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The Yukawa Particle and the Heisenberg Uncertainty Principle Revisited

Module by: OpenStax College. E-mail the author

Summary:

  • Define Yukawa particle.
  • State the Heisenberg uncertainty principle.
  • Describe pion.
  • Estimate the mass of a pion.
  • Explain meson.

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Particle physics as we know it today began with the ideas of Hideki Yukawa in 1935. Physicists had long been concerned with how forces are transmitted, finding the concept of fields, such as electric and magnetic fields to be very useful. A field surrounds an object and carries the force exerted by the object through space. Yukawa was interested in the strong nuclear force in particular and found an ingenious way to explain its short range. His idea is a blend of particles, forces, relativity, and quantum mechanics that is applicable to all forces. Yukawa proposed that force is transmitted by the exchange of particles (called carrier particles). The field consists of these carrier particles.

Figure 1: The strong nuclear force is transmitted between a proton and neutron by the creation and exchange of a pion. The pion is created through a temporary violation of conservation of mass-energy and travels from the proton to the neutron and is recaptured. It is not directly observable and is called a virtual particle. Note that the proton and neutron change identity in the process. The range of the force is limited by the fact that the pion can only exist for the short time allowed by the Heisenberg uncertainty principle. Yukawa used the finite range of the strong nuclear force to estimate the mass of the pion; the shorter the range, the larger the mass of the carrier particle.
The image shows the creation a pion from a proton and its exchange to a neutron. After the exchange, the proton has become a neutron and the neutron has become a proton.

Specifically for the strong nuclear force, Yukawa proposed that a previously unknown particle, now called a pion, is exchanged between nucleons, transmitting the force between them. Figure 1 illustrates how a pion would carry a force between a proton and a neutron. The pion has mass and can only be created by violating the conservation of mass-energy. This is allowed by the Heisenberg uncertainty principle if it occurs for a sufficiently short period of time. As discussed in Probability: The Heisenberg Uncertainty Principle the Heisenberg uncertainty principle relates the uncertainties ΔEΔE size 12{ΔE} {} in energy and ΔtΔt size 12{Δt} {} in time by

ΔEΔth4π,ΔEΔth4π size 12{ΔEΔt >= { {h} over {4π} } } {},
(1)

where hh size 12{h} {} is Planck’s constant. Therefore, conservation of mass-energy can be violated by an amount ΔEΔE size 12{ΔE} {} for a time Δth4πΔE Δth4πΔE size 12{Δt approx { {h} over {4πΔE} } } {} in which time no process can detect the violation. This allows the temporary creation of a particle of mass mm size 12{m} {}, where ΔE=mc2ΔE=mc2 size 12{ΔE= ital "mc" rSup { size 8{2} } } {}. The larger the mass and the greater the ΔEΔE size 12{ΔE} {}, the shorter is the time it can exist. This means the range of the force is limited, because the particle can only travel a limited distance in a finite amount of time. In fact, the maximum distance is dcΔtdcΔt size 12{d approx cΔt} {}, where c is the speed of light. The pion must then be captured and, thus, cannot be directly observed because that would amount to a permanent violation of mass-energy conservation. Such particles (like the pion above) are called virtual particles, because they cannot be directly observed but their effects can be directly observed. Realizing all this, Yukawa used the information on the range of the strong nuclear force to estimate the mass of the pion, the particle that carries it. The steps of his reasoning are approximately retraced in the following worked example:

Example 1: Calculating the Mass of a Pion

Taking the range of the strong nuclear force to be about 1 fermi (1015m1015m size 12{"10" rSup { size 8{ - "15"} } m} {}), calculate the approximate mass of the pion carrying the force, assuming it moves at nearly the speed of light.

Strategy

The calculation is approximate because of the assumptions made about the range of the force and the speed of the pion, but also because a more accurate calculation would require the sophisticated mathematics of quantum mechanics. Here, we use the Heisenberg uncertainty principle in the simple form stated above, as developed in Probability: The Heisenberg Uncertainty Principle. First, we must calculate the time ΔtΔt size 12{Δt} {} that the pion exists, given that the distance it travels at nearly the speed of light is about 1 fermi. Then, the Heisenberg uncertainty principle can be solved for the energy ΔEΔE size 12{ΔE} {}, and from that the mass of the pion can be determined. We will use the units of MeV/c2MeV/c2 size 12{"MeV"/c rSup { size 8{2} } } {} for mass, which are convenient since we are often considering converting mass to energy and vice versa.

Solution

The distance the pion travels is dcΔtdcΔt size 12{d approx cΔt} {}, and so the time during which it exists is approximately

Δt d c = 10 15 m 3 . 0 × 10 8 m/s 3 . 3 × 10 24 s . Δt d c = 10 15 m 3 . 0 × 10 8 m/s 3 . 3 × 10 24 s . alignl { stack { size 12{Δt approx { {d} over {c} } = { {"10" rSup { size 8{ - "15"} } `m} over {3 "." 0 times "10" rSup { size 8{8} } `"m/s"} } } {} # " " approx 3 "." 3 times "10" rSup { size 8{ - "24"} } `s "." {} } } {}
(2)

Now, solving the Heisenberg uncertainty principle for ΔEΔE size 12{ΔE} {} gives

ΔEh4πΔt6.63×1034Js3.3×1024s.ΔEh4πΔt6.63×1034Js3.3×1024s size 12{ΔE approx { {h} over {4πΔt} } approx { {6 "." "63" times "10" rSup { size 8{ - "34"} } `J cdot s} over {4π left (3 "." 3 times "10" rSup { size 8{ - "24"} } `s right )} } } {}.
(3)

Solving this and converting the energy to MeV gives

ΔE1.6×1011J1MeV1.6×1013J=100MeV.ΔE1.6×1011J1MeV1.6×1013J=100MeV size 12{ΔE approx left (1 "." 6 times "10" rSup { size 8{ - "11"} } `J right ) { {1`"MeV"} over {1 "." 6 times "10" rSup { size 8{ - "13"} } `J} } ="100"`"MeV"} {}.
(4)

Mass is related to energy by ΔE=mc2ΔE=mc2 size 12{ΔE= ital "mc" rSup { size 8{2} } } {}, so that the mass of the pion is m=ΔE/c2m=ΔE/c2 size 12{m=ΔE/c rSup { size 8{2} } } {}, or

m100MeV/c2.m100MeV/c2 size 12{m approx "100"`"MeV/"c rSup { size 8{2} } } {}.
(5)

Discussion

This is about 200 times the mass of an electron and about one-tenth the mass of a nucleon. No such particles were known at the time Yukawa made his bold proposal.

Yukawa’s proposal of particle exchange as the method of force transfer is intriguing. But how can we verify his proposal if we cannot observe the virtual pion directly? If sufficient energy is in a nucleus, it would be possible to free the pion—that is, to create its mass from external energy input. This can be accomplished by collisions of energetic particles with nuclei, but energies greater than 100 MeV are required to conserve both energy and momentum. In 1947, pions were observed in cosmic-ray experiments, which were designed to supply a small flux of high-energy protons that may collide with nuclei. Soon afterward, accelerators of sufficient energy were creating pions in the laboratory under controlled conditions. Three pions were discovered, two with charge and one neutral, and given the symbols π+, π, and π0π+, π, and π0 size 12{π rSup { size 8{+{}} } ,`π rSup { size 8{ - {}} } ,`"and "`π rSup { size 8{0} } } {}, respectively. The masses of π+π+ size 12{π rSup { size 8{+{}} } } {} and ππ size 12{π rSup { size 8{ - {}} } } {} are identical at 139.6MeV/c2139.6MeV/c2 size 12{"139" "." 6`"MeV/"c rSup { size 8{2} } } {}, whereas π0π0 size 12{ π rSup { size 8{0} } } {} has a mass of 135.0MeV/c2135.0MeV/c2 size 12{"135" "." 0`"MeV/"c rSup { size 8{2} } } {}. These masses are close to the predicted value of 100MeV/c2100MeV/c2 size 12{"100"`"MeV/"c rSup { size 8{2} } } {} and, since they are intermediate between electron and nucleon masses, the particles are given the name meson (now an entire class of particles, as we shall see in Particles, Patterns, and Conservation Laws).

The pions, or ππ size 12{π} {}-mesons as they are also called, have masses close to those predicted and feel the strong nuclear force. Another previously unknown particle, now called the muon, was discovered during cosmic-ray experiments in 1936 (one of its discoverers, Seth Neddermeyer, also originated the idea of implosion for plutonium bombs). Since the mass of a muon is around 106MeV/c2106MeV/c2 size 12{"106"`"MeV/"c rSup { size 8{2} } } {}, at first it was thought to be the particle predicted by Yukawa. But it was soon realized that muons do not feel the strong nuclear force and could not be Yukawa’s particle. Their role was unknown, causing the respected physicist I. I. Rabi to comment, “Who ordered that?” This remains a valid question today. We have discovered hundreds of subatomic particles; the roles of some are only partially understood. But there are various patterns and relations to forces that have led to profound insights into nature’s secrets.

Summary

  • Yukawa’s idea of virtual particle exchange as the carrier of forces is crucial, with virtual particles being formed in temporary violation of the conservation of mass-energy as allowed by the Heisenberg uncertainty principle.

Problems & Exercises

Exercise 1

A virtual particle having an approximate mass of 1014GeV/c21014GeV/c2 size 12{"10" rSup { size 8{"14"} } `"GeV/"c rSup { size 8{2} } } {} may be associated with the unification of the strong and electroweak forces. For what length of time could this virtual particle exist (in temporary violation of the conservation of mass-energy as allowed by the Heisenberg uncertainty principle)?

Solution

3 × 10 39 s 3 × 10 39 s size 12{3 times "10" rSup { size 8{ - "39"} } `s} {}

Exercise 2

Calculate the mass in GeV/c2GeV/c2 size 12{"GeV/"c rSup { size 8{2} } } {} of a virtual carrier particle that has a range limited to 10301030 size 12{"10" rSup { size 8{ - "30"} } } {} m by the Heisenberg uncertainty principle. Such a particle might be involved in the unification of the strong and electroweak forces.

Exercise 3

Another component of the strong nuclear force is transmitted by the exchange of virtual K-mesons. Taking K-mesons to have an average mass of 495MeV/c2495MeV/c2 size 12{"495"`"MeV/"c rSup { size 8{2} } } {}, what is the approximate range of this component of the strong force?

Solution

1 . 99 × 10 16 m ( 0 . 2 fm ) 1 . 99 × 10 16 m ( 0 . 2 fm ) size 12{1 "." "99" times "10" rSup { size 8{ - "16"} } `m` \( 0 "." 2`"fm" \) } {}

Glossary

pion:
particle exchanged between nucleons, transmitting the force between them
virtual particles:
particles which cannot be directly observed but their effects can be directly observed
meson:
particle whose mass is intermediate between the electron and nucleon masses

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