtλt size 12{λt} {}. We also know that the half-life of 14C14C is 5730 y, and so once λtλt size 12{λt} {} is known, we can use the equation λ=0.693t1/2λ=0.693t1/2 size 12{λ= { {0 "." "693"} over {t rSub { size 8{1/2} } } } } {} to find λλ size 12{λ} {} and then find tt size 12{t} {} as requested. Here, we postulate that the decrease in 14C14C is solely due to nuclear decay.
Solution
Solving the equation N=N0e−λtN=N0e−λt size 12{N=N rSub { size 8{0} } e rSup { size 8{ - λt} } } {} for N/N0N/N0 size 12{N/N rSub { size 8{0} } } {} gives
NN0=e−λt.NN0=e−λt. size 12{ { {N} over {N rSub { size 8{0} } } } =e rSup { size 8{-λt} } } {}
(3)Thus,
0.92=e−λt.0.92=e−λt. size 12{0 "." "92"=e rSup { size 8{ - λt} } } {}
(4)Taking the natural logarithm of both sides of the equation yields
ln0.92=–λtln0.92=–λt size 12{"ln "0 "." "92""=-"λt} {}
(5)so that
−0.0834=−λt.−0.0834=−λt. size 12{ - 0 "." "0834"= - λt} {}
(6)Rearranging to isolate tt size 12{t} {} gives
t=0.0834λ.t=0.0834λ. size 12{t= { {0 "." "0834"} over {λ} } } {}
(7)Now, the equation λ=0.693t1/2λ=0.693t1/2 size 12{λ= { {0 "." "693"} over {t rSub { size 8{1/2} } } } } {} can be used to find λλ size 12{λ} {} for 14C14C size 12{"" lSup { size 8{"14"} } C} {}. Solving for λλ size 12{λ} {} and substituting the known half-life gives
λ=0.693t1/2=0.6935730 y.λ=0.693t1/2=0.6935730 y. size 12{λ= { {0 "." "693"} over {t rSub { size 8{1/2} } } } = { {0 "." "693"} over {"5730"" y"} } } {}
(8)We enter this value into the previous equation to find tt size 12{t} {}:
t=0.08340.6935730 y=690 y.t=0.08340.6935730 y=690 y. size 12{t= { {0 "." "0834"} over { { {0 "." "693"} over {"5730"" y"} } } } ="690"" y"} {}
(9)
Discussion
This dates the material in the shroud to 1988–690 = a.d. 1300. Our calculation is only accurate to two digits, so that the year is rounded to 1300. The values obtained at the three independent laboratories gave a weighted average date of a.d. 1320±601320±60 size 12{"1320" +- "60"} {}. The uncertainty is typical of carbon-14 dating and is due to the small amount of 14C14C size 12{"" lSup { size 8{"14"} } C} {} in living tissues, the amount of material available, and experimental uncertainties (reduced by having three independent measurements). It is meaningful that the date of the shroud is consistent with the first record of its existence and inconsistent with the period in which Jesus lived.
There are other forms of radioactive dating. Rocks, for example, can sometimes be dated based on the decay of 238U238U. The decay series for 238U238U ends with 206Pb206Pb, so that the ratio of these nuclides in a rock is an indication of how long it has been since the rock solidified. The original composition of the rock, such as the absence of lead, must be known with some confidence. However, as with carbon-14 dating, the technique can be verified by a consistent body of knowledge. Since 238U238U has a half-life of 4.5×1094.5×109 y, it is useful for dating only very old materials, showing, for example, that the oldest rocks on Earth solidified about 3.5×1093.5×109 size 12{3 "." 5 times "10" rSup { size 8{9} } } {} years ago.
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